You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
The answer is 24 kgm/s Solution : Change in momentum = mass * velocity Mass = 400g Velocity= 60 m/s Change gram into kilogram, As kilogram is a SI Unit 400 divided by 1000 = 0.4 kilogram = 0.4*60 =24 kgm/s
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity Final velocity= 60m/s Mass of the B = 400g = 0.4 From the formula Impluse= mv- mu 0.4×58.3 - 0.4×60 23.32- 24 = -7/10 nm
For constant acceleration "a" & V=½(u+v): F∆t~ma·|∆x|/V~(∆K/V)F^ ~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v. So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
Final velocity=60m/s Initial velocity=0m/s Mass of ⚽ =200g Solution:; Impulse= change in momentum =Pf-pi =(60m/s×0.2kg)-(0m/s0.2kg) =0.2kg(60m/s. - 0m/s) =12kgm/s
While teaching impulse using ball bounce example you said we can take any direction of motion of ball is positive and other as negative My question here is why we can take any direction as positive according to sign convention rule motion along right or upward side should be taken as positive and motion along left or downward side should be taken as negative please explain me
1st ball goes in upward direction with initial velocity of 2 ms means positive direction. 2nd ball comes in downward direction hence we take final velocity as negative.
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation. Thanks sir ❤ Answer of that question is -24kg.m/s
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
Initial velocity (u) of the ball = 0 m/s. Final velocity (v) if the ball = 210 km / sec = 58.33 m/s. And the mass (m) of the ball = 400g = 0.4kg 》》Therefore, IMPULSE (I) = MV - MU (I) = (0.4)(58.33) - (0.4)(0) (I) = 23.33 kg m/s
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How?? But according to Newton, 3rd Law action and reaction are equal. 2nd Question is that, what's physical meaning of 0.2kgm/S momentum???? Please! Reply, I will be waiting for your reply! Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced . Impulse=∆p =m(v-u) , we take mass as common. =m(-v-u) ,here v is negative And we know that . m(-2-2)=m(-4) I hope you will understand
sir do u only explain for CBSE class 11 students or even to state syllabus of class 11 and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
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The impulse is -48kgm/s
Final Velocity = 210km/h
= 60m/s.
Initial Velocity = 0 m/s.
Mass of the ball = 400g = 0.4 kg.
Impulse = change in momentum
= MV -- mu
= M(V -- u)
= 0.4(60 -- 0)
= 0.4 × 60 =} 24kgm/s *Ans*
Well bro❤
Well done
Ok thank u
😅😅😅😅
You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
You make Concepts Super Duper Easy! 🥳
Glad you like them!
u = 0 m/s, v = 60 m/s
mu = 0.4 kg x 0 = 0kgm/s and mv = 0.4kg x 60m/s = 24kgm/s
impulse = change in momentum = (24 - 0) Ns = 24 Ns
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
Impulse will be change in momentum.
So, Impulse=m(v-u)
=4/10(0-60)
4/10×-60
-24kgm/s.
Why-. It will be +24
coz ball is moving forward in the direction of given force so +24
0 is the initial velocity coz the ball was at rest before it was kicked
0:32
Getting this teacher teaching live today is a great chance
I use to watch his teachings always
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ua-cam.com/video/H1tF7a_HXVg/v-deo.htmlsi=zPqRxxr72EUGPtpj
The answer is 24 kgm/s
Solution :
Change in momentum = mass * velocity
Mass = 400g
Velocity= 60 m/s
Change gram into kilogram, As kilogram is a SI Unit
400 divided by 1000 = 0.4 kilogram
= 0.4*60
=24 kgm/s
Correct
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity
Final velocity= 60m/s
Mass of the B = 400g = 0.4
From the formula
Impluse= mv- mu
0.4×58.3 - 0.4×60
23.32- 24
= -7/10 nm
initial velocity will be 0 coz ball is in rest
Wow this man teaches so great much love from Nigeria sir , thank you
G
Best videos for A level physics which is hard... concept cleared
Sir you are best teacher I ever seen 🎉
Many many thanks!
I = ∆momentum
=mv - mu
= m(v-u)
= 0.4(60-0)
= 24 Kgm/s or Ns ❤
For constant acceleration "a" & V=½(u+v):
F∆t~ma·|∆x|/V~(∆K/V)F^
~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v.
So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
Impulse=change in momentum
I=mv-mu
I=m(v-u)
Given that
M=400g=0.4kg
V=210kmhr-¹
U=0ms-¹
I=m(v-u)
I=0.4(60-0)
I=24kgms-¹
Fantastic! Correct answer 👍
It's mind blowing, super explanation 🎉
V=210km/s=60m/s
mass of foot ball=400 gram =400/1000=0.4
Impulse = mv-mu
Impulse= m(v-u)
Impulse= 0.4(60-0)
Impulse= 24kgm/s
Final velocity=60m/s
Initial velocity=0m/s
Mass of ⚽ =200g
Solution:;
Impulse= change in momentum
=Pf-pi
=(60m/s×0.2kg)-(0m/s0.2kg)
=0.2kg(60m/s. - 0m/s)
=12kgm/s
0.2 kg ❌
0.4 kg✅
practicality is his strategy. he makes a complicated concept simpler. Thanks chemistry tutor
U=0m/s V=60m/s Mass of the ball =0.4kg
M(v-u)
0.4kg (60-0)
0.4 x 60
24kgm/s.
Impllulse = change in momentum
u=0gm-m/s^2
v = 400g × 60m/s
= 24000gm-m/s
=24kg-m/s
Impulsive force = 24-0
=24 kg-m/s
Thank you very much may god bless you
While teaching impulse using ball bounce example you said we can take any direction of motion of ball is positive and other as negative
My question here is why we can take any direction as positive according to sign convention rule motion along right or upward side should be taken as positive and motion along left or downward side should be taken as negative please explain me
1st ball goes in upward direction with initial velocity of 2 ms means positive direction. 2nd ball comes in downward direction hence we take final velocity as negative.
Answer= 24kgm/s
You're videos are amazing, and you even try to respond to every comment 🤯
Thanks
The answer is not applicable as we don't know the final velocity may be it rebounded untill reached the other goal keeper.
Outstanding way of teaching
Initial velocity = 0
Mass = 0.4 kg
Speed = 60m/s
So
Impulse = 0.4 *60
Which is 24 kg m/s
Impulse=mv-mu
m=0.4kg
u=0m/s
v=-60m/s
•°• impulse=0.4{-60-(0)}
=0.4×(-60)
=-24kgm/s
Amazing 😍
From Nigeria
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation.
Thanks sir ❤
Answer of that question is -24kg.m/s
Bro I'm also in 9th and I knewed most of the thing and also understood everything
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
Your video is amazing sir
# first comment
Thank you so much 😀
Initial velocity (u) of the ball = 0 m/s.
Final velocity (v) if the ball = 210 km / sec = 58.33 m/s.
And the mass (m) of the ball = 400g = 0.4kg
》》Therefore, IMPULSE (I) = MV - MU
(I) = (0.4)(58.33) - (0.4)(0)
(I) = 23.33 kg m/s
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
Sir in ball question isnt it -2.-2 be 4 not -4 so answer should be 0.4 not -0.4😢
The best teacher ever
Mind blowing way of teaching sir 🎉🎉top notch 🎉. Where r u from?
Amazing vido from ethiopia kidanu
Thanks for liking
You explain things very well
8:13 24 kg m/s
Super! Right answer!!
I really enjoy this videos🎉
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How??
But according to Newton, 3rd Law action and reaction are equal.
2nd Question is that, what's physical meaning of 0.2kgm/S momentum????
Please! Reply, I will be waiting for your reply!
Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced .
Impulse=∆p
=m(v-u) , we take mass as common.
=m(-v-u) ,here v is negative
And we know that . m(-2-2)=m(-4)
I hope you will understand
WOW! Such an amazing video!!
Thank you 😊
Very helpful sir.
Thank you sir
For. This video
Most welcome
Thanks for the super easy explnation
Great sir ! I am your big fan
Wow ! Thanks
Thank you sir for your reply, could you tell me where did you learn English and what is your fluency secret
I love you teaching
Thankyou sir❤
Waw nice page and tutor❤❤❤❤
Thank you so much sir, your video really helped me understand the concept of impulse.
An outstanding 🎉🎉 lecture!
Thanks for liking
24 kgms^-1
THANK YOU SIR
thank you sir, love your teachings
The answer is 24kgm/s
Sir why impulse is needed
Thank you sir
Welcome
thank you very much sir!!!!!!!!
Most welcome!
I like ur teaching, you make concepts super 👌
Thanks meet you again sr.
Interesting lesson sir.
Impulse= MV
Where m= 400g which is equivalent to 0.4kg
Total velocity= 60m/s
So , impulse= MV
Impulse= 0.4*60
Impulse= 24kg m/s
thankyou so much sir ❤️❤️❤️
The answer is -48 kg m/s❤❤
It is not a rebound. Initial velocity is 0. Try again you should get answer as 24 kg m/s
@ManochaAcademy oh yeah it's my fault thanks for the correction❤️❤️
Am from Pakistan ❤
Me also
Are you Muslim
Same 😊
This Comment is going to blast Soon 🌚💀
Nice bro im from ind respect to pak♥️
48Ans
momentum = impact ? and impulse = change of momentum ?
Ronny Heberson his impulse is 6kgm/s
|∆p| = |mv - mu|
= |0 - 24|
= 24 kgm/s
❤
Impulse(J)=M . Change in velocity J =400 . 0 J =0 ,therefore the impulse is 0 Kg/M.
sir do u only explain for CBSE class 11 students
or even to state syllabus of class 11
and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
I wish if I can have you as my physics teacher! 😢
Great to hear that you like our videos!
Sir Make 1chapter in 1shot ❤
Akshay Kumar left acting and started teaching physics😂
And he's really doing very well at teaching.
Ha ha :)
Ronny Heberson
Football lovers
Rooney Haberson
Football lovers
😂😂😂😂 can you leave our teacher alone
I can't understand the last question can somebody clarify me please?
24 kg.m/s is correct answer of footwall
Impulse:- ( -24 kgm/ s
PHYSICS CLASS 12TH LECTURE PLEASE FIR UPCOMING NEW BATCH
answer is 48 kgm/s
Wrong 😂
The answer is 24
Collision of two balls 💀
Please I want lecture for class 12th physics ISC please sir
-48
🎉🎉🎉
the momentum of the ball kicked by Ronny is 24kgm/s
Impulse is 24 Ns
I just solved it and got 24kgm/s
24kg ms-1
1:43 who watched in 0.25x 😂
Dear Sir, please clean your teath , its very distracting.
Love ~ Shayan
0.1×(-2-2) how sir
Ahh😢😢
Sir you can upload Gravitation chapter class 9 in Hindi Sir please don't ignore
Hello It's Jeet
9:01 9:02 🍖😱
Impulse=24 kg m/s
Super!! Right answer 👍
-24kgm/s
24km/s
hi
Hi, thanks for watching!
-48000
24 kgm/s
Im 16 year old girl need support
What help?
@cooking.818
In what aspect
Impulse of Ronny heberson kick is 240 kgm/s
It should be 24 kg m/s. Check your calculation.
Yes , it is my fault in calculation,
Impulse= 0.4×60-0
=24kg m/s