Can You Solve This Problem From 𝗝𝗘𝗘 𝗠𝗮𝗶𝗻 𝟮𝟬𝟮𝟰, 𝟮𝟵𝘁𝗵 𝗝𝗮𝗻 - 𝗦𝗵𝗶𝗳𝘁 𝟮
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- Опубліковано 31 січ 2024
- Can you Solve This Problem ? 𝗝𝗘𝗘 𝗠𝗮𝗶𝗻 𝟮𝟬𝟮𝟰 - 𝟮𝟵𝘁𝗵 𝗝𝗮𝗻 - 𝗦𝗵𝗶𝗳𝘁 𝟮
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Kya solution h 🥶🥵
My respect for aman malik sir 📈📈📈📈
Bhai ye common problem hai
Yeh amazing soln nhi hai
There are better methods
tum ek method bata do
@@pratyakshYT95.5
@@pratyakshYT95.5 btao better method...mujhe to ye wala mast laga
in my paper i figured out the solution x=45 y=1 by hit and trial as 45 square was nearest to 2023 but i was not sure that it was the only solution so i left the question , great analysis by you sir
Mene bhi same yahi hit Kia but 30 seconds me hi question skip karke aage badh gya tha
Mujhe toh yaad hi nhi aisa koi question tha paper mein? Meri bhi same shift thi
I think udhar x and y belongs to n nhi tha
Aur isliye ek aur possible case bnega -45 wala
question different tha kuch complex numbers se related tha jitna yaad hai
🛐🛐🛐🛐
What a mind blowing solution!
This channel is very underrated...
rhne bhi do 2026 tk ☠
Aman sir, aapne aise solutions le aate ho saamne ki dekh kr maza aa jaata hai, aap jaisa teacher maine shayad hi dekha hai
x=45, y=1 (by hit and trial).
Frrr same i did
NAH, IF it's mcq then only it can happen
@@aayushjawalekar4169 Why would it not work lmao it's literally an answer and if it's wrong then the question can't be right
MATHS IS NOT A SUBJECT IT IS FEELING
Ha bhai mera bhi favourite subject hai
❤❤
Yeah it is the best feeling in the world 🤤
My favourite subjects are maths and physics ❤❤❤❤
It's love bro
Sir , I have done it in a simpler way 😅
X² = 2^y + 2023
X² - 2^y = 2023
X² - 2^y = 2025 - 2
X² - 2^y = 45² -2¹
On comparing
X = 45 , y = 1
X+y = 45+1 = 46
Yes ,but you can't be sure if there are any other solutions
Matlab kuch bhi they are not complex no. 😂😂
@@AdarshShukla-le4gctoh usne complex number kaha use kiya?
Ye toh issliye kyuki you knew (45)² is 2025, othw it's just another guessing method
@@AdarshShukla-le4gc every real no. is complex no.
Take modulo 4 assuming y>1 since x^2=-1 not possible since squares are either 0 or 1 mod 4 now this implies y=0 or 1,so you get the answer
PS:This only works since x and y are naturals
I always love the solution when there is no loss of generality. Great solution sir.
Kya solution hai sir🔥🔥😯 ekdum bhannat🔥🔥
Mathematics is a language of God ❤😊
I solved this in my mind in 5 seconds, u see there is a trick for perfect squares of numbers with unit digit having 5 , so 5² =25, 15² = 1×2 ,25 = 225 (we are doing 1×2 since ten's place is occupied by 1 and then we multiplt it by successive number) , 25² = 2×3,25 =625 , 35² = 3×4,25=1225 , 45² = 4×5,25 = 2025 , there we go we got 2025 now in lhs , 2ⁿ + 2023 we need to find the value of the power of 2 to make it 2025 if u look carefully the power should be 1 to make it 2023+2=2025 , now x is 45 ,y is 1 therefore x+y= 46 simple and very easy no need to waste 6 minutes lol
us bhai us
Yes bro 😂😂😂same thinking.What a coincidence.Class 9th mind same
Us Bhai Us
Agar subjective me ata to?
@@Wanderer-dd4mj it will never come , there's no chapter which has these types of question in ncert. Ncert is either too childish , or too hard
Brilliant problem and a nice solution strategy
What a way of solving this, since I'm in my graduation but still I like to solve these JEE sums. Great explanation sir.
wow what a problem solving, so helpful to know the actual way to solve now i can use these ideas in other different situations too , thank you ! sir!
Sir I tried another method, if we make this equation like this: 2^y+2-2+2023 = x²
=>2(2^(y-1) - 1)+2025=x²
Now x will be:
=> √2(2^(y-1) - 1)+2025
So now as 2025 is a perfect square and its clearly visible that making y=1 will make the value 2(2^(y-1) - 1) =0 hence we can say x=45 and y=1
Thanks sir👍
Nicee
🤌✨✨❤
This solution only proves y=1 is a solution. It does not prove that y=1 is the only solution.
It's giving u single value for it; But not a complete proof!
Same ways I solved it😊.
this question don't demand any concept from any chapter of the syllabus just pure common sense, indeed a good question
It was a basic level olympiad question from prmo diophantine equation
@@thevibetree1 Seriously
Sir I want to conclude one thing that you are a person from different planet.❤
Maths ko dimag se nhi dil se padha jata h kyuki yeh feeling h❤
Wow sir super solution Olympiad ka flavour aa gya
Thank you Sir for this amazing question
Felt in love with maths again sir. Koti koti naman Aman sir❤
jo log IOQM ki thodi bhi taiyari kiye hey unke liye bahut hi jyada asaan tha
Pata nahi jee coaching Wale number theory kyon nahi padhate
Diophantine eqn. Right
@@prashant34049 star batches me number theory ke basics padhate h and geometry me RMO ke pyq and Pathfinder krwate..
@@prashant34049 mostly nobody teach
Bhai tune kiya kaise diophantine se
Kidhar kagaya modulo
Elsborate krega mera to aa hi nai rha
@@monujhembrom9279
What an analysis ... really fantastic.. Great Aman ji
This question is so amazing. Solving it with this method is even more amazing
This question also came in my mock test yesterday....
Thank you sir for an outstanding explanation ❤
Sir aap great ho kasam se itna accha explanation kisi ka nahi dekha hoga maine
Ye jitne bhi log tukka laga rahe hai.. Unke liye
615 + x²= 2^y. (x, y are non zero integers /can be both negative or positive) Find maximum value of x+y. Lagao isme tukka
ban gaya cool?
@@bruhyou197 mere se toh bana hi hua tabhi toh diya h 😅
@AkshunChauhan-bt6ey x, y = (59, 12) & (-59, 12) so maximum sum is 71, minimum sum is -47
Loved this approach sir😊😊
🤯🤯🤯🤯🤯 mind blowing sol.
This is why i tell to my freinds that you are the one who is giving me ideas.
Use both side log you can see directly
@@SKYLORD6905please provide solution using log
@@SKYLORD6905 Log 2023?
@@mukul9221 no use x²-2023 then take log then use log property tumhe kuch gadbad dikhheji kyuki ayega log(ײ-2025) ayega agr x=45 dal doge toh log define hi nhi hoga
This is also called solution by parity. Olympiads preparers would have found this extremely easy
Nice approach sir 😊
Gave JEE in 2011 but man what a solution to this beautiful question. Just randomly youtube recommended me your video
super solution sir great thought 🔥🔥🔥
sir acche se samjh aa gaya thank you so much
Maine 2023 ke sabse pass wala square dekha jo hota hai 2025 square of 45 toh isko x ki jgh rakha aur 2025-2023 kiya
Fir 2 bacha lhs me aur rhs me 2^y bacha equate krke y =1 aygya aur x = 45 phle se liya tha hence x+y = 46
Sir ye shi solution hai ?
Truly great teacher and very well explained
Yeh bahut aasan problem hai. Aur Aman sir ka soln koi bahut khatarnaaak nhi hai. Any IOQM student will nail it faster.
Sir simple agar ham mod 4 kare to we know that every perfect square is 0,1 mod 4 and if we claim that y>2 then 2^y would be 0 mod 4 and 2023 is 3 mod 4 which is not possible and hence y
Exactly, simple ioqm examples lol
which chapter is it from? number theory?
Normal Application of Number Theory in Math Olympiad(Divisibility Theory)
Great 👍🏻
What a solution sir,you are best, salute 🫡🫡 to you sir.
The very instant I saw 2023 and x², I rewrote it as 2025-2 because 2025 is 45², rearranged it as (x-45)(x+45) = 2(2^(y-1) -1). Rest is just deducing lhs and rhs as even or odd
Sir 45 ka square 2025 hota hai.
Agar hum x ki jagah 45 rakhe aur aur y ki jagah 1 tho dono barabar ho jaenge
Answer - 45+1 = 46
😅 Hit and trial se kiya
sir i get many learnings about maths by watching your videos ,thankyou so much
Mera shift
Ques me summation of all possible x and y puchatha. Thank you sir legendary soln...
29th shift 2 me tha yeh?
@@utkarshpandey01 yess
@@soumabhopal9901 kon sa question tha
Yaha par x, y € N tha ya R
Kyunki R mein toh ans 2 ho jayega
Great ❤❤❤
Ye to sabse basic question hai hit and trial se hogya
Really ye sachme aya tha mains me
Sidhe y=1 rakhoge to 2025 kiska square hai 45 ka x=45 hogya
Dono natural number hai khtm😂😂
Ha ye ese question hote h ki dekh ke phli bari me click kra toh ho gya
... Vrna exam pressure me Kbhi kbar soch ni pate
Are you actually that dumb
What jf more pairs of x and y could exist
Clearly you do not have the iq level to solve this in the exam room
Question had asked all the possible pairs of x and y
Everyone could only predict a single possibility of y=1 and x=45
What if there were more
You cant take risks
Matrix Wale ka kya tha ans ......
@@vanshgupta6454 tumhara shift konsa tha aur exactly kya question tha wo batao fir ans bata dunga Mera 27shift 2 tha
Haa isse ho jata hai aise competitive setting mein
But it doesn't hurt to know the full beauty of the question
Sir isko graph se bhi to kar skte hai
Best explanation sir...
What a great solution sir....
Sir easiest solution ye hoga ki y cannot be greater than 2 kyunki phir RHS (4k +3) ke form ka ho jayega jo kabhi bhi perfect squae ni ho skta so y=1 aur x =45
Sir if we use trial and error method we can easily find the answer, it is very easy question for the 7th and 8th class students who knows the concept of squares and square roots.
This solution was just amazing like mannnn❤
Bhai Saab, kya solution hai. Sahi hai!
Sir very good explaination. Really enjoyed it.
Great 👍 sir
Its a very very easy question, but maybe not in the exam!!!
X= 45 and Y = 1
Hit and trial...
Better for ioqm beginner question
but in student should you following approch
1) x,y both are natural numbers
2) find perfect squares near 2023 which is 2025 so y=1 and x=45.
Sir bahut aacha laga sir
sir mere paas ek short trick hai☺. Aap pehele powers ko compare karlo jisse aapko 2=y+1 mil jaega aur aap further directly 2 second me solve kar sakte ho☺
Masterpiece ❤
jala dala bhai 🔥🔥
Kya baat h sir salute h aapko
AMAZING EXPLANATION SIR 💗💗💗
Wonderful solution sir😊
🛐🛐🛐🛐🛐🛐❤❤❤❤❤ MIND blowing🎉🎉🎉
Superb solution Sir , wahh Sir wahh ❤👌🏻
Sir, Apne aisa samjhaya ki mai class 9th ka student isko samajh gaya.
First when i saw this qiestion i took the values of perfect square greater that 2023 which is 2025 =45²
i.e x=45 and y=1
As an ssc aspirant and maths lover , this is crazy
areee waah what a beautiful question dil jeet gaya
😮 Wow what a solution sir
Full respect to you sir
you are too... good
Physics is love ❤
But math me everything 🔥🔥
Mere shift may yeh question tha. Exactly iss form ka nahi tha lekin puch yehi Raha tha
Guruji tusi great ho
Fantastic analysis sir
Excelent
Can hit and try method also be a right method to solve this question
Sir, procedure kaise pata kare. I mean how to know from where and how to start to solve a question
sir yaha mene kya socha ki x2 jo hai jo vo ek odd number hai toa jo unit place hoga ex ka vaha odd number he ho sakte hai thn mene equation ko x2- 2023 = 2^y karke log base 2 leliya vaha se x2>2023 hona chahiye aisa aaya jisse ki ye patcha chal gaya ki xsquare ki value 45 hoyegi and vaha se y sidhe aagaya
love you bhai!
Thank you sir
This was a perfect art!❤
Thanks
It was easiest question ever for all my friends and me
Sir aapse question poochna ho toh kaha pooch skte h ?
Sir jee advance maths ke liye book suggest Karo please jaldi. Jisme mains ke questions na ho
I solved this thing mentally . x=45 , y=1
Just beautiful sir❤
Will there be multiple integer solution of x and y. Or it is the unique solution.
thanks sir
I am a commerce student but l love to watch this video
Pranam Charan sparsh peri pagdi apke pairo me
Kuchh v likhu Kam hai gr8 teacher
Sir bina expand kiya bina kuch solve kiya pata chal jata hai x odd hai because vo equal hai hai odd plus even
Such questions are rare in JEE more kind of math Olympiad question
Btw good reasoning by sir 👍 👌
Sir thank you so much for this solutions. Sir do you have any guidance regarding maths for class 9 students? How to practice such hard questions?
Chill kr be abhi ...11vi me ache se li jayegi sbki😂
Though I'm in 9th class, this question felt too easy. I just first tried to find square root of 2023 which was around 44 and after that we have to add a factor of 2 to make it a perfect square and square of 45 is 2025 which is 2023+2 so y = 1 and x = 45 and as it is given that y and x both are natural numbers so no ±45=x. Therefore, x+y = 45+1 =46
for real this was more of a logical one
First I want to answer before seeing solution if we put y=1 then rhs become 2025 which is sq of 45 so x=45 then
X+y= 46
It hit me when I was looking at squares ending with 25 which are generally of numbers ending with 5
Sir and others fellow students pls verify
Nice concept