Russia | A Very Nice Algebra Problem

[@Tr1dun9]

Does it need to add modulus after you remove the square root

[@Sergey_Moskvichev]

Видимо не нужно, так как остаётся чётная степень 4.

[@jolpicmagazine4494]

No because the sign before the square root tells you everything.

[@prollysine]

--> 4x^3-6x^2+4x-1=0 , by faktoring multp. *1/2 , 2x^2(2x-1)-2x(2x-1)+(2x-1)=0 , (2x-1)(2x^2-2x+1)=0 , 2x-1=0 , x=1/2 ,
2x^2-2x+1=0 , x=(2 |+/-| V(4-8) )/4 , solu ., x= 1/2 , (1+i)/2 , (1-i)/2 ,

[@prollysine]

Thanks !