Complex Numbers : Roots of a quartic equation : ExamSolutions

Tutorial on complex numbers and how to find the roots of a quartic equation.
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[@yolanankaine6063]

You've basically taught me the whole chapter. Thanks so much

[@mrtrash5873]

You sir, are a genius. Thank you.

[@ExamSolutions_Maths]

+Mrtrash 587 I wish I were, but thank you anyway.

[@SirUni25]

Thanks! It helps me a lot as teacher. I know now how to teach this certain lesson to my learners.

[@ellaee5814]

Thank you for your video!

[@TheKohler94]

thank god i found this! helped so much!

[@yondabigman4668]

thank you, there are barely any websites that cover further math.

[@ExamSolutions_Maths]

You could in theory but I would not encourage it, especially if some roots are complex numbers.

[@YAKUMO0822]

Thanks!it help me in my work!

[@ExamSolutions_Maths]

No problem. Pleased to hear it helped.

[@DonAbhilash]

Would they give a real root and ask to find the other roots?
if yes, then how would you do it?

[@mdjahin99]

Thank you Sir!

[@marly5000]

amazing video!!!.....it really helped thank you :)

[@ExamSolutions_Maths]

Pleasure

[@frankivinstutoring3775]

Can anyone explain why you are able to state that the multiple of the two complex factors must equal zero? This is stated without explanation. Couldn't they multiply to give some non zero value since any of the other two could be zero?

[@abhi20user-z8jm5my9p]

Good strategy w and m

[@ExamSolutions_Maths]

@PeteJohnMcGarvey yes

[@MegaBunky]

brilliant.

[@dannym1917]

thank you for this :) it really helped :)

[@asantesanamotsa5186]

May God bless you abundantly

[@cyclopsnipple]

Yeah they always are for quartics, but sometimes they give cubics with no roots provided

[@9526772]

may i ask whether the root will be provided or not ?

[@chowcalvin59]

Can you factorized them if the question never give any roots?

[@842Mono]

Someone has already asked this question in previous comments here. The reply was no; it's not possible. :)

[@gbzhou529]

Seems it would be easier to use the fact that sum of all roots=-b/a and product of all roots=e/a

[@ExamSolutions_Maths]

@Raufkool You couldn't

[@benboys_]

Can a quartic have only 1 real root just touching the x axis? If so, what would the 3 complex roots look like? And is there a cubic with 3 complex roots?

[@ExamSolutions_Maths]

If it touched then it would be a repeated root. So it could have 2 real roots and then the other two would be complex conjugates of one another or there could be 4 real repeated roots and then no complex roots.
As for the cubic it is impossible to have 3 complex roots.

[@Raufkool]

Hi ! How would one proceed if none of the roots are provided ?

[@zunnunzahid]

Use trial and error starting from -3 to +3 integers

[@cookietho_o1054]

What does the i in the 4-2i stand for?

[@ExamSolutions_Maths]

i = the square root of (-1)

[@ExamSolutions_Maths]

Sorry, I am confused by your question.

[@theycallmemuzz7394]

Nothings as trippy switching back to normal playback speed after watching this playlist in x1.75

[@ExamSolutions_Maths]

@Mal1234567 hi

[@111falak]

hahaha i like your username!

[@raeesshafiq4539]

8:15 unnecessarily long method lol