Hi Chantel! I am so glad that this channel has helped you pass your Physics class - that's amazing news! Good luck in your future studies - and if you're taking another class in Physics, Chemistry, or Math, we may be able to help you in those classes as well. Also, a huge THANK YOU for your support in us and in the channel. The channel would not be where it is without your support - you are greatly appreciated! 😀
Thank you for your kind words, Antonio! I am so glad that these videos are helping you with Physics practice. Keep up the great work and thank you for being a part of this community! 😀
To start, I appreciate you going through these problems. I wanted to mention, however, that I think this problem was done incorrectly. When I followed your math, my answer was wrong according to my homework. I think the formula to use should be initial KE + initial PE + Work from non-conservative forces = final KE + final PE. Giving 1/2m*initial velocity squared+ 0 + (-force from kinetic friction*d) = 1/2m*final velocity squared + mg*final height. This yields the correct answer according to my homework.
Been watching your channel for my physics class and recently got a 96% on our first exam, the highest in the class! Thank you for helping me understand the why behind each problem!
WOAH! This is absolutely incredible! I am so glad that you found this channel. I am so proud of you - congratulations! Hard work never goes unnoticed. Keep up the great work and thank you for being a part of this community! 😀
F_f is 180 before the 35 degree rotation. The skier is traveling in the 35 degree direction so the F_f is pointing in the 35+180 degree direction or 215 degrees down the slope.
You're welcome! I am so glad that you found this channel and that it has helped you with your Physics homework. Keep up the great work and thank you so much for being a part of this community! 😀
This is AMAZING, Oleander! I am so glad that these videos are helping you in your Physics class. Keep up the awesome work and help us spread the word! Also, a huge THANK YOU for your support in us and in the channel. The channel would not be where it is without your support - you are greatly appreciated! 😀
You're welcome, Steven! I am so glad that these videos are helping you in your Physics class. Keep up the great work and thank you for being a part of this community! 😀
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step): Step 1: (12^2)/2 = 72 Step 2: ANSWER - 9.8 x 2.5 = 47.5 Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991 Step 4: ANS/(a/2) = 89.40165981 Step 5: sqrt(ANSWER) = 9.455245095 Rounded to 3 sig figs is 9.46! Hopefully this helps!
My professor said this section was supposed to be easier than the previous section with kinematic equations. I feel like he was lying because this homework question was ridiculous. Again, I appreciate your explanation of this question and the breakdown. Hopefully this isn’t on my upcoming exam because if it is, I’m in trouble.
I am in a similar situation. My professor rushed this section, hardly touching on it. When I looked at the homework, I had no idea where to even start. This problem feels like something that should be at the end of the semester. The text is hopeless as it goes into excessive detail, but fails to summarize the key takeaways. This is a major flaw in almost every textbook I have ever worked with. They need to explain a unit in detail, then at the end of the unit with a summary and important "takeaways". It would help me prioritize what I really need to concentrate on, and what is a "good to know" but not essential.
Hi Aaron! This Physics problem was brutal but getting to the end is just that much better. Good luck on your upcoming exam and thank you so much for being a subscriber to the channel! Your support means a lot to us and the channel would not be where it is without your help. Thank you! 😀
Remember - the unit for work is Joule and therefore an energy. The “work” done by gravity is taken into account by the change in Potential Energy due to gravity. Essentially, work done by gravity is the change in Potential Energy due to gravity. Hopefully this helped!
Hi Jose! Great question - the cos of 180 is only a little sliver of the entire square root. Once all calculations are performed under the radical, the resulting value is still positive. Hopefully this helps! 😀
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step): Step 1: (12^2)/2 = 72 Step 2: ANSWER - 9.8 x 2.5 = 47.5 Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991 Step 4: ANS/(a/2) = 89.40165981 Step 5: sqrt(ANSWER) = 9.455245095 Rounded to 3 sig figs is 9.46! Hopefully this helps! Also, a huge THANK YOU for your support in us and in the channel! The channel would not be where it is today without your help - thank you so very much. You are greatly appreciated!
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step): Step 1: (12^2)/2 = 72 Step 2: ANSWER - 9.8 x 2.5 = 47.5 Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991 Step 4: ANS/(a/2) = 89.40165981 Step 5: sqrt(ANSWER) = 9.455245095 Rounded to 3 sig figs is 9.46! Hopefully this helps!
I did tell a friend btw, as suggested. You should have your own channel. You're the best I've seen at this stuff. Great instructional video. Ive seen many (of this guys videos through openstax). I would love to get the teachers name in this video.
I just wanted to say you single handedly saved me from failing my physics class. Thank you!
Hi Chantel! I am so glad that this channel has helped you pass your Physics class - that's amazing news! Good luck in your future studies - and if you're taking another class in Physics, Chemistry, or Math, we may be able to help you in those classes as well. Also, a huge THANK YOU for your support in us and in the channel. The channel would not be where it is without your support - you are greatly appreciated! 😀
I have been watching your channel for practice for my physics classes and wow! 10/10 to you sir, thank you for making these.
Thank you for your kind words, Antonio! I am so glad that these videos are helping you with Physics practice. Keep up the great work and thank you for being a part of this community! 😀
To start, I appreciate you going through these problems. I wanted to mention, however, that I think this problem was done incorrectly. When I followed your math, my answer was wrong according to my homework. I think the formula to use should be initial KE + initial PE + Work from non-conservative forces = final KE + final PE. Giving 1/2m*initial velocity squared+ 0 + (-force from kinetic friction*d) = 1/2m*final velocity squared + mg*final height. This yields the correct answer according to my homework.
That's what I concluded too. His answer is incorrect
This is one of my favorite physics problems, I just love how everything falls into place at the end. Keep up the good job
Thanks, James! Keep working hard and thank you for being a part of this community! 😀
Wow! This is great! You explained this so well.
You're very welcome! Glad these help - keep studying hard!
I LOVE THS CHANNEL. THANK YOU SO MUCH, I FEEL LIKE IM LEARNING NOW!!!
You're welcome, James! I'm glad these are super helpful for you! 😀
Been watching your channel for my physics class and recently got a 96% on our first exam, the highest in the class! Thank you for helping me understand the why behind each problem!
WOAH! This is absolutely incredible! I am so glad that you found this channel. I am so proud of you - congratulations! Hard work never goes unnoticed. Keep up the great work and thank you for being a part of this community! 😀
F_f is 180 before the 35 degree rotation. The skier is traveling in the 35 degree direction so the F_f is pointing in the 35+180 degree direction or 215 degrees down the slope.
I never knew Ray Romano was such an excellent physics teacher
😂 Me neither!
You have saved my homework grade once again. Thank You, very good explanation and patience.
You're welcome! I am so glad that you found this channel and that it has helped you with your Physics homework. Keep up the great work and thank you so much for being a part of this community! 😀
Thank God for you. I would have 100% bombed physics without you and, so far, I have an A thanks to you!
This is AMAZING, Oleander! I am so glad that these videos are helping you in your Physics class. Keep up the awesome work and help us spread the word! Also, a huge THANK YOU for your support in us and in the channel. The channel would not be where it is without your support - you are greatly appreciated! 😀
Where did 9.46, I got 6.24m/s and the book also gives 6.24 as the answer????
Nice video. Very useful. Thanks teacher
You got it, Benjamin! I am so glad that this video has helped you in your Physics class. Keep working hard and help us spread the word! 😀
the best physics teacher but this one got me I give up
Thank you for your kind words, Gio! Some Physics problems are going to be brutal but stick it out until the end - the reward is that much greater! 😀
Yup got about 1/2 way and gave up, I'll just get this one wrong on my test tomorrow :)
Good luck on our exam! I believe in you! 😀
Thank you so much, I love your videos!
You're welcome, Steven! I am so glad that these videos are helping you in your Physics class. Keep up the great work and thank you for being a part of this community! 😀
I keep getting 4.7 when I crunch the numbers in on the last equation
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step):
Step 1: (12^2)/2 = 72
Step 2: ANSWER - 9.8 x 2.5 = 47.5
Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991
Step 4: ANS/(a/2) = 89.40165981
Step 5: sqrt(ANSWER) = 9.455245095
Rounded to 3 sig figs is 9.46!
Hopefully this helps!
@@GlaserTutoring What does (a/2) stand for in step 4???
Could you film chapter 24 numbers 6, 8, 9, 13 and 16? Please and thank you!
Hi Minni! These videos are up on the channel now so go check them out! Good luck in your studies!
My professor said this section was supposed to be easier than the previous section with kinematic equations. I feel like he was lying because this homework question was ridiculous.
Again, I appreciate your explanation of this question and the breakdown. Hopefully this isn’t on my upcoming exam because if it is, I’m in trouble.
I am in a similar situation. My professor rushed this section, hardly touching on it. When I looked at the homework, I had no idea where to even start. This problem feels like something that should be at the end of the semester. The text is hopeless as it goes into excessive detail, but fails to summarize the key takeaways. This is a major flaw in almost every textbook I have ever worked with. They need to explain a unit in detail, then at the end of the unit with a summary and important "takeaways".
It would help me prioritize what I really need to concentrate on, and what is a "good to know" but not essential.
Hi Aaron! This Physics problem was brutal but getting to the end is just that much better. Good luck on your upcoming exam and thank you so much for being a subscriber to the channel! Your support means a lot to us and the channel would not be where it is without your help. Thank you! 😀
why dont you also include work done by gravity
Remember - the unit for work is Joule and therefore an energy. The “work” done by gravity is taken into account by the change in Potential Energy due to gravity. Essentially, work done by gravity is the change in Potential Energy due to gravity. Hopefully this helped!
If this problem's on my test I'll just go ahead and log out.
Don't give up, Maanav! Some Physics problems are going to be brutal but stick it out until the end - the reward is that much greater! 😀
How do you square root this answer if the cos of 180 is -1!!!!!!!!!!!
Hi Jose! Great question - the cos of 180 is only a little sliver of the entire square root. Once all calculations are performed under the radical, the resulting value is still positive. Hopefully this helps! 😀
where did 9.46 come from kept getting 6.47
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step):
Step 1: (12^2)/2 = 72
Step 2: ANSWER - 9.8 x 2.5 = 47.5
Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991
Step 4: ANS/(a/2) = 89.40165981
Step 5: sqrt(ANSWER) = 9.455245095
Rounded to 3 sig figs is 9.46!
Hopefully this helps!
Also, a huge THANK YOU for your support in us and in the channel! The channel would not be where it is today without your help - thank you so very much. You are greatly appreciated!
Wow :0
Glad this video has helped you!
I cant get 9.46 tho.
I solved it my way and got 9.38965
I solved it your way and got 9.30896
I directly input your final solution and got 9.30896
Hi there! I just redid the calculation in my calculator and then answer still stands. I can try my best to write down what I inputed into my calculator with the appropriate steps (The Term ANSWER is the answer to the previous step):
Step 1: (12^2)/2 = 72
Step 2: ANSWER - 9.8 x 2.5 = 47.5
Step 3: ANS + 0.08 x 9.8 x cos(35) x (2.5/sin(35)) x cos (180) = 44.7082991
Step 4: ANS/(a/2) = 89.40165981
Step 5: sqrt(ANSWER) = 9.455245095
Rounded to 3 sig figs is 9.46!
Hopefully this helps!
great explanation, but omg i hate physics.....
Thanks, Laura! Hopefully these videos help your aversion to Physics a little! 😂
I did tell a friend btw, as suggested. You should have your own channel. You're the best I've seen at this stuff. Great instructional video. Ive seen many (of this guys videos through openstax). I would love to get the teachers name in this video.
Oh, is this really Ray Ramano?