Physics - Mechanics: The Pulley (1 of 2)
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- Опубліковано 25 сер 2024
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This lecture series will cover Newton's Second Law of Physics: F=ma.
This lecture series will introduce you to the function of a pulley, also called the Atwood Machine.
Problem Text:
A string is placed over a massless and frictionless pulley. A mass of 8kg is suspended at one end while a mass of 5kg is suspended from the other. What is the acceleration of the system.
i've learned more from you in 11 minutes than i have from my professor in 9 hours.
Thank you!
It is good to see that these videos are peaking your interest in physics and science in general. It does appear that you are re-discovering the principles and understanding them. Good for you!
I wish that you teached me when I was in high school, I always loved physics but my grade are not that good, but now thanks to god that I know your channel...
Michel van Biezen thank u
Thanks, sir!!!
Your teaching is excellent but I do have one question, why did you make the gravity positive? I would have made the gravity negative because its going downwards, but it would give me the wrong answer.
@@abdulnaqvi8284 Because gravity itself, fundamentally, is a DOWNWARD force. (As it *PULLS* objects toward earth)
So the positives value will always be downwards, and negative value will be upwards because it is against gravity.
Hope u get it, correct me if I'm wrong.
My left ear learned a lot from this video.
lol i thought it was just me !
I would have been puzzled the whole video if I didn't see your comment xD I only had my right one in
i thought my earphones have broken!
I also thought my earphones were broken xD
My right 👂 is angry
Damn this is high quality video for a physics tutorial. Subbed
it is pretty nice to see that you are still replying to comments considering the fact that the video was uploaded 9 years ago! I am generally solving these questions by turning these two masses into one body and finding the acceleration from there.
Yes, that is the technique we use in the videos as well; look at the whole system as one entity.
Thank you your explanations are very in depth with a simple and easy to follow delivery. Keep up the good work.
Wow this video was God sent! Someone recommended this video in an MCAT practice question thread and this just explained everything so well. Thank you :)
Glad it helped and glad you found our videos. They should be a big help for getting ready for the MCAT. 🙂
Why this tutorial did't come when I was young. I'm now learning together with my daughter from your tutorial. It's very useful. Thank you.
First day discovering the channel. 995,000 subscribers!!! I bet when I come back in a couple days you’re over the mill mark 👏
Welcome to the channel. There are 9900 videos, so that will keep you busy for a while. 🙂
Really like how you explain simple pulleys. Make my life alot easier
Thank you, Sir! This was great. I had two physics teachers that tried to explain this to me and they made it so complicated by subbing equations into each other. You made it so easy and I have a test tomrrow.
Glad it helped!
Thank you, You have helped my understanding and with that i have improved my grade significantly.Thanks
this saved my life from a high school teacher that doesnt know how to teach properly, basicaly a self tought class. This helped me very much thank you!
Video was very helpful, helps an AP high school student more than the teacher does.
Thank you so much! I understand you much more than my AP Physics teacher... hopefully i'll do fine on my test tomrrow!
Jonathan che my words exactly
How’d it go??
It's been four years. Did you pass?
i've learned more from you in 11 minutes than i have from my professor in 9 hours.
thanku sir...love and respect from india...
Welcome to the channel.
damn entered my left ear and left
+Dhruv Pandey
Sorry but our early video are for left-ear only. Then we discovered we could make our videos for left- AND right-ears!
+Michel van Biezen lool
Entered your ear and left 🤣🤣😂😂
This video is exponentially better than the SAT study books I just bought.
Faisal,
At first only using variables (and no numbers) may look strange and confusing.
But it is the best way to learn how to solve problems in physics.
I recommend that you learn this technique, because in the long run, it will greatly improve your ability to solve physics problems.
Just take it one step at a time and make sure you understand each step before going on to the next step. After giving it some time it will make sense
Thank you sir.Your lecture is the savior.I really hate my physics teacher and like a rubbish.Thank you so much for my physics test!
Glad you found our videos. Good luck on your test. 🙂
Great teaching understood it in 13 min. Wish my school had a good Physic teacher.
Glad it was helpful!
This man deserves a damn award, saving my grade one video at a time.
Extremely helpful video, Mr. Biezen. Very clear and I appreciate how you solved algebraically before plugging in values; I usually define my formulas and jump in plugging numbers.
Dear lord, I was trying to figure out how to answer a problem, surfed for an hour and half, and you helped me. THANK YOU !
Thank you so much for this! I completely did not understand the lesson from my teacher, but this video explained it wonderfully.
Glad you found our videos! 🙂
You are welcome. Thanks for the comment.
Thankyou my school teacher sucks so i study from you 🙂👍
Glad we are able to help with our videos. 🙂
What a perfect video for the night before my exam. Thank you so much for this!
All the best on your exam.
I wish my professor would teach these concepts straightforward like Biezan, he does it in like 10min too. My professor just explains how the equations are derived and has us do practice questions as HW, without actually doing at least one problem to show us how its done. Going though step by step of how to solve physics questions in these videos helps me understand more and gives me hope to pass my physics class
Thank you so much! Had a problem like this on Khan academy, the hints and solutions really weren’t helping glad I found this!!!
Glad it helped!
Thank you sir. You are better than my real Physics teacher.
If I could like this video twice I would. Thank you so much Mr Van Biezen for these
YOU JUST SAVED MY PHYSICS GRADE BLESS YOU
Thank! You had to do some heavy lifting too.
Suvrath Hegde
Sure. It makes everything a lot easier. If you are just trying to understand the concepts or show that you know how to solve a problem 10m/sec^2 makes it much simpler. But when the "exact" answer is asked for you must use 9.8 m/sec^2
I have clearly understood whatever he explained me...now I can do my exam well.
Thank you so much. Repeating the video over and over has helped me a lot!
I love to learn physics specially when mathematical equations are involved. You do such a great job at that. Thanks you for sharing the knowledge!
You are very welcome. Glad you found our videos! 🙂
Just watched an entire 2 min studypug ad AND clicked the link, cuz you deserve it. Saved my ass
Thank you
There is a formula for this type of question which is actually a derivation.
Here the mass of object 1 should be greatest than mass of object 2 (m1 > m2) and should be in Vertical motion
For acceleration
a = [(m1 - m2)÷(m1 + m2)]×g
For tension
T= [(2m1m2) ÷(m1 + m2) ]×g
(I mentioned in magnitude)
If m1 = m2
Then
a=0
If i am wrong correct me
Nice work. We try to avoid assigning equations to everything, instead teaching the techniques to derive the equation in any situation.
@MichelvanBiezen Sir, it's actually very helpful. Your way of teaching is great and beginner friendly too and you explain the concept crystal clear.I really appreciate it.All I wanted to convey is that if direct formula and tricks are given it will be helpful for students appearing in competitive exams that's it. And Sir, I have been watching your videos for a long time and it really helped me to ace my exams😊. Thank you so much. Wow it's been 11years and you still reply. Hats off
And I am going to attend an entrance exam. Wish me luck please🙏
Best wishes and good luck!
Got a physics test on this tomorrow and you saved my shit bro good looks
Shadd,
I believe I made a problem like that.
Thank you, this was super helpful!! was browsing the physics forum for ages trying to figure out how to solve a standard pulley problem and this explained it so simply instead ^^;
Glad you found our videos. 🙂
Beautifully explained
its always the old videos, thank you so much
Glad you like them!
We call it Atwood's machine because Mr Atwood came up with this machine for the purpose of slowing down the acceleration of gravity, so that it would be practical to measure it accurately when subject to human reaction time. He also used it as a way to experimentally verify the constant acceleration kinematic formulas.
Nice comment. Like the insight.
sir, your explanations are tremendously good!!! Love 'em. I hope I watched 'em in the beginning of my sessions
Great job. Thanks for uploading physics problem solving videos... These videos will be very helpful for physics guys.
Anyone else cramming some last minute studying before an exam?
Lol me
Lol me
Hahaha
Akuu
beautiful studied for one 3 nights and i got everything that i need to pass my upcoming test thank you
Thanks for your explanation! The detail you added really helped me to understand!
Merry Christmas 🌲 thanks for all the wonderful videos and explanations.
Merry Christmas to you as wll. 🙂
@@MichelvanBiezen 🙂
Very clear explanation from Papua new Guinea
Glad you think so! Welcome to the channel!
I learn more from this
Thank u sir , I understood the problems very well and u explain by easy way 👍
thanku sir...i studied these things like a life ago......kind of nicely refreshed the memory..
Wow sir you are the best, I had a different question from this one but I found everything right...the tension I calculated is balanced thank you I just subscribed ❤
Welcome to the channel! 🙂
Sir, Thank you so much for the lesson!
You are welcome.
In college physics, this is amazing. thank you.
You are welcome. Glad you found our videos. 🙂
I finally understand this topic
Glad you found this video. 🙂
Thank you SO much. I can't tell you how much your videos help. It makes a huge difference in my confidence this class.
I was very stressed out bc I thought I would fail my phy final exam...u make it alot easier to me I rly appreciate ur cooperation Mr u saved my life...we need more videos like this with simple explanation.honstely I wish u were my physics teacher. Tnx again
Really good, really helpful thanks for spending the time to do this for us!!!
my left ear loved this video
thank you so much. such a good teacher
I learned a lot!!! Thanks for helping me in the exam!!
I have an exam in 10 minutes this saved my skin
What a quick reply
🙂
why did he write m1g minus m2g and not plus? if you look at the diagram both forces act in the same direction so the resultant force on the system is g(m1 + m2). what is the explanation for putting a minus?
To find the net force you must add all the forces that aid the acceleration (they act in the same direction as the acceleration) and SUBTRACT all the forces OPPOSING the acceleration (they act in the opposite direction of the acceleration).
+Michel van Biezen yes because even though m2g is acting down, acceleration for M2 is upwards so it opposes. thank you very much, i understand now :)
sir you just saved me now i understand pully problems thank you once again I am in class 9
That is great. Where do you go school? Typically that is not covered in grade 9 here.
same here brother, these pakistani and indian schools make us teach these college things in grade 9 and 10
Very nice explainer
Thank you so much, you saved my test grade
Good luck on your test.
Great video, thank you!
Glad you liked it!
My right ear hated this
But my left ear loved it
Great video! Explained very clearly.
i know that the m2g is slow down the systyem acceleration but the definition when we sum the force is force in the same vector need to add not subtract
Because you want to differentiate between which forces are aiding the acceleration and which forces are opposing the acceleration.
Yeah but how it can controversial the definition
Very helpful video!!! Thank you Mr. Biezen!
I really wish you were my physics teacher... Physics would probably be more enjoyable if you were.
Thank you. We do try to make it interesting in our classrooms.
Thanks man helped me out a lot
It's interesting how a guy with such great physics tips set's up a stereo microphone so we all only get the left side input :-D
That's the problem. My husband and I are physics and math majors, not film majors. Hence we have absolutley no knowledge of how to make videos or video mic equipment. However we do have some sort of learning curve. Therefore our less "old" videos are in stereo!
@@MichelvanBiezen Dear Mrs van Biezen
I have to tell you that the content of the video was - in my huble opinion - top-knotch, and the AV production quality was of a high standard.
The only quirk was the onesided audio, which had no impact on the message delivered.
I retract my comment as it was useless, as I see multiple other people saying the same thing in the comment section.
Thank you for making these videos. This specific lecture on pulley mechanics helped me get through a physics problem that I was struggling with, and I am grateful.
I will continue to watch your content, and I will take it happily, right, left or both ears :-)
We don't take it personally. It's all a learning curve.
Thank you so much respected Sir.
Glad you found this video helpful. 🙂
example are easy with less consept involved regards from india
Welcome to the channel
thanks for the comment. saved me
Glad we could help.
Thank you, sir!
You are welcome. 🙂
Thanks man
Gracias!!!!! Me ayudó bastante a entender el ejercicio!!
Thanks!!
Welcome!
thanks for the explanation
Let us say I'm making a 2:1 ratio pulley system. 1st mapping is: (A) 10kg weight on ground rope tied to it, (B) Pulley anchored on ceiling, and (D) I am hand pulling from free end on ground over top pulley to move (A) to a balanced point and progress capture. Here I get 10kg to move, 20kg on pulley anchor, while I tugged at 10kg. Correct? OK... Map 2: What if I add another identical size pulley hanging same height @ 60cm away... then run atop both pulleys still in a 2:1 (no direction change). Even if angle of the two pulleys is more or less out of the equation... Am I reducing friction? Does this have potential for preventing potential vectoring or twist of my tugging position? Did I make any difference like changing acceleration or ease I might feel by possibly sort of creating a larger bullwheel so there is less bite over just atop the single pulley? I know that is a lot to ask. Thank you for considering my inquiries.
MY first questions get transformed into another practical or not reason to know where I am going with this. Map X: I am standing on the shore trying to free a pinned raft. I am fortunate enough in this scenario to have the pulley attached to the Raft. I make a 2:1 Point (A) = Shoreline anchor Point (B) = Pulley secured to Raft Point (C) = Me tugging on the free end of rope. Here I should get mechanical advantage of shoreline anchor receiving same load as me tugging, while the pulley to Raft is doubled. Correct? SO... what if I employ a second identical pulley inline with first, same 60cm apart (maybe/likely even more) still 2:1 as in no direction change for second pulley. Same inquiry: am I achieving anything other than a backup pulley? Thank you again.
The mg force is in the Same direction so we can’t calculate in one system because F =ma can use only F make the object has Same acceleration but we need to calculate in each object and add 2 equation so we can get your equation does it correct
There are 2 ways to solve a problem like this. You can take the whole system at once and calculate the net force on the whole system, or you can draw a free body diagram around each mass and calculate the total force on each block, and then solve the the two equations simultaneously. The first method is easier and faster, but they are both correct methods to solve the problem. We show the second method in a different video.
@@MichelvanBiezen but the whole system solution has the source from the each mass equation rigg
What do you mean by the "source". We are only dealing with mass and force, not sources. Also, what do you mean by "solution"? We are either looking for acceleration of the system, or the tension in the string.
Thanks 🙏
You’re welcome 😊
you are the best! love from cyprus!!
For a small island, we have a lot of students watching our videos from Cyprus. Welcome to the channel!
very nice
A very interesting lecture. My question:
How would you explain this by the old system? Since you only examine a static condition, the forces in the rope’ s sides while the pulley is not rotating.
I spent 60 years in static engineering and I am glad that I got out of it in the right time. One of my daughter is a physicist from Cambridge.
In this example, the pulley is rotating and the masses are accelerating.
thankksssss love uu, no homo tho, great explanation, far better than my lectures
You are welcome. Glad you found our videos. 🙂
The tension in the string is 60.3, the resultant force is 60.3*2 = 120.6(N), which is less than the sum of the two weights (5+8)*9.8 = 127.4 (N). Please explain why!
The tension in a string can only equal the weight of the object havning from it, IF the object is not moving or moving at a constant speed. If the object is accelerating, the tension will not be the same. (See the other videos in the Newton's application videos).
Thank you very much!
Mind expanded thank you 🙏
Glad you found our videos. 🙂
Until now, I had used a much longer approach ie ......8g-T=8a.......T-5g =5a...to give a =3g/13 =2.26
Sir when will tension be different and how will we find acceleration when tension is different
We have examples of that when the pulley has mass. Physics - Mechanics: Application of Moment of Inertia and Angular Acceleration (2 of 2) ua-cam.com/video/wrhT5xGS-f8/v-deo.html
Thanks really helpful and well explained !!!!
And what if I wanted to include friction and mass of the pulley? How would the equation look?
We usually ignore friction (since it tends to be insignificant), but if the pulley has mass you must take into account its moment of inertia: see these two chapters: PHYSICS 13 MOMENT OF INERTIA APPLICATIONS and PHYSICS 13.1 MOMENT OF INERTIA APPLICATIONS 2 starting at: ua-cam.com/video/dEAtTpIG8AM/v-deo.html and ua-cam.com/video/XHkDJwQ4Xng/v-deo.html