Concave Mirrors and Convex Mirrors Ray Diagram - Equations / Formulas & Practice Problems
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- Опубліковано 6 сер 2016
- This physics video tutorial provides the ray diagrams for a concave and convex mirror. It also contains a few examples and practice problems along with the equations needed to solve it.
Law of Reflection - Geometric Optics: • Law of Reflection - Ge...
The Mirror Equation:
• Spherical Mirrors & Th...
Refraction of Light:
• Refraction of Light
Snell's Law & Index of Refraction:
• Snell's Law & Index of...
Total Internal Reflection & Critical Angle:
• Total Internal Reflect...
Thin Lens Equation:
• Thin Lens Equation, Op...
_____________________________
Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
_________________________________
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
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click ua-cam.com/video/Y_usiphPZ4o/v-deo.html to get the notes of geometrical optics
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click ua-cam.com/video/Y_usiphPZ4o/v-deo.html to get the notes of geometrical optics
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click ua-cam.com/video/Y_usiphPZ4o/v-deo.html to get the notes of geometrical optics
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One thing at 19:50, however ~~ di is -6 cm
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Guys, the Image is supposed to form beyond C at 13:50 !
Just correct that ☺️
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Hey great video but I noticed a mistake at 13:48. If you have an object placed between f and C, the reflected image will be located beyond C (as in di > 2f).
I checked my math with the sample of f=8cm, do = 12 cm, ho = 4 cm. In this situation, I found that C =16 cm and the calculated di = 24 cm so therefore di > C.
thanks. my ray diagram was showing this as well and I figured I wasn't wrong cause I was pretty careful with the lines.
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NOTES:
1/f = 1/do + 1/di
distance (do, di)
-positive if it is on the front of the mirror
-negatice if it is on the back of the mirror
focal length (f)
- positive for concave mirrors
- negative for convex mirrors
M = hi/ho = -di/do
- positive, upright image with respect to the object
- negative, inverted image with respect to the object
- |m| > 1; enlarged image
- 0 < |m| < 1; reduced image
- |m| = 1; same size
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18:30 He means convex mirror not concave
Yes
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The focal length of the concave mirror is negative
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This video is very helpful. I have a question though. For the object between c and f, why isn’t the image beyond c?
for the concave mirror example in the beginning was the focal length supposed to be negative? Also around 18:30 you said that the focal length for a convex mirror was negative, but I looked it up and it's positive.
i too
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22:47 hey! you said if di is (-ve) it will be a virtual image but - indicates real image I think it needs correction:)
the way he explain make sense and i like that im understanding. thanks
im on a roll, watching your videos and grabing as many info as i can,im a sucker for math. and i watched ur other videos and ive seen u making a simplier formula than what is on the book, and i have a feeling that you solve problems as you go along the video,, u solved the value of the height of the image mentally. i was wondering how u did that because i cant solve it myself not until i write it down and isolate the (Hi) on one side.... (dumb question but it might help me save sometime on my exam).. thank you in advance
No any tips for math , just practice makes perfect.
I've been always so confused with these mirror ray diagram but I guess I understand it now!
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The 2 incident rays:
Obj to mirror to focal ( not parallel to axis plane)
Obj to focal to mirror ( parallel to axis plane)
Special case (convexed lens) - obj to mirror refract to center whereby center distance to mirror is radius thus focal/focusing point distance to mirror is r/2
Actual converge/intersect is Real i
fake converge formed from actual divergence is Virtual image (so to say, diverge on front side && converge back side && image behind mirror)
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you stumbled around 18;30 i think and said concave mirror when you meant to say convex. good work though your my teacher behind closed doors :)
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thank you so much for this, but shouldn't the image be on the other side????
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19:00 you said it’s concave mirror but in your calculations you use covex mirror
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It's the other way around,the convex mirror that you present should be the concave mirror and the concave mirror is the convex mirror.
actually I was thinking the sam way
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Thank you so much for this explanation
Don't you think you have swapped the focal length signs for convex and concave, apparently the f for concave has to be negative and positive for convex. I stand to be corrected**
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Also, for any of my fellow studiers on MCAT Physics or AP Physics, and if anyone wants more practice/a comprehensive review of Concave vs Convex Lens and thin lens equation, I found this educational lesson helpful too: moosmosis.org/2019/09/27/concave-lens-vs-convex-lens-with-thin-lens-equation-ap-physics-and-mcat-physics/
(the gray commentary boxes reviews common misconceptions and easy pointers just like our awesome OP OC tutor)
good luck yall!