TMUA Paper 2: Old ECAA logic questions

[@stanleyjessop7273]

These videos are outstanding, you’ve a gift for communicating the solutions in a clear and engaging way

[@hgbdph4593]

Genuinely such a useful video, fresh paper 2 questions and potentially the only free, worked solutions for them on the internet. Thank you.

[@Philmloud]

I paused the video before you went through it and got the exact same thing as you did for 2016 Q36. Anyways thanks so much for all your TMUA videos I've been watching since the beginning of this year in prep for Tuesday :)

[@hawadoh]

7:01, I think the question is asking us to find the contrapositive statement, which should be option E but the ‘or’ replaced with ‘and’

[@vrinda5700]

That's exactly what I thought as well. Should be and.

[@hawadoh]

@@vrinda5700 yea I still think it should be option E!! if you’re doing the TMUA this year (idk if it’s discontinued), good luck bro!! I got 7.1 last year and I’m sure you’re do just fine!!

[@vrinda5700]

@@hawadohI agree, it's the one that makes sense.
Yes, I will be doing the TMUA this year- it's in 2 days and I'm freaking out lol. I think they're discontinuing it from next year. Thanks btw :) and wow that's a great score, I only hope I'll get as much!!
Any last minute advice?

[@anaklusmus]

@@vrinda5700 how much did you get I'm doing it this year, please please give me some advice

[@AA-nn7eh]

For Q36, I think you're right because if you get the contrapositive of the statement by using De Morgan's laws you get X is on and Y is off.

[@_gusowen]

I

[@PK-uj8mp]

7:01 remember that the definition of 'or' includes 'and' in its definition, since its inclusive. If we take 'a or b', or means 'a', 'b', OR 'a and b'. We want 'If Z is off, then x is on AND y is off'. E fulfils this condition still because it uses inclusive OR, we can discard the the 'a only' and 'b only' because we have 'a and b'

[@PK-uj8mp]

It's like saying 2=>1. We know 2 is obviously not equal to 1, but => is just as valid as saying >, they're both correct

[@rtwodrew2]

Yeah I was considering this but I didn't know whether ECAA used that same definition as TMUA. But I agree that this is the only explanation

[@anaklusmus]

i like your explanation, wanna be friends? i am taking tmua this yr

[@Spudandrowback7D]

I have u to thank for whatever score I get

[@JackFan22]

I think the bulb question is E because if bulb X is on or bulb Y is off, then bulb X is on and bulb Y is off is also true. Since we are only saying that it is necessary and doesn't need to be sufficient, then it is ok.

[@anaklusmus]

for 2017 q35, if f(x) is a quartic with the middle stationary point below the x-axis, and you do y=2f(x), isnt it possible to bring the middle stationary point above the x axis or touch the x axis?

[@anaklusmus]

or because the y value if the middle stationary point is negative so multiplying by 2 moves it down

[@anonymous99923]

how did you factorise it at 14:05?

[@julianolechowski]

For the bulbs question, if you draw out a truth table for "if not(X) or Y then Z":
X Y not X Z
0 0 1 1
0 1 1 1
1 0 0 0
1 1 0 1
It becomes clear that Z is only off if not X = 0 and Y = 0, so X = 1 (on) and Y = 0 (off). Hence, the answer is D.

[@Benhutchie22386]

Thank you!

[@cheesecake2281]

I thought Q35 cant be a cubic as it must intersect the x-axis not just touch it? But the case is still wrong if you look at a negative quadratic

[@cheesecake2281]

Just realised idk what intersect implies

[@rtwodrew2]

Yeah I don't think intersect excludes tangentially

[@zzzzzzl491]

yea q36 should be contrapostitive, meaning that if A'--> B then B'--> A is true

[@shahd888]

loved the fire breathing pigs question haha

[@LK-sk9wl]

I think 36 should be D

[@rtwodrew2]

It's definitely not D, because if X was off, Z would definitely be on, so that configuration doesn't work