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Показувати елементи керування програвачем
Автоматичне відтворення
Автоповтор
[1+√(x+3)]² = [√(x+2)]² -> 1+x+3+2√(x+3) = ±(x+2) -> either: 2√(x+3)=-2 -> (x+3)=(-1)²=1 -> x=-2 (Check shows the answer is invalid) Or: 4+x+2√(x+3) = -x-2 -> 2√(x+3) = -2x-6 -> √(x+3) = -(x+3) -> x=-3 (Check shows the answer is invalid) .
So you solved for the extraneous solution, but what is the correct solution?
The solution to this equation is that the equation has no solution!😉 This is a case where the equation has no (valid) solution.
@ ok thanks!
Ok I see it. X =-2 is the only correct solution.
But -2 is as a solution is extraneous sir.
[1+√(x+3)]² = [√(x+2)]² -> 1+x+3+2√(x+3) = ±(x+2) -> either: 2√(x+3)=-2 -> (x+3)=(-1)²=1 -> x=-2 (Check shows the answer is invalid) Or: 4+x+2√(x+3) = -x-2 -> 2√(x+3) = -2x-6 -> √(x+3) = -(x+3) -> x=-3 (Check shows the answer is invalid) .
So you solved for the extraneous solution, but what is the correct solution?
The solution to this equation is that the equation has no solution!😉 This is a case where the equation has no (valid) solution.
@ ok thanks!
Ok I see it. X =-2 is the only correct solution.
But -2 is as a solution is extraneous sir.