How to optimize trains for better transfer per min in satisfactory

Skip to a subject:
Explanations 3:06
How to find your min and max interval range 9:43
Setting up the rail system 14:32
- Having the right amount of trains 17:57
- Making adjustments to the interval 19:01
- Rail systems with intersections 21:04
Note on dealing with bad framerate 25:02
32 stacks per freight car
locks 28sec per trip, 0.467 metric min (I made that up, it's not a term that exists)
max belt is 1560
stacks of 50, 1 train every 1.367 mmin (1m22): 1170
stacks of 100, 1 train every 2.254 mmin (2m15): 1418
stacks of 200, 1 train every 4.212 mmin (4m13): 1519
stacks of 500, 1 train every 10.3 mmin (10m18): 1553
This is the equation for stacks of 100:
x = mmin
3200 /x = max train
(1560x² -728) /x² = max belt
How to solve to get optimal:
3200 /x = (1560x² -728) /x²
0 = 1560x² -3200x -728
0 = (40x +8.282)(39x -87.9)
87.9 = 39x
2.254 = x
Your minimum and maximum time range:
x = train interval in metric min (multiply by 60 to get the time in real seconds)
y = the amount you need per minute
maximum: 3200 /y = x
minimum: ²√ (728 /(1560 -y)) = x

[@donwald3436]

has this game even released yet lol.

[@RicardoVermeltfoort]

still early access
but 1.0 has been confirmed to release this year