Mesh Current Problems - Electronics & Circuit Analysis
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- Опубліковано 22 сер 2024
- This electronics video tutorial explains how to analyze circuits using mesh current analysis. it explains how to use kirchoff's voltage laws combined with ohm's law to calculate the electric current flowing through each resistor as well as the electric potential of each node.
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Well said...
@Devadut S Balan u take things way to literal😬
@@jorgelevario3478 who asked
@@Jeffman529 who asked
@@triparadox.c who asked
I understood mesh analysis more in 30 minutes from your explanation than I did from my 2 hour lecture. Thank you!
Indian lecturer?
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Understood from a 27 min video that I couldn't done from a 3 week class 😅
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Thank you for this video! I've been confused with my teacher's method because when I change the direction of the loop, it no longer works but this still works whatever the direction of the loop was. Again, Thank you!!
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I was confused as well but the answer is actually correct because there are two ways to solve this.
1) (His way) to keep the polarities constant in each loop while using the previous current calculation.
2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop.
Both ways result in the same answers.
At 14:00, why does he put 8(i1 - i2) instead of 8(i2 - i1) when i2 flows through the positive of the resistor so shouldn't i2 be positive and i1 be negative?
Beacuse he was working According loop 1...
8(i2-i1) is correct. I guess he missed that side
I was confused as well but the answer is actually correct because there are two ways to solve this.
1) (His way) to keep the polarities constant in each loop while using the previous current calculation.
2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop.
Both ways result in the same answers.
I always get clarity in your videos. Thank you, Sir. Highly appreciated
i think in loop 2 the V2 will be 8(i2 - i1) not 8(i1 - i2) as the dominating loop is 2nd not 1st
It still made sense tho
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You say use Vb for the voltage across the battery but on your circuit diagram Vb is designated to the node where R1, R2 and R3 connect.
16:55 shouldn't V4 be 2(I3-I2)? It's a drop for I2 and a rise for I3. Why does he flip it?
2 years later i'm still confused
2 months later even I'm confused@@ntwisisochauke3495
I spent 2-3 hours on these type of questions finally someone was there to help me out thanks a lot
Explained it better than my lecture..... your methods are easily understood...Thanks
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A lot of upper level Math, Physics, and Engineering actually all combine in various ways, (for example, a course like Statics uses concepts from all 3). Chemical Engineering could be a potential major seeing as all of these different fields combine.
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He is an Electronics Engineer.thats why
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Love this guy's videos. Helped me several times already!
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Thank you! I've finally understood Kirchhoff's laws and mesh current analysis after watching this video
Jeez I understood mesh more than I did in my 3hrs class
Thanks very much sir
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In example 1, why is the current flowing through R2 the difference between I1 and I2? Is it just convention to make both loops flow in the same direction clockwise? (That is, Mesh Analysis does not work if we do not do it this way?)
I'm confused by the arrow on the current source. To me it seems to say that I2 should flow in the *opposite* direction, but perhaps I am misunderstanding
You’re so good…I love you Man 😁
This video helped me a lot. You've done a tremendous work explaining this topic. Thank you!
Friday 26 March, 2021 - 9:22 p.m. - I have a HW in EE 204 ( 2 Hours to the Dead line ) Thanks very much
LUAI
At 4:20, he says Vb is 90V, but we can only know Va is 90V and that Vb is in fact smaller than that.
he said Battery
14:03
Sir
Isn't it should be 8(i2- i1)?
Coz i2 is potential rise and i1 is potential drop
Edit:
I compared the approach of other vloggers, in this video R2 and R4 remains with their polarity that's why 8(i1-i2)
In the other approach they reverse the polarity between the meshes
Mesh 1
R2 is Positive UPWARD
Current downward
Mesh 2
R2 is positive DOWNWARD
current upward
Mesh 2:
- 8(i2-i1)-5i2-2(i2-i3)= 0
BY INSPECTION this video is right. 🙏
Thank you for this video
I was confused as well but the answer is actually correct because there are two ways to solve this.
1) (His way) to keep the polarities constant in each loop while using the previous current calculation.
2) (another way) To change the polarities according to the current flow direction and input the new difference in current by giving priority to the current that is in that certain loop.
Both ways result in the same answers.
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In fact you helped me. 🤝
this was a very good example. Thanks
Thanks I understand this better with your explanation
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you know its good when you watched the video understood it and then the second you get stuck come straight back watch a few seconds and it all clicks again. I think its a linked memory with voice complex that recalls information
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Organic chemistry tutor? I say organic chemistry god.
I have been watching your videos for years, but with this class I don't know if I can. My professors unfortunately uses different conventions on when a current is negative or positive which is the opposite of yours, so even though you're much better at teaching this stuff, I think it's just going to cause confusion learning two different conventions at once. :/
Eggzactly
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I believe there is an error in the calculation, What he's effectively done is swapped the polarity of the voltage across the 2 ohm resistor R2, here's how,
in the first loop he designated I1 flowing from high to low potential through R2 and I2 flowing from low to high, that's fine, but then in the second loop he has designated I2 flowing from high potential to low potential by making the equation -8I2 and designated current I1 flowing from high potential to low potential by making the equation +8I1, this is effectively changing the arrangement of the signs of the voltage across R2 when analysing the current through R2 in the second loop compared to the first
how can that be correct? Would the same be true if R2 were a battery? Because the sign of a battery doesn't change since the direction of voltage across it is fixed, and according to the math he's done, he isn't sticking to the sign convention he has assigned for the voltage across R2 from the first loop, i understand he is taking the difference between the currents I1 and I2 but he's doing so in the wrong order, i believe it should be 8(I2 -I1), if you disagree that's totally fine but i would appreciate if you explained why. Many thanks friend.
I got confused at that part as well. Your reasoning is correct I think. I also had a sort of "rule" that I followed for mesh current analysis. When you are working inside a loop, the positive sense of the current is the sense of the current of your current loop.
At the first loop, the positive sense would be that of I1, therefore the current at R2 would be I1-I2 because I2 is in the opposite direction from that of I1.
At the second loop, the positive sense now becomes that of I2, so the current at R2 would be I2-I1 because I1 is now in the opposite direction of I2 (which is the positive sense).
However, it seems that doing it like that is wrong. I checked the values in Multisim (a circuit simulator) and his values are correct. If you solve it with R2(I2-I1) you get wrong values. I hope someone explains why that is the case as I don't really understand it.
Edit: One possible explanation probably has to do with the fact that the current has to flow from a point with a higher voltage to a point with a lower voltage. Since one end of R2 is connected to ground, if you take I2 as a positive quantity you are assuming that the current I2 is flowing from the ground up to Vb. Which is impossible.
I am not sure if this is the right explanation though.
The video is too much of a spin . the video is just a bad description of equation writing . And the video lacks detailed information of technique . Confusion number 1 : the Video does NOT use Mesh currents thru R2 , instead he is adopting a Branch current technique thru R2 , because he is using a Single +-polarity across R2 . Basically , the video is a mess and needs to be redone .
the Two Fragments would be written this way , when using a Branch current flowing Down thru R2 : +( I1 - I2 )R2 for Mesh I1 , and -( I1 - I2 )R2 for Mesh I2 .
however ,
when using "Mesh Currents" flowing thru R2 , the Two Fragments would have been written this way : +( I1 - I2 )R2 for Mesh I1 , and +( I2 - I1 )R2 for Mesh I2
notice for both Mesh I2 fragments , they are Identical :
-( I1 - I2 )R2 is the Same as +( I2 - I1 )R2 .
however ,
the Symantic of writing these Fragments is Hugely different . As said , one is based on using a Branch current thru R2 , while the Second writing is done using Mesh currents thru R2 .
if these Fragments seem odd or confusing to write , then you do NOT yet underand the basics of KVL , Ohm's Law , Branch currents , and Mesh currents .
NOT your fault , as many books are Poorly written by people who do NOT know what they are talking about ,...especially 2 year Tech school level books ( the worst )
the video is very lacking of KVL with Ohm's law equation writing details .
@@ArjolP what would happen if someone Pre-labels a +-polarity across a resistor that is NOT +pos Ohm's law , and they are asking for the voltage across that resistor . would that pose any issues during the equation writing process ? the answer should be No . the circuit is still just as easy to analyze regardless of the +-polarities across the resistors . There should be absolutely No confusion . if there is confusion , then something is not yet understood .
@@ArjolP you do not yet understand how to solve simple physics problems. you have taken the video's analysis Out of Context .
you are trying to use a Convention that is in your head . however ,
the Convention that is in your head is NOT the same convention
the video is using .
i am posting a new response to Numan Ahmed
with a Full explination as to why the first level equations in the
video are Valid and Correct , for R2 in the 3 loop circuit .
please note , the video is trash and is a very bad way to present
circuit analysis .
yes , the video is trash .
however ,
the first level equations written in the video are valid and correct .
to understand this , you MUST use the same Convention and Orientation
the video is using .
you have a particular Convention in your head that you want to use ,
however , other peoples analysis might be using a different Convention .
Thus , to follow someone elses first level equation writing , you MUST
know what Convention they are using .
i analyzed his analysis ( Meta analysis ) to understand what he did .
( i can do that )
the 3 loop circuit :
the video's convention writes the KVL +-sign as he Exits each component .
the video's convention is using Branch currents thru R2 ( the 8 ohm resistor )
the video says he is using mesh currents , however , he is actually using
Branch currents . thus he does NOT know how to use mesh currents .
But ,...
based on the Conventions that he used , the First Level equations are Correct.
Here is how he wrote the Fragment you speak of , for R2 , starting with loop I1 :
he is Traversing CW ClockWise and he is writing KVL +-sign as he Exits each component.
Exiting R2 at the Bottom of R2 is -neg .
thus he writes -neg8 ( I1 - I2 ) .
note that ( I1 - I2 ) is the Branch current thru R2 .
next , for loop I2 , still Traversing CW ClockWise , at the Exit point of R2
( Top of R2 ) , he writes +pos . +pos8( I1 - I2 ) .
again , ( I1 - I2 ) is the Branch current thru R2 .
he could have shown : I4 = ( I1 - I2 )
where I4 is the Branch current thru R2 .
with I4 flowing Down thru R2 .
Your ( observation and curiosity ) are Out of Context .
Realize , there are many , many Conventions that can be used , and thus
there are many , many ways to write first level equations for the same circuit .
All of the Conventions that could be used are ALL Valid , and ALL the
first level equations that are written of each of those conventions are ALL valid .
however ,
once we choose a particular ( Convention and Orientation )
we need to "Stick with it" , so we do NOT contradic our selves ,
and to avoid a convoluted mess ( such is your question )
you should solve a basic vector based projectile physics problem ,
and apply all that technique to solving electric circuits .
( read beyond the words in the electronics book ,...go deep )
we can always analyze the same circuit using another ( different )
Convention . our initial first level equations will look different .
but in the end , the numerical answers will still describe the exact
same circuit operation .
( provided we have No errors in our math manipulation )
Thanks from Egypt ♥️
Students might also find one (or more) of my videos helpful for Mesh and Nodal Analysis ..... I have videos for every aspect of electronics ...... but in circuit analysis Playlist I have videos for all the methods ..... supernode, supermesh, superposition, Thevenin, Norton, source transformation and etc. ..... sometimes it helps to watch several videos for the same topic to get a fuller understanding
Thank you 🙏🏾 and God bless you
Thank you Sensei 🙇🏾♂️
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Good idea.
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There is a error at 15:07. it should be negative v4, its a voltage drop for loop 3 for r4 not a voltage rise so -v4
are we seeing the same video?
forgive my ignorance, (first problem) but was this just an example problem? or is it somehow actually possible to have more Voltage than what the battery outputs? because if the battery is 90V and point C is 94, im wondering how its possible, does it have to do with the current source? thank you in advance
I also have the same question and also commented on this, and I'm waiting for the response.
Thanks a lot! You save my day.
Thanks from Ghana 🇬🇭
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for second loop, shouldn't it be 8(I2-I1)?
I believe it should be
If you are going to do it like that it has to be -8(I2-I1) .
Nope, there's a special case current source which is the 5 amp, basically the 2nd loop is i2 = 5A
if a Branch current is being used thru R2 , where the Branch current is depicted to move Downward thru R2 , the 2 Equation Fragments you speak of would be : +( I1 - I2 )R2 for Mesh I1 , and -( I1 - I2 )R2 for Mesh I2 .
however ,
if he had used "Mesh Currents" thru R2 , the Two Fragments would have been written this way : +( I1 - I2 )R2 for Mesh I1 , and +( I2 - I1 )R2 for Mesh I2
please note , the Two Fragments of Mesh I2 are identical ,...
-( I1 - I2 )R2 is the Same as +( I2 - I1 )R2
being identical , it can be confusingly easy for someone to Mix conventions of
Branch currents and Mesh currents . Thus many people do NOT know what
they have actually written ,...been there , done that , but NOT anymore .
The Symantic of writing these Two Forms is Hugely different .
If this seems odd , then you do NOT yet know the difference between a Branch current and Mesh Currents , and you do NOT yet clearly understand how to Traverse a circuit using ( KVL with Ohm's Law ) . keep studying , keep reading .
it takes depth of understanding of using ( KVL with Ohm's Law ) , to know the simplicity and difference to what is going on here . The video does NOT discuss such details . And there is NOT enough room here , for me to describe those details .
he wrote 8( I1 - I2 ) when in Mesh loop I2 ,
but he did NOT describe the technique . what technique ?
was he using the +-sign as he Enters each component ?
was he using the +-sign as he Exits each component ?
the Video is a mess .
He is using the +-sign as He Exits each component , when writing the KVL +-sign.
He is using the +-sign as He Exits each component , when writing the KVL +-sign.
And , he reverted to using a Branch current thru the 8 ohm resistor .
He is NOT using Mesh currents thru the 8 ohm resistor .
Thus ,
he does NOT know the difference between a Branch current and a Mesh current.
While traversing Mesh I2 , he encounters the 8 ohm resistor .
Traversing Up thru the 8 ohm resistor , the +-sign Exiting 8 ohm resistor is
+pos ( at the Top ) .
Next , he is using ohm's with the Pre-labeled + at Top and - at Bottom .
thus he wrote +8( + I1 - I2 ) , which is Valid , in the context of the technique
he is using .
note : +8 is +KVL , + I1 is +pos ohm's law , while - I2 is -neg ohm's law .
I do NOT write equations the way he did . He has choosen to do it like that ,
and he does it the same way all the time , than the equations that he writes are
valid ,...but what a mess . Too much effort to Reverse Engineer to discover
someone's Technique . He should have described all this at the begining .
Still ,
he does NOT know the difference between a Branch current and Mesh currents .
Effectively , he wrote the equation fragments using Branch current I3 , as if
I3 were the Current that flows Down thru the 8 ohm resistor . That is why
he always writes ( I1 - I2 ) for ( Mesh I1 and Mesh I2 )
of the 8 ohm resistor , because I3 = ( I1 - I2 ) .
For the equation fragments that i wrote , i am using the +-sign as i
Enter each component . And i am writing ( KVL with Ohm's Law )
for the Resistor .
A Voltage source only has KVL +-sign , as there
is No Ohm's Law for an Independent Voltage Source .
in addition to all that , some people choose to ( KVL hop )
across each component when traversing , saying V-rise or V-drop .
Many techniques are possible , however some techniques are easier
to use then others . using KVL hop is usually more difficult to use .
using +-sign when Exiting each component is usually more difficult to use .
quick observation to your question :
+8( I1 - I2 ) is Valid
- 8( I1 - I2 ) is Valid
+8( I2 - I1 ) is Valid
ALL Three are Valid !
how can that be ?
when using different techniques , the first level equations can look differnent .
regardless of the technique used , once a technique has been choosen ,
ALL portions of the equation writing must then use this same choosen technique .
Thus , your question really comes down to Mixing Conventions during the
equation writing process . His equations are Valid , based on the technique
he is using . You are trying to view his analysis in a way that you are familiar
with but is a different convention , thus you are Mixing Conventions thus you
caused confusion onto your self .
your initial concern does reveal an important point .
When writing equations , do NOT Mix techniques .
When writing equations , do NOT Mix Conventions .
If you choose to write KVL +-signs as you Exit each component , then you MUST
Always do that for Every component in the circuit , during a particular analysis .
If you choose to write KVL +-signs as you Enter each component , then you MUST
Always do that for Every component in the circuit , during a particular analysis .
@@nax1807 It should NOT be .
+8( I2 - I1 ) NOT Valid , based on the Context of technque the video is using .
you too , are Mixing Conventions .
Judy - chan question is Out of Context .
Judy - Chan is Mixing Conventions .
i have a Huge explination to Judy - chan .
Hello to every struggling engineering aspirant (like me :3) watching this video
in the second example, I believe you could have solved the system of equations faster by solving for i1 in the first equation and solving for i3 in the third. Then just plug it all back into the second equation. Then plug in i2 into equations 1 & 2 to solve for i1 and i3, respectively.
You wrote Vb on the Va.I didn’t thought that you denoted Vb= Vbattery. I thought that you made a mistake on the first example. Till you said on the 2nd example that Vb stands for battery voltage. Lol
That's why I also got confused and went to other tutorials because of that mistake haha.
No wonder I kept messing up, my school teaches the other way where if you go from - to +, you put a negative sign in the equation. I interchanged both often.
Respect Sir!!!! Thank you!!!
G.O.A.T tutor. However, at 14:20 it should be I3 instead of I2 I believe.
u are my hero
respect from jordan