How to Make Frequency Table, Histogram, Polygon and Ogive

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[@BurmeseUSA]

I dont remember how many times I refer back to this video. so helpful to me. thanks .

[@helpyourmathstat]

I'm glad it helped

[@murungigeofrey7482]

Thanks I am Moses 💕🥰

[@user-vb6xh8tu5e]

thank you. this video is really help. i love how patient and clear you make sure to be in every step

[@amoahbright696]

Thank you instructor. I love your pace and explanations as to which parameters to use for which graphical representation

[@helpyourmathstat]

You are very welcome! :)

[@ReadySeasoning]

Me, who was confused about an exam, which I will be taking next week,and God gracious, I discovered that video, and it really helpful and beyond ❤

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[@herbydeslorge]

Thank you Miss! That is very helpful, I ve been struggling with an exercise for days now I got some clue to solve it because of your explication.

[@helpyourmathstat]

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[@zipporahwanjiru4270]

She really made me understand and learn new things about frequency

[@helpyourmathstat]

You are welcome! :)

[@rocketrider1405]

You always subtract 1 from the value of the LCL of the 2nd interval to obtain the UCL of the first interval if the lowest place value of your data is 'ones' as it is here ... if the data looked like 4.1, 6.7, 9.2, 12.1 ... then you'd subtract the value of the lowest place value which in this case is one tenth in order to obtain the UCL of the 1st interval.

[@emmanuelwara9794]

Thanx very much for this resourceful illustration, it really summarized everything for me on frequency distribution....

[@helpyourmathstat]

You are welcome. Please check our Free Statistics Website for all Statistics topics you may need help with, helpyourmath.com/150.5/mat150

[@seal0118]

great walkthrough, thanks

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[@umaralexander]

Wow! You've solved my problem with grouped data. God bless you

[@helpyourmathstat]

You are very welcome! 😃

[@Odhiambozakayo]

Thank you for well explained

[@Midnightrider.]

Thank you so much miss you were of great help to me i needed help with ogive and frequency polygon.

[@helpyourmathstat]

You are very welcome!

[@omanjawalpita5112]

Your explanation is very clear mam.Thank you soo much❤.

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[@masuma_khatun3872]

Thank u so much!For me,it really summarized everything about frequency distribution. And You speak very nicely 😍.
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[@ricemasterdragon2166]

Do i have to round for the class midpoint?

[@milley1087]

Why am I lost. Where did 39 and 105 come from in the polygraph

[@itsmee1817]

I think it's because if you look at all the numbers at the bottom of the polygraph they each have a gap of 11 so how she got the 39 was she did 50-11= 39 and the for 105 she added 94+11 to get that. Hopefully that helps :)

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[@helpyourmathstat]

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[@user-st6gh7fx2i]

Thank you for sharing this, it helps a lot :)

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[@chawulaninhleko]

Thank you well explained

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[@radanerobinson4131]

This is very informative.

[@helpyourmathstat]

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[@mandisimavuso]

During Frequency polygon at the end where we took 39 and 105 ?

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[@successnicki8146]

What do I use if the number of class is not given.
Please someone should give me an answer

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this video very very very helhpful to me
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Tnx nice lecture mam

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Thank you ❤

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[@noori_guk2475]

when I'm trying to find mid point on my own by adding lower limit 45 to upper limit 55 then dividing with 2 it's giving me 72.5
Can u plz tell me why?

[@helpyourmathstat]

You did 45 + 55/2 = 72.5. The correct way is 45 + 55 = 100, then 100/2 = 50. Or (45+55)/2 = 50. Thanks! - Prof. Xin from HelpYourMath

[@noori_guk2475]

@@helpyourmathstat ohhh thnks I got it 😌❤️

[@gemechisaabera8799]

Ok teacher What is reduce formula class boundary

[@elivaidahbridget7246]

Also where does the 105 come from

[@rajamuneeb4669]

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Thanks Maam :)

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[@dananjayachathuranga7113]

thank you

[@jennas6236]

where did you get 39 for the polygon chart ?

[@user-mk8kq8sf3h]

1:From the table, we know class midpoints are 50,61,72,83,94, which are also x coordinates for the polygon chart.
2:You may find out the gap between two consecutive midpoints is always 11; for example, 61-50=11, 72-61=11.
3: Therefore, we can conclude that the point before 50 is 39 ( 50-11=39).

[@wegotthis2345]

@@user-mk8kq8sf3h oh my thank you so much for this as i have the same question.

[@user-mk8kq8sf3h]

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​@@wegotthis2345 You are very welcome!!! As a volunteer of helpyourmath, I am happy to help.

[@ahadmoen]

Impressive ma'am🥰

[@helpyourmathstat]

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[@kiplazh]

Thank you

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[@Study_knowledge05]

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[@zakariemohamedisak1162]

Thanks you

[@helpyourmathstat]

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[@niyahtg1860]

Why did she round the 10 to 11? Rounding is usually done to get a whole number. I am confused.

[@helpyourmathstat]

Please watch this video: ua-cam.com/video/V-LHn7jPczs/v-deo.html

[@elinessmutakilamfunda1417]

That's the rule... You round off wether it a whole number or decimal

[@anthonystark1514]

It's because you always have to find the ceiling of a number in statistics, so you round up. Ceiling means to round up

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[@the.sniper.trader_]

Please how did you get 39 and 105 on the frequency polygon, treat as urgent i have a test tomorrow by 9am😩😩

[@helpyourmathstat]

???

[@elivaidahbridget7246]

Very helpful but I don’t understand where the 39 comes from ... the 39 before 50

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really i get all

[@helpyourmathstat]

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[@helpyourmathstat]

Thank you!

[@idirisxaashi5725]

Why did you add class width 10 +1 =11

[@helpyourmathstat]

For Class Width, round up the dividend to the next whole number. If your dividend is 2(whole number), 2.1, 2.2, 2.3, 2.4, 2.5... 2.9, round it up to 3.

[@RougeLace]

is 10 not a whole number? why do you have to round up to 11?

[@helpyourmathstat]

Please watch this video: ua-cam.com/video/V-LHn7jPczs/v-deo.html

[@hafizzuhari6003]

i miss physical class :((( this video help me so much

[@helpyourmathstat]

You are welcome!

[@nkwoimmanuela3826]

1:05
10 is a whole number already. Why take it to 11?
I thought you only applied that rule when you have a decimal value🤔

[@abelngenda6817]

Exactly my thought too

[@seyhamean1897]

Why10 change to 11?

[@helpyourmathstat]

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[@AbdulRehman-yo3wq]

eaisly defined

[@helpyourmathstat]

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[@sweetcancer_6963]

for some who doesn't get what the '# of classes' - the formula is k = 1 + (3.322 [Log(n)])
And for some, you need to know that the CLASS WIDTHs' formula is C = R/k where R = Max - Min divided by the k = k = 1 + 3.322 Log(n)
Also, I would like to add in order to organize for huge data sets you can use the STEM & LEAF method, it's very easy and helpful when you utilize it for these ungrouped data

[@anelemadiya5785]

Is it always 5 classes even if they didn't give you?

[@helpyourmathstat]

The number of classes is determined by each question. This example demonstrates with 5-classes. But you can apply this for other number of classes, such as 6-classes, 7-classes, so on.

[@omunguochieng9664]

i think you have made mistake you are not supposed to ad the no. of class but the class width on thye class limit

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