7.13 | A car’s bumper is designed to withstand a 4.0-km/h (1.1-m/s) collision with an immovable
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- Опубліковано 12 вер 2024
- A car’s bumper is designed to withstand a 4.0-km/h (1.1-m/s) collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance. Calculate the magnitude of the average force on a bumper that collapses 0.200 m while bringing a 900-kg car to rest from an initial speed of 1.1 m/s.
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Hey y'all - taking into account significant figures, the final answer should be 2.7 x 10^3 N. Hope everyone is having a good semester. Cheers!
I solved it in two steps
1. Calculate the KE=mv^2/2
2. Calculate Wnet=Fnet * d
Fnet=KE/d
Thank you so much for helping us understand physics better.
Thanks the beauty of Physics - there are many ways to solve a problem! Keep up the great work! 😀
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Ya same thing for me.. thank you so much for your efforts
You're welcome! Keep up the great work! 😀
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thank you
You're welcome, Zach! I am so glad that these videos are helping you in your Physics class. Thank you for being a part of this community! 😀
I think I see the problem you don't have to assume the initial size of the bumper in order to subtract and find the change because the change in the bumper is actually given in this problem and not the initial or final size of the bumper
Awesome job, Reese! This is exactly correct. Keep up the hard work!
Couldn't you use equation W = F(change in x) once you found W?
change in x being 0.200 m
You could have, Jake! I like to work with sign values of numbers (-0.200) instead of 0.200 because it gives more context (adds direction) to the calculation. Use whichever one you feel more comfortable with. Keep studying hard!
At 9:17 you say to assume that the bumper is 0.5 m in length before the collision with the wall. Where do you get this assumption from? I don't have this assumption as part of my question?
It's only an example of the size change, wich is 0.2m.
sir but the not only the car is moving, also bumper is moving, the bumper is attached to car so they kinda like same system. please explain.
At 4:58
ΔKE = 1/2mΔv^2 is incorrect.
Δv^2 is not the same as [vf^2 - vi^2].
Squared difference of velocities is not the same as difference of squared velocities.
for algorithm pt 2
Thank you for your support once again, Zach! 😀
for algorithm
Thank you for your support, Zach! 😀
sir but the not only the car is moving, also bumper is moving, the bumper is attached to car so they kinda like same system. please explain.