jan 31 shift 1 question sin inverse alpha+sin inverse Beta+sin inverse gamma = pi.(alpha^2+beta^2+gamma^2)(alpha^2+beta^2-gamma^2).Find gamma? Sir please let me know answer. Thanks.
Sir, I remember the question being like +6| x-2 | and not -6|x-2| . I don't remember exactly. So if there are students who attempted on 30 jan S2 then please do reply if I am right or wrong......
Sir maine ek bahut bekar method try kiya usme bracket open kerke x ko each term mein multiply Kiya so degree of equation 3 ayi so ek cubic equation bna and we know the cubic equation ke three solutions hote hai sir yha pe galti kha ho rhi hai ??
Find the values of a, b, c and x, y, z with the value of ... (We let that...) k=x×b⁴-b³-b²+b-2(z×c+x×a)×b° Where we have an equality as, a×x+y+b×y-z+c×z = {b-[x×b⁴-b³-b²+b-2(z×c+x×a)×b°]}÷ (2×y) as well as we also have that, b²=a×c , y²=x×z , y²=b²/2 and.... 1). a, b, c belongs to natural numbers. as well as... 2). x, y, z also belongs to natural numbers. and... 3). k belongs to real numbers. Sir please answer and solve my question 🙏🙏 I am you're big fan ❤️
Sir mujhe to modulus wali equatiom se 6 solitions mil rhe hai by different cases and 1 solution h 0 toh total no. of solutions ho gye 7😢😢 aapka 3 graphical se aarha h aur mera 7 algebraic method seee... Am i wrong? Pls someone solve by algebraic method
@@Mechsisgic actually iss liye hua h bhai kyunki maine answers to nikal liye par case se verify nahi kiya.. answer aane ke baad case se check karna padta h , uske baad answer accept ya reject hota hai.. for eg. Case hai x >2 aur answer aagya root 3, to phir root 3 is less than 2, so it does not match (or verify) the case, i.e. root 32 so root 3 ko reject kardo.. ese karte karte finally 4 answrr got rejected and my answer became 3 solutions👍
e ki power - ln x ko 1upon e ki power lnx likh de aur e ki power lnx x ban jaayega aur tera question y=1/x ho jaayega aur uske baad 1/x kewal ek jagah discontinous hoga at x=0 aur usi point par defferntiable bhi nhi hoga Toh yaha se m=1 n=1 Toh m+n=2
Actually by solving it analytically I am getting 7 no of possible solutions by taking different cases and solving 3 different quadratic equations. How is this possible?? Kindly explain sir
My solutions are 0 (real) +root7 , -root 7( both real) and i have done b²-4ac on the remaing two quad equations, and thus cheked them Both are having real roots. (B²-4ac>0) Thus gaining 4 more real solutions Therefore 7 solutions total all real..
Bro Jo 7 solution aa rhe h wo alag alag cases leke aaenge aur agar solution case satisfy nhi kr rha to use count nhi krenge. Jaise maano tumne case liye x greater than 2, to fir Jo do solution aaye h wo check kro ki greater than 2 hai ki nhi , agar nhi hai to reject ho jaenge
Shift 2 question
All + sign in bracket
Answer = 1 solution
Ans toh 3 hai na?
Shift 2 question
Whi toh bhai me socha... Hain mujhe toh dikha hii nhi😂😂😂
I got scared that I left this question
@@whitedevil3993same
Such a beautiful explanation
U made my day sir❤
Sir plz dono approach btaya kariye i love maths
learnt to expand modulus from this question
Sir no. of solutions 1 hi hai
x=0 hi ek solution hai
Maine different case bana je solve kiya hai
Yes
@@hardikbatwal1889 3 hi hai minus root 7 , 1.28 and 0
@@rishipandya-q2s correct
graph pe command kasie kare, please!! ek video
Sir Can u please make a new playlist on making Graph of every Functions please
Gjb explanation 🔥
Gjb?
Ans hee galat nikal diya lekin explanation ka kya karna
jan 31 shift 1 question
sin inverse alpha+sin inverse Beta+sin inverse gamma = pi.(alpha^2+beta^2+gamma^2)(alpha^2+beta^2-gamma^2).Find gamma?
Sir please let me know answer.
Thanks.
Gamma = 1?
Gamma =√3/2 by observation
Pls write more clearly
Why is alpha²+beta²+gamma² there
@@69Gigantosaur we have to find gamma ? And apply it in inverstrigonometric equation.
Ans 7 a raha hai by solving equations by taking cases
Thanks sir iss question ka soln kahi bhi dhang sai nhi dai rakha tah apna aacha sai explain kiya haii
Sir, I remember the question being like +6| x-2 | and not -6|x-2| .
I don't remember exactly.
So if there are students who attempted on 30 jan S2 then please do reply if I am right or wrong......
Yes it was +
You are right
Yes my answer was coming 2 solutions
Sir maine ek bahut bekar method try kiya usme bracket open kerke x ko each term mein multiply Kiya so degree of equation 3 ayi so ek cubic equation bna and we know the cubic equation ke three solutions hote hai sir yha pe galti kha ho rhi hai ??
Find the values of a, b, c and x, y, z with the value of ...
(We let that...)
k=x×b⁴-b³-b²+b-2(z×c+x×a)×b°
Where we have an equality as,
a×x+y+b×y-z+c×z = {b-[x×b⁴-b³-b²+b-2(z×c+x×a)×b°]}÷ (2×y)
as well as we also have that,
b²=a×c , y²=x×z , y²=b²/2
and....
1). a, b, c belongs to natural numbers.
as well as...
2). x, y, z also belongs to natural numbers.
and...
3). k belongs to real numbers.
Sir please answer and solve my question 🙏🙏
I am you're big fan ❤️
Sir equation se dekhe toh( 0,1) ke beech mein bhi 2 cut point aa rahe hai
but the 2 cut point are not the soln as the case taken is for x between 0 and 1 and cut point are not in this range
Same
Sir answer me 1 diya hai maine bhi 3 mark Kara tha
Question wrong hai sir , last me +6|x - 2| hoga
Kya isme Descarte's rule lga skte hai ? If so how? Pls halp
Sir AOD ka pura video mil nahi raha hai😢😢😢😢😢😢😢😢😢😢😢
Question mein -6 nahi +6 hai sir and answer according to answer key is 1
Sir question alag tha minus nahi tha plus tha
haa aur x=0 sirf solution tha??
Ha bhai only 1 soln x=0
@@afridbasha7547 thanks bhai
@@afridbasha7547 bhai vo binomial wala question sahi tha kya?? 2-p,p,2-a,a jisme ye chaar term consecutive diye the (1+x)^n mai
Ye to mere paper mein nahi tha shift 1 ke meine miss to nahi kar diya?
30 January Shift 2 ka question hai..
Sir mujhe to modulus wali equatiom se 6 solitions mil rhe hai by different cases and 1 solution h 0 toh total no. of solutions ho gye 7😢😢 aapka 3 graphical se aarha h aur mera 7 algebraic method seee... Am i wrong? Pls someone solve by algebraic method
Same mere bhi
Mai khud soch raha hu ki aisa kyu huaa
@@Mechsisgic i figured it out
@@Mechsisgic actually iss liye hua h bhai kyunki maine answers to nikal liye par case se verify nahi kiya.. answer aane ke baad case se check karna padta h , uske baad answer accept ya reject hota hai.. for eg. Case hai x >2 aur answer aagya root 3, to phir root 3 is less than 2, so it does not match (or verify) the case, i.e. root 32 so root 3 ko reject kardo.. ese karte karte finally 4 answrr got rejected and my answer became 3 solutions👍
sirji mains ek quistion aaya tha jo aapke YT short pe dekha tha ❤
This question is not from morning shift.
Ig there was no negative sign there in this question😮
Yes
No wrong answer
Algebraic method se solution nahi aate kyonki inequality satisfy nahi hoti .only 1 soln
Tarun Khandelwal sir solved same question in our maths class and also there is +ve sign in 6।x-2।
So the ans will be only 1 soln 👍🏻
Bro ashish sir or tarun Khandelwal sir pls reply i am confused
@@pradeepkumarpatel5845 Tarun sir
@@prashantgupta43905 ok tum prayas 2.0 me ho kya
@@pradeepkumarpatel5845 No Arjuna JEE 2025😅
@@prashantgupta43905 OK bro
sir aapne question galat likha h
-√7, 0, (-6+√53)
exactly
Y=e^-|lnx| where m is those point where fn is not continues and n where fn is not derivable then find m+n? Shift 2 question 😊
e ki power - ln x ko 1upon e ki power lnx likh de aur e ki power lnx x ban jaayega aur tera question y=1/x ho jaayega aur uske baad 1/x kewal ek jagah discontinous hoga at x=0 aur usi point par defferntiable bhi nhi hoga
Toh yaha se
m=1
n=1
Toh m+n=2
Samaj aaya bro
m = 0 n = 1 m+n= 1
@@sahilgupta546bhai x= 0 to domain mein hi nhi hai isiliye wahan discontinous nahi hoga
@@chetananand1167Bhai domain mein isliye he to nhi Hain kyuki wahan pe function spike karta hai(discontinuous hai).
Sir graphical method har no of zeros wale sawalo me kaam aata h kya
Matlab graphical method dhoka toh nhi dega😅
Sir question mei negative sign nhi tha jha 6 likha h
haa aur x=0 sirf solution tha right??
@@nerdy6600 Bhai 2 solutions aae the mere
@@ABCX223 bhai toh mereko ye bata agar vo coefficient positive, toh overall term positive hogaya na??
@@ABCX223 x²+|x|+5|x-1|+6|x-2|
x²≥0,|x|≥0,|x-1|≥0,|x-2|≥0
and the expression to be zero they all should be zero simultaneously which is not possible
@@nerdy6600 ha Bhai mere se silly mistake ho gyi lgta h
Sir graph ?
Sir only one solution answer aa rha h
Sir graph hee toh nhi banta 😢
Thankyou sir
Sir AJ ka 31 shift 1 me ek khatarnak limit aya tha uski video krona😢
120/π^3 integration 0se π x^2sinx cosx/sin^4x+cos^4x ki value 😮
We can directly solve it. If we put y=1 then the RHS becomes whole square of 45
So x=45,y=1
X+y=46
From Bangladesh ❤
Actually by solving it analytically I am getting 7 no of possible solutions by taking different cases and solving 3 different quadratic equations.
How is this possible??
Kindly explain sir
I am also getting 7 solutions total after making casess
Maybe you are getting 4 solutions as complex solutions .And the question is asking for real solutions .
Thank you
@@bhaveshsinghbisht yeah maybe... let me check
My solutions are
0 (real)
+root7 , -root 7( both real) and i have done b²-4ac on the remaing two quad equations, and thus cheked them Both are having real roots. (B²-4ac>0)
Thus gaining 4 more real solutions
Therefore 7 solutions total all real..
Bro Jo 7 solution aa rhe h wo alag alag cases leke aaenge aur agar solution case satisfy nhi kr rha to use count nhi krenge.
Jaise maano tumne case liye x greater than 2, to fir Jo do solution aaye h wo check kro ki greater than 2 hai ki nhi , agar nhi hai to reject ho jaenge
Sir 3.00 likha hu shi h?
Acha ese bna skte h graph 😮
I am getting 5 solutions and all are real ???
Sir shift one me aesa koi que hi nahi tha
SIR ITS HUMBLE REQUEST PLZ CHALLENGE THIS QUESTION
IN 30 JAN SHIFT 2 INTEGER TYPE QUES OF MATHS
GIVEN ANS BY NTA = 1
YOUR AND OURS ANS = 3
🙏🙏🙏🙏🙏🙏
Shift 1 me nahi tha ye
Mere paper me to nhi aaya🤔
Second shift m tha
tyagi bro>>>>>>
bhannu bhai roxx
Bilkul aasan
Ye kab shift 1 mein tha yr 😂😂
Maine to nhi dekha
Ye shift 1 mein Nhi tha
2nd m tha
Mere toh algebraic process me 4 real solutions ayee😅
Mera bhi dekte hi solve ho gaya tha
I'm in class 10th Maharashtra board, and I solved this problem very easily 😅 that was so easy yaar! Pata nhi kis baat ka jee mains hai ye
Bro koi problem nahi jab paper doge to Pata chal jayega
Bhai kaisa gya paper...
Kitna expect kr rahe ho 😅
Mai bhi MH BOARD se hu
And tumne JEE preparation start ki ya nhi??
Aur agr haa, to kha join kiya?
@@prashantgupta43905 expecting around 88-90% bro and preparation start karne wala hu abhi because mein planning kar Raha hu abhi
Chutiyapanti band kar me bhi Maharashtra board me hu .Humko modulus sikhaya hi nhi he 😂
easy question tha 30 second me hogaya
Cases bnake
aisa koi sawaal nhi deka hamne
😢 nai aaya
Blunder by NTA again ,unhone eska answer 1 diya h 😂
Op sir
NTA mei bhi shayad reservation vale teacher hai😂😂😂
Sir answer 1 aata hai iska😂😂😂😂
@@CHIRAG_4063 bhai meri hee shift mei tha answer 1 diya tha maths mei 100 percentile hai mera 1 hee answer kiya tha maine
❤❤❤❤❤
op bhannu
physics galaxy better
mc
First coment
Wrong answer
wrong solution , waste of time
Bina pen uthaye class mei 5 second mei ans bataya tha lagbhag sabme mere class mei💀
Sir Can u please make a new playlist on making Graph of every Functions please
120/π^3 integration 0se π x^2sinx cosx/sin^4x+cos^4x ki value 😮
0 hoga i think
Bilkul aasan