Friction

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  • Опубліковано 20 сер 2024
  • Friction force explained in a simple and practical way!
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    Friction is a force that opposes the relative motion or tendency of such motion of two surfaces in contact. It acts parallel to the surfaces and is caused by the irregularities present on the surfaces in contact.
    There are three main types of friction: static friction, sliding (kinetic) friction, and rolling friction.
    1. Static Friction is the force that opposes the initiation of motion between two surfaces that are in contact and at rest relative to each other.
    Static friction prevents the object from moving even when a force is applied. It adjusts itself to be equal and opposite to the applied force until the force reaches a critical value, known as the limiting friction. Once this critical value is exceeded, the object starts moving.
    2. Sliding or Kinetic Friction: Sliding friction, also known as kinetic friction, is the force that opposes the motion of two surfaces sliding past each other. Once an object overcomes static friction and starts moving, sliding friction comes into play. It is generally weaker than static friction and remains relatively constant as long as the surfaces continue to slide past each other.
    3. Rolling Friction: Rolling friction is the force that resists the motion of a rolling object, such as a wheel or a ball, on a surface. Rolling friction is generally lower than sliding friction, making it easier for objects to roll than to slide. It occurs because the object deforms slightly at the point of contact with the surface, and this deformation creates resistance.
    In summary, static friction prevents the initiation of motion, sliding friction opposes the motion of sliding surfaces, and rolling friction hinders the motion of a rolling object. Understanding these types of friction is crucial in various fields, from physics and engineering to everyday scenarios where friction plays a role in the movement of objects.
    At Manocha Academy, learning Science and Math is Easy! The school coursework is explained with simple examples that you experience every day! Yes, Science & Math is all around you! Let's learn every day from everyday life!

КОМЕНТАРІ • 156

  • @ManochaAcademy
    @ManochaAcademy  16 днів тому +1

    For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
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  • @rithizx
    @rithizx 6 місяців тому +14

    HW : w= mg= N
    2×10 = 20 N=> Nf
    Coefficient of static friction(mu) =0.4
    fs = (mu)s× N
    = 0.4 × 20
    = 8 N
    But, even the 4N is acting on the object but the fsmax will cancel the force because it is Self Adjusting Force and the force is the less than fsmax ... 😊

  • @priyankakotian2651
    @priyankakotian2651 3 місяці тому +4

    I am really glad I found ur channel please keep making such videos now got friction into my head and heart
    answer to last question 8N.

  • @MAdciTy-v3e
    @MAdciTy-v3e 3 місяці тому +4

    I think the answer would be 8N because--
    M= 2 KG
    W= mg
    = 2 KG*10 m/s²
    = 20N
    Coefficient of static friction= 0.4
    therefore, 0.4*20N= 8N

    • @aritra1183
      @aritra1183 Місяць тому

      Wrong, this is limiting force or f max so to move the block you need more than 8N force the force applied on the block is 4N since friction force is self adjusting it will adjust itself to 4N and cancel the force applied
      So the answer is 4N

  • @niranjanninja1678
    @niranjanninja1678 8 місяців тому +6

    Thank you sir for clear explanation about friction ❤

  • @adebayoadekunle1251
    @adebayoadekunle1251 8 місяців тому +8

    The frictional force is 8N.
    Therefore the applied force, 4N, is not sufficient to move the box.

  • @benardbanks7938
    @benardbanks7938 8 місяців тому +8

    Hi,am benard from Uganda am happy to join you

    • @ManochaAcademy
      @ManochaAcademy  8 місяців тому +4

      Thanks Benard! Great to hear you like our videos! Do share it with your friends!

    • @arslansattar351
      @arslansattar351 8 місяців тому +1

      It's clay in generals. Language .

  • @user-hm5er4dn6w
    @user-hm5er4dn6w 8 місяців тому +4

    You are a blessing to most students who watches you💯, I thank God that I am of your UA-cam follower ❤❤❤❤

  • @ChiranjiviSanapathi-et7rb
    @ChiranjiviSanapathi-et7rb Місяць тому +2

    Thank s sir ❤😊

  • @sensei0001
    @sensei0001 21 день тому +2

    Sir , i am from mars , and your videos are just awesome 🎉❤

  • @IkenazorOzioma
    @IkenazorOzioma 6 місяців тому +3

    The answer is 8N

  • @ayushmondal8514
    @ayushmondal8514 8 місяців тому +4

    Really understood clearly the topic also enjoyed too....🤩🤩thanks sir for your support ❤❤❤

  • @kamalrajkhadka123
    @kamalrajkhadka123 8 місяців тому +8

    Hello sir your explanation is very well
    Love from Nepal❣️

  • @rohitshastry2007
    @rohitshastry2007 8 місяців тому +4

    This is really a very helpful video. Concept is Crystal Clear.

  • @cholamwambula140
    @cholamwambula140 8 місяців тому +2

    This is most wonderful experience explanation, so I like it sir

  • @navaidsaquibshaikh2382
    @navaidsaquibshaikh2382 8 місяців тому +2

    Thanking you sir for your effective explanation.

  • @user-hh5ez2wq6i
    @user-hh5ez2wq6i 8 місяців тому +2

    Why we should not used cos theta instead of tan theta to calculate angle of friction. Sir

  • @arslansattar351
    @arslansattar351 8 місяців тому +1

    Its flight of consistent i air.Height:gravity +force presere iniciated and de inicisted on road and air. Two diodes . ILclined end.

  • @alinazari4356
    @alinazari4356 7 днів тому

    World best video ❤️

  • @mgopal4927
    @mgopal4927 8 місяців тому +1

    Your explanation,teaching is awesome sir. Thanks a lot and lot .....for your service sir.

  • @user-pt8bq9ne2h
    @user-pt8bq9ne2h 8 місяців тому +1

    4 newton is the force of friction for the question sir

  • @roshnigupta1306
    @roshnigupta1306 8 місяців тому +1

    Bestt teacher 😊

  • @TThany
    @TThany 10 днів тому

    I like it sir and I understand well the concept of friction. Thanks for you sir😂❤

  • @ayushericekka651
    @ayushericekka651 8 місяців тому +3

    Great Video!!!

  • @arslansattar351
    @arslansattar351 8 місяців тому +2

    Law of flight inertia and clay friction is inverse to one other.

    • @arslansattar351
      @arslansattar351 8 місяців тому +1

      4

    • @arslansattar351
      @arslansattar351 8 місяців тому +1

      Bolts are pin apliers for race.break.clutch (pateren at control 14 feet )(28feet)$cale and compos (180 scale:1.3.0 compos:90 balance)

  • @arslansattar351
    @arslansattar351 8 місяців тому +1

    Batery and temptatire is rule of a moving obstecle .(/@w of movement)

  • @user-bp4yf5tq7t
    @user-bp4yf5tq7t 20 днів тому

    The way u taught ch friction now i don't have any doubt in this ch u r superb sirr thankyuu so muchh ❤

  • @user-kq5ft8sg3t
    @user-kq5ft8sg3t 8 місяців тому +2

    Hi I'm Solomon Manyuot Mabor, from south Sudan am so glad for the work you have done ✅✅✅👍👍🎉🎉🎉.

  • @ItsJustAurora.
    @ItsJustAurora. 3 місяці тому

    This helped me a lot when I was doing exams, Thanks! ❤❤

  • @muhammadkhanmarwat3770
    @muhammadkhanmarwat3770 8 місяців тому +1

    Nice way of teaching

  • @vijendran007
    @vijendran007 8 місяців тому +2

    Sir can you please upload vectors addition and subtraction.

    • @ManochaAcademy
      @ManochaAcademy  8 місяців тому

      We will definitely try to upload more videos soon!

    • @vijendran007
      @vijendran007 8 місяців тому

      Thank you sir

  • @GhatkuothBiel
    @GhatkuothBiel 7 місяців тому +1

    So wonderful topic

  • @ujwal181
    @ujwal181 Місяць тому +1

    what is your name sir?

  • @MohammedZulkifilu
    @MohammedZulkifilu Місяць тому

    The force of friction between the floor and the block is 8N

  • @geometric3150
    @geometric3150 8 місяців тому +2

    nice video

  • @sudhakarkashyap512
    @sudhakarkashyap512 2 дні тому

    Can you suggest me a good science book for class 8 and 9

  • @annetyebale6166
    @annetyebale6166 8 місяців тому +1

    Wow so interesting

  • @FazilVijay-et9md
    @FazilVijay-et9md 7 місяців тому

    Solution is here
    Given
    Ms=0.4
    Mass=2kg
    Applied force=4N
    Find force of friction
    Soln.
    N=W
    W=Mg
    =2x10=20
    Msmax=MsxN
    =0.4x20
    =8N
    Hence we need to produce more than 8N.but the Applied force is only 4N ,thus the object can not be moved.And answer for question =8N

  • @pintumukherjee5187
    @pintumukherjee5187 8 місяців тому +1

    Thanks a lot sir...ur way of explaining is inexpressible 🙏🙏.
    Please bring courses for 11 and 12 sir 😭🙏

    • @ManochaAcademy
      @ManochaAcademy  8 місяців тому

      Your welcome! Courses for Class 11 are coming in the first week of January!

    • @pintumukherjee5187
      @pintumukherjee5187 8 місяців тому

      @@ManochaAcademy for 12 sir?

    • @pintumukherjee5187
      @pintumukherjee5187 8 місяців тому

      @@ManochaAcademy pls launch courses for 12 also🙏🙏😭

  • @sriramulasreelekha2773
    @sriramulasreelekha2773 2 місяці тому

    In rolling friction 0.02 x10N/1m means in the final we get it's unit as N/m? But frictional force unit is N, how is it possible?

  • @sunahangrai3601
    @sunahangrai3601 8 місяців тому +1

    i like this teacher

  • @arslansattar351
    @arslansattar351 8 місяців тому +1

    Force and mas remain gravited this state any build ups .

  • @SaudaSalim-r4z
    @SaudaSalim-r4z Місяць тому

    Well teaching

  • @user-bn7yi9so5d
    @user-bn7yi9so5d 5 місяців тому

    I understand friction Thank you

  • @___________________________u2v
    @___________________________u2v 4 місяці тому

    Thanks ☺️

  • @odokenneth3712
    @odokenneth3712 3 місяці тому

    Thank you sir I would like you to make a practical lecture on physics and chemistry Thank you sir

  • @sarveshpatil1016
    @sarveshpatil1016 5 місяців тому

    you are best sir

  • @VishnuS-ht5qf
    @VishnuS-ht5qf 4 місяці тому

    Thanks sir tor explanation😊😊😊😊😊

  • @user-vp8iq2vj7e
    @user-vp8iq2vj7e 3 місяці тому +1

    Gud morning sir

  • @user-br3qv7yr3d
    @user-br3qv7yr3d 5 місяців тому

    I like your technic fo telling sir

  • @rhan9717
    @rhan9717 4 місяці тому +1

    thanks a lot for this amazing explanation! you deserve much respect!

  • @Salman_Hakro
    @Salman_Hakro 8 місяців тому

    Sir want a video on exam preparation tips

  • @siddharth......
    @siddharth...... 8 місяців тому +2

    I'm first manocha sir 😁

  • @ijeomatony7232
    @ijeomatony7232 5 місяців тому

    Frictional force i.e the limiting friction is 8N

  • @Pragya_kashyap
    @Pragya_kashyap 7 місяців тому

    Thank you sir🙏❤

  • @dinesha4525
    @dinesha4525 2 місяці тому

    How to calculate coefficient of friction?

  • @AshokKumar-ur2jf
    @AshokKumar-ur2jf 8 місяців тому

    Very good sir

  • @user-dv6ur2uq8e
    @user-dv6ur2uq8e 3 дні тому

    Hi sir

  • @ShadabRazi-cd9ip
    @ShadabRazi-cd9ip 2 місяці тому

    Sir , what is fluid friction ?

  • @Bint_e_islam-s
    @Bint_e_islam-s 8 місяців тому +1

    Sir g please basic statistics 😢❤😢❤😢❤

    • @Muslim__960
      @Muslim__960 8 місяців тому

      Yes, please sir 😢😢😢😢😢😢

  • @cubingprince8146
    @cubingprince8146 8 місяців тому

    Can you upload more videos for class 11 and 12? If possible, do it as soon as possible

  • @highvoltexplorer
    @highvoltexplorer 8 місяців тому

    Nice friction😊

  • @SaudaSalim-r4z
    @SaudaSalim-r4z Місяць тому

    And the answer is 8N

  • @user-qt4cc7ou1t
    @user-qt4cc7ou1t 8 місяців тому

    Sir, you are three much❤❤❤

  • @SreehaanChalla
    @SreehaanChalla Місяць тому

    The answer is 8n

  • @AbdulRasheed-jq4jt
    @AbdulRasheed-jq4jt 8 місяців тому

    Sir please make videos on ch electricity with experiments

  • @pusparasaayilavan4235
    @pusparasaayilavan4235 6 місяців тому

    answer is 4N

  • @FUSHIDOZI
    @FUSHIDOZI 26 днів тому

    5:06 hahah that sound

  • @codewithaditya5857
    @codewithaditya5857 8 місяців тому

    Sir question answer be 8 newton.

  • @Boxoun.
    @Boxoun. 3 дні тому

    Happy birthday 🥳 🎊
    I

  • @BandameediAnjamma
    @BandameediAnjamma 3 місяці тому

    8

  • @vivek_xo
    @vivek_xo Місяць тому

    4N

  • @eminentscholarsacademy0623
    @eminentscholarsacademy0623 8 місяців тому

    The frictional force is 8.0N

  • @NyirendaMackness
    @NyirendaMackness 6 місяців тому

    Your explanation, teaching is awesome sir.Thanks alot sending love ❤from Zambia

  • @AbdulRasheed-jq4jt
    @AbdulRasheed-jq4jt 8 місяців тому

    Sir I know you have made videos on the electricity but they are not enough they not have many things

  • @itsreallyrandom6331
    @itsreallyrandom6331 8 місяців тому +3

  • @saminanasir7598
    @saminanasir7598 3 місяці тому

    6:17

  • @worddeedschool5660
    @worddeedschool5660 8 місяців тому +14

    Good morning sri 🤣

  • @vibhavjee5788
    @vibhavjee5788 8 місяців тому +2

    1st view...

    • @ManochaAcademy
      @ManochaAcademy  8 місяців тому

      Super! Thanks!

    • @vibhavjee5788
      @vibhavjee5788 8 місяців тому

      @@ManochaAcademy thankyou for replying sir your videos help me a lot!!!.

  • @MBK_9ineT9
    @MBK_9ineT9 5 місяців тому

    I got 8N
    Is it correct

  • @sriritwikshastry9603
    @sriritwikshastry9603 8 місяців тому +1

    Amazing Video!
    NO more friction to study this topic :)

  • @AshokKumar-ur2jf
    @AshokKumar-ur2jf 8 місяців тому

    Sir class 9th also exampler book question answer and complite preparation (from bihar)

  • @modesterasamoah
    @modesterasamoah 6 днів тому

    hi sir i want to join ur class

  • @cubingprince8146
    @cubingprince8146 8 місяців тому

    Is the abs is 8N?

  • @Boxoun.
    @Boxoun. 3 дні тому

    Where do you leave 🛤️🛖😂😂

  • @user-qv6ln4sv4v
    @user-qv6ln4sv4v 7 місяців тому

    Thanks for sharing and helping us to know more knowledge about science😇😇

  • @user-zb6xj1vh3c
    @user-zb6xj1vh3c 8 місяців тому +1

    I am abraham from ethiopia

  • @ashwinin4983
    @ashwinin4983 8 місяців тому

    the frictional force between the block and the floor is 4N, same as the applied force as the applied force is less than limiting frictional force

  • @moturayomopelola4958
    @moturayomopelola4958 6 місяців тому

    What is the answer sir, I got 4N

  • @user-bn7yi9so5d
    @user-bn7yi9so5d 5 місяців тому

    4n

  • @RajinderSingh-ll6mq
    @RajinderSingh-ll6mq 21 день тому

    Sir when friction is constant how will we say our body in motion 😂😂😂

  • @user-fs4re3dc7n
    @user-fs4re3dc7n 8 місяців тому

    Thanks sir
    Well understood 🙏💕

  • @manojkhatri1245
    @manojkhatri1245 4 місяці тому

    Thaank you ita was gajab explanation 😊😮

  • @surekhamaske6866
    @surekhamaske6866 7 місяців тому

    Sri?

  • @ChiranjiviSanapathi-et7rb
    @ChiranjiviSanapathi-et7rb Місяць тому +1

    ❤😮😅 reply

  • @user-bn7yi9so5d
    @user-bn7yi9so5d 5 місяців тому

    8n

  • @srinuvasareddyvelagala6692
    @srinuvasareddyvelagala6692 15 днів тому

    Tell in Telugu

  • @user-iz2ky1kn2s
    @user-iz2ky1kn2s 2 місяці тому

    Are you Vishwajeet's father sir

  • @kartikmeena9688
    @kartikmeena9688 8 місяців тому

    Sir please explain in Hindi 😢😢😢😢

  • @user-zf7dd8jo6h
    @user-zf7dd8jo6h 5 місяців тому

    16newtons