Solving Rational Equations

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  • Опубліковано 17 лис 2024
  • www.greenemath....
    / mathematicsbyjgreene
    In this lesson, we review solving rational equations. To solve a rational equation, we will multiply both sides by the LCD of all rational expressions. We must be careful, since multiplying both sides by a variable or variable expression will sometimes give us extraneous solutions. Therefore, we must always check our proposed solutions for a rational equation in the original equation.

КОМЕНТАРІ • 14

  • @mikerich8661
    @mikerich8661 8 місяців тому +1

    Whenever I solve a rational equation, when using the zero product property, if a factor matches with at least one of the denominators of the original rational equation, I underline it to show that this factor can be ignored because it would have a value that is not permissible in the original rational equation. For example if (x + 7) is in one of the denominator at least and is in the equation (x + 7)(x - 8) = 0, I would underline the (x + 7) and ignore it because it would cause an extraneous solution to the original rational equation. Hope this explains how I solve rational equations.

    • @Greenemath
      @Greenemath  8 місяців тому

      Some books will show it that way as well by putting the domain out first. {x | x ≠ -7, 8}

  • @adelinamarasigan2147
    @adelinamarasigan2147 4 роки тому +1

    Thank u so much. God bless!

    • @Greenemath
      @Greenemath  4 роки тому

      You are so welcome! Good luck with your studies :)

  • @reydichos8560
    @reydichos8560 4 роки тому +1

    in the first example. where do you get the "add 10" and the "-2" pls comment hehe

    • @Greenemath
      @Greenemath  4 роки тому

      What's the time marker?

    • @reydichos8560
      @reydichos8560 4 роки тому +1

      3:49

    • @Greenemath
      @Greenemath  4 роки тому

      @@reydichos8560 In order to solve the equation for x, you need x by itself on one side. 2x - 10 = x + 4, so to get rid of the 10, we add 10 to both sides.
      2x - 10 + 10 = x + 4 + 10
      The -10 + 10 becomes 0, so you just have 2x on the left.
      2x = x + 14
      So from there, you can subtract x away from each side:
      2x - x = x - x + 14
      x = 14, which is the solution;
      Not sure where you saw a -2, need a time stamp on that one? If you are struggling with theses steps, might I suggest you start at the beginning of the course? My website is completely free:
      GreeneMath.com

    • @reydichos8560
      @reydichos8560 4 роки тому +1

      @@Greenemathahh okaay'2 THANK YOU SO MUCH!

    • @Greenemath
      @Greenemath  4 роки тому

      @@reydichos8560 You are very welcome!

  • @ivmm3340
    @ivmm3340 5 років тому +2

    Thanks😊👍

  • @thefightreport69
    @thefightreport69 Рік тому +1

    Brian mclogan is confusing af

    • @Greenemath
      @Greenemath  Рік тому

      Math is a very hard subject to learn.