1.1.2 Vector Algebra: Component Form

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  • Опубліковано 1 гру 2024

КОМЕНТАРІ • 10

  • @MukeshKumar-ef4rz
    @MukeshKumar-ef4rz 8 років тому +5

    great series, helps in brushing up the basics. thumb's up!

  • @LennyMarkh
    @LennyMarkh 12 років тому +3

    A good way to determine the cross product operation is to write out ijki. When you move to the right, e.g. from i to j you add the term, when you move left, e.g. i to k, you subtract the term.
    So for the the i direction you'd have (A_y * B_z - A_z * B_y)
    A_y * B_z is positive since you moved from left to right and
    A_z * B_y is negative (subtracted) since you moved from right to left.

    • @divwyanshu
      @divwyanshu 2 роки тому

      If you are still active, I cannot understand your approach. Please elaborate

  • @jg394
    @jg394  12 років тому +3

    Yep. That works too. Whatever helps you remember.

  • @AgnimitraSutradhar
    @AgnimitraSutradhar 8 років тому +3

    Amazing Intro to the electrodynamics besides Griffiths is the great book for Intro to Electrodynamics and J.D.Jackson gives the priceless numerical :)

  • @Tube-gl2sh
    @Tube-gl2sh Рік тому

    In the ciruit of fig. Below find the effetive capacitance and charge stored in each capacitor?

  • @jimdogma1537
    @jimdogma1537 11 років тому

    There typically is. He just multiplied the j-hat expression by -1 to reverse the terms so that I-j-k hat all added together. However, I think that just complicates the easier way to find the determinant. If I didn't already know how to find it, I think I would have been confused.

  • @animals42life8
    @animals42life8 7 років тому

    In 0:59 time frame, you said that "a vector can formed as a sum of the scalar products of each of these basis vectors..." In the left hand side, it is a vector so it is obvious that it must be vector also in the right hand side, but in the quoted message, it's a scalar product which has a scalar value. It's contradicting. Can you please make some clarifications? Thank you, I've been really looking for some basic materials to learn Electrodynamics, and I think I found the right startup.

  • @kunaltandon2711
    @kunaltandon2711 5 років тому +4

    I think the second term in the determinant should be -ve as per the rules of determinant.