Since then I came from Africa to India I didn't know any single word of Engineering graphic designing but through you sir I'm now not to compare with others... thanks you so much
Hi Md. Patel..... I am sure these videos are helping you learn the concepts... All the best and do let your friends know about this channel so that they can also benefit.....
awesome sir i am from iit kgp earlier i used to hate this subject but now due to you only i have started understanding its concepts The way you teach is such that i have started imagining Things in 3D thanks a lot Keep making new videos :)
Hi Rahul..... I hope you are enjoying the content.... I am glad that your interest in this subject has started to grow.. Thats great... Do watch all the videos on drawing and mechanics...... And also let your your friends know about this Channel so that they can also benefit.......
+Aparna Krishnan Hi Aparna.... I appreciate your comments.... All the best And do let your friends know about this channel on drawing and mechanics so that they can also benefit.....
What a nice way of teaching and letting us imagining the whole scenario sir ...... commendable efforts .... thank you for making concepts so clear as crystals .....
+saurabh pathak Saurabh..... Thanks for appreciating my work... And i believe that you are enjoying the videos..... And do let your friends know about this channel on mechanics and drawing so that they can also benefit..... All the best.......
You are the great sir, when i am seeing your videos, it seems like you put your all efforts, and i also gets more energy to understand your concepts,,, really hardworking sir... thank you sir..
Draw the projections of a circle of 50 mm diameter resting in the HP on a point A on the circumferences, its plane inclined 45" to the HP and the top view of the diameter AB making 30 angle with the VP
+Pavan Tej Thanks a lot Pawan..... Do watch all the content both from drawing and mechanics..... And do recommend this channel to your friends, classmates and juniors so that they can also benefit......
Thank you so much sir.......... I don't know what is projections of planes by seeing this tutorial I able to write my exam. Once again thank you sir......😊😇😇😇
+gaurav dubey Hi Gaurav.... Thanks for your kind words and appreciating the content..... And do let your friends know about this channel so that they can also benefit.... All the best in life......
I had a doubt, when we say the diameter's TV is inclined to VP at 30 degree. Is it necessary to take points a and b as the the diameter on the 30 degree line or can we take any two points?
Hi Manas........ I am sure these videos are helping you learn the concepts... All the best and do let your friends know about this channel so that they can also benefit.....
A circular plate of diameter 80 mm is resting on a point of its periphery on H.P. such that it makes an angle of 400 to the H.P. The diameter passing through the point of its resting on H.P. makes an angle of 600 with V.P. Draw the projections of it.
Draw the projection of a circle of 50 mm diameter resting in the H.P. on a point A on the circumference, its plane inclined at 45 to the H.P. and The top view of the diameter AB making 30 angle with the V.P. (ii) The diameter AB making 30° angle with the V.P.
1.Draw projections of a rhombus, ABCD, with AC = 80 mm and BD = 50 mm if: a. BD is parallel to both HP and VP, and AC is inclined 30º to VP 2.A pentagonal plane rests on VP on one of its corners, inclined 30º to it. The diagonal through that corner is inclined 30º to HP. Draw its projections, if it lies in the 4th quadrant. SIR CAN YOU PLEASE SOLVE THESE TWO QUESTIONS???
Hi Bilal.. I am sure that these videos are helping u learn... Keep watching and do let your friends know about this channel so that they can also benefit................
Draw the projections of a circle of 50 mm diameter resting in the H.P. on a point “A” on the circumference, its plane inclined at 45° to the H.P. and the diameter AB making 30° angle with the V.P.
Hi Sai..… Thanks for appreciating my work…and all the best for your exam I am sure this channel is helping you learn…You can support my channel by donating and do watch this video: ua-cam.com/video/WfyUEhxhjZU/v-deo.html Have a Nice day
I used shiver when ever I hear about EG , but after watching ur lectures am pretty interested in EG and more life saver for many of the students Thank you for wonderful videos And amazing explanation
You said that the edge which is going to be inclined in the third step is placed perpendicular to line XY in the first step.. No edge type thing is here but we have a line(diameter), can't we coordinate circle in the way that line AB is perpendicular to line XY
Hi Paramesh....Well Thanks for appreciating my work... All the best in life And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401 Small contributions can make a Big Difference
7. A circular lamina of diameter 40 mm rests on one of its circumference point on H.P. the diameter containing the point inclined 45° to V.P. The surface of the lamina is inclined 40° to H.P. Draw its projection
Hi Neel.......First of all....Thanks for appreciating my work.... I always focus on giving you guys excellent quality free education.... All the best in life and do let your friends know about this channel on drawing and mechanics so that they can also benefit....
Sir u always asked us to take the line perpendicular to XY which is going to inclined in 3rd step then in this question why did u kept AB parallel to XY, why didn't we took point A at point 5 in fig. Thankyou
Yes edges which will be inclined in final step has to be kept perpendicular to xy line..... But this is diameter ok...... Edge is different from a diameter
shows a thin plate of negligible thickness. It rests on its PQ edge with its plane perpendicular to V.P. and inclined 40° to the H.P. Draw its projections. Sir can you plz explain this question.....
Sir, In earlier videos you said that whichever edge gonna be with any plan (HP or VP) that edge should be perpendicular to xy line in step 1 . But here ab (diameter of circle) is parallel to xy , why ?
Superb explanation sir I had learned very well and I have no words to express as it is very helpful and I too had shared with my friends sir and they too got helped from you tutorial sir “THANKS A LOT SIR”
Manas Patnaik sir in second case why do we take the true length of diameter on the 30° line and then cut an arc with top view ab's distance on the straight line from b?
+opposer The answer to your question lies in the video itself.......And its in a way related to projection of lines as in diameter as a line.....Remember if its top view length is inclined we use beta and when its true length is inclined we use theta.....
Hi Vibhu........ I am sure that these videos are helping u learn... Keep watching and do let your friends know about this channel so that they can also benefit.......
sir... In case 2 of this problem, we are asked to make a true length of a diameter inclined to VP, so have you found out the inclination of the reduced diameter with VP. Sir this can be done as it is done in case 1 right????
In this 3 rd step arc is not cutting on the locus line with ab radius and with center a while we try to cut locus line the arc is cutting at point b original position?????
A circle, rotated once, looks like an ellipse. Rotated a 2nd time, it again looks like an ellipse, which we draw using the spline function. Find a method to draw the second ellipse exactly.
Thanks for appreciating my work... All the best... Teaching is my passion.....And dont worry all the content that i upload can be accessed for free forever.....
Sir the last recreating one of the true length i did understood but I didn't understand why are we taking ab of the top view as radius any reason behind that?
Since then I came from Africa to India I didn't know any single word of Engineering graphic designing but through you sir I'm now not to compare with others... thanks you so much
all the best brother....take care
U are literally better than profs of iit. Thanks for saving my day and exam!!!!.
Hi Md. Patel.....
I am sure these videos are helping you learn the concepts...
All the best and do let your friends know about this channel so that they can also benefit.....
awesome sir
i am from iit kgp
earlier i used to hate this subject
but now due to you only i have started understanding its concepts
The way you teach is such that i have started imagining Things in 3D
thanks a lot
Keep making new videos
:)
Hi Rahul.....
I hope you are enjoying the content....
I am glad that your interest in this subject has started to grow..
Thats great...
Do watch all the videos on drawing and mechanics......
And also let your your friends know about this Channel so that they can also benefit.......
You. Are. A. Life. Saver. Amazing. Thank you so, so much!
+Aparna Krishnan
Hi Aparna....
I appreciate your comments....
All the best
And do let your friends know about this channel on drawing and mechanics so that they can also benefit.....
Manas Patnaik My entire class uses your videos to practice. 😃
Sir thank you for your help your videos are really amazing it's very easy to learn.
Aparna Krishnan Smthg not satisfactory...
Hi
What a nice way of teaching and letting us imagining the whole scenario sir ...... commendable efforts .... thank you for making concepts so clear as crystals .....
+saurabh pathak Saurabh.....
Thanks for appreciating my work...
And i believe that you are enjoying the videos.....
And do let your friends know about this channel on mechanics and drawing so that they can also benefit.....
All the best.......
Sir
I have doubt on recreating the circle with ab inclined at 30 degree
I never seen the face of my drawing sir...upto I know you're the only teacher of me and who ever asks about my drawing sir ...I reply MANAS PATNAIK
All the best Bhanu
God Bless.....
YOU SAVED ME FROM FAILING IN Engg Drawing
You are the great sir, when i am seeing your videos, it seems like you put your all efforts, and i also gets more energy to understand your concepts,,, really hardworking sir... thank you sir..
भैया जैसी चित्रकारी आपने करी है हम तोह मन्त्रमुक्त हो गए बिलकुल।
Draw the projections of a circle of 50 mm diameter resting in the HP on a point A on the circumferences, its plane inclined 45" to the HP and the top view of the diameter AB making 30 angle with the VP
In UA-cam no one say like you sir
I learned by you only sir....
All the best.
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MashaAllah, amazing explanation ❤
Splendid stuff. You're the superhero who wears no capes.
Your teaching is excellent sir and a lot easily understandable.
We need more and more videos from you sir.
Wow manas sir is still replying to comments 😍
This is pawanteja patnaik... U doing a great work sir.. Plz do it through out.. Students need this type of visual class.. Thank u sir.
+Pavan Tej
Thanks a lot Pawan.....
Do watch all the content both from drawing and mechanics.....
And do recommend this channel to your friends, classmates and juniors so that they can also benefit......
Thank you so much sir..........
I don't know what is projections of planes by seeing this tutorial I able to write my exam. Once again thank you sir......😊😇😇😇
Incredible guide you are Manas... kudos to you
+gaurav dubey
Hi Gaurav....
Thanks for your kind words and appreciating the content.....
And do let your friends know about this channel so that they can also benefit....
All the best in life......
Yeah for sure... its done already...
Do you have any video on traces????
If not then plz make one
Thnxx
+gaurav dubey
There is a video on traces of lines......
Thanks you helped me solve a layout issue for designing our curved from wood hoods for cabinetry!
sir u did not showed the difference between two cases
Tum Bht Mast Kaam Karte Ho Manas Bhai 💯
Gr8 teaching sir
But I have doubt in 3rd stage
Do we have to draw the 30degree angle from pt.of intersection of 2',5'-2&axis
I had a doubt, when we say the diameter's TV is inclined to VP at 30 degree. Is it necessary to take points a and b as the the diameter on the 30 degree line or can we take any two points?
You are a real god for all the engineering students more than a God thank you so much for your best way of teaching sir
Sir you are awesome what a teaching wonderful job sir I never seen before this type of teaching thanks a lot
Hi Manas........
I am sure these videos are helping you learn the concepts...
All the best and do let your friends know about this channel so that they can also benefit.....
A circular plate of diameter 80 mm is resting on a point of its periphery on H.P. such that it makes an angle of 400 to the H.P. The diameter passing through the point of its resting on H.P. makes an angle of 600 with V.P. Draw the projections of it.
Thnx a lot sir.......i'm from dtu and tomorrow it is my test......you're great sir
Sir tan q so much....u r really a visible god to Engineering students
Sir i have doubt at the step 3 sir can u explain me sir please
Thank you sir for this video.
What the real figure looks like in the second part where true lenght is inclined at 30°?
A great explanation. Its commendable. Good English and teaching methodology.
nice work realy useful for Beginner technologist (Best of Luck)
Hi Shoaib.......
I am sure my videos are helping you learn.....
Keep watching and do share this with your friends also...
All the best......
Ya it's very helpful fr me .and am also sharing your lectures to my friends Thanxx alot Manas patnaik
Draw the projection of a circle of 50 mm diameter resting in the H.P. on a point A on the circumference, its plane inclined at 45 to the H.P. and
The top view of the diameter AB making 30 angle with the V.P.
(ii) The diameter AB making 30° angle with the V.P.
In 2nd case at 10:53 why you have 30deg from line 2'5'. Why not from any other point on XY.
You can take it further away also..no issues........
Thanks sir this is very kind of you , that you reply to my question.
Very helpful sir!!
+omega king i am always there 4u guys.....
One words sir i am amazed by your teaching
All the best
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1.Draw projections of a rhombus, ABCD, with AC = 80 mm and BD = 50 mm if:
a. BD is parallel to both HP and VP, and AC is inclined 30º to VP
2.A pentagonal plane rests on VP on one of its corners, inclined 30º to it. The diagonal
through that corner is inclined 30º to HP. Draw its projections, if it lies in the 4th
quadrant.
SIR CAN YOU PLEASE SOLVE THESE TWO QUESTIONS???
It was so precise and clear. Thanks for the explanation.
Hi Zacharia.....
Keep learning man...
All the best.....
Sir really I am benefited by ur videos I am really thankful to you
I learn E.G. here so much more than in my lectures. thanks for your existing sir !
U r going to best tutorial in youtube osm even my professor cant teach like u
over all I use your vedioes ..very interesting and informative ...thank u soo much
Hi Bilal..
I am sure that these videos are helping u learn...
Keep watching and do let your friends know about this channel so that they can also benefit................
sir actually the whole class use your vedioes .. very thankful ..
+Bilal Rasool
Thats great.....
Which college are u from Bilal...?
i am from pakistan .
Sir you are teaching do good that I could not understand in class but here I understood everything
Draw the projections of a circle of 50 mm diameter resting in the H.P. on a point
“A” on the circumference, its plane inclined at 45° to the H.P. and the diameter
AB making 30° angle with the V.P.
@Manas Patnayak...... u r the best!
Engineering Drawing | Engineering Graphics |: ua-cam.com/play/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS.html
Sir can you please explain the difference between the top view of diameter making an angle with vp and diameter making an angle with vp practically?
Sir I can't understand the second case..
how did you do this one...?
Plz explain once sir...
because of you I pass the Eg exam
love you
Sir in this kind of problems we are questioned that
measure the angle of the plane with the H.P. .
Which angle we should measure??
Sir u r awesome ...yr taching style is fabolous
Best channel for eg, 🥰
keep it up sir..........the way you teaches is outstanding
Sir at 4:27 how can we get points 1,2,3,4,5,6 should we have to divide Circle into 8 equal parts to get points 1,2,3,4,5,6 plzz solve this query
Thank you very much sir
Now we are have a good knowledge on this top ,we are very much thankful to you sir
Hi Sai..…
Thanks for appreciating my work…and all the best for your exam
I am sure this channel is helping you learn…You can support my channel by donating and do watch this video: ua-cam.com/video/WfyUEhxhjZU/v-deo.html
Have a Nice day
In 5th problem why are you marking b' in locus of b, instead of directly drawing it with b?
I used shiver when ever I hear about EG , but after watching ur lectures am pretty interested in EG and more life saver for many of the students
Thank you for wonderful videos
And amazing explanation
Sir u have the best teaching skill
You said that the edge which is going to be inclined in the third step is placed perpendicular to line XY in the first step.. No edge type thing is here but we have a line(diameter), can't we coordinate circle in the way that line AB is perpendicular to line XY
Excellent teaching... Super sir
Hi Paramesh....Well Thanks for appreciating my work...
All the best in life
And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401
Small contributions can make a Big Difference
Manas Patnaik No mention sir..But your teaching very nice..Some more videos are upload to us.. Thank you so much sir..
11:38 why we have to consider b1
Thank you, u just saved my first year
Superb teaching and drawing skills
Thanks for your lovely comments Dhananjay....
U r very very very much good and better than our principal sir
THANK YOU FOR ALL VIDEOS. ALL VIDEOS ARE VERY USEFUL.
BUT I GETTING LOTS OF PROBLEM IN THIRD STEP.
Really you work hard for us..I like your hard work and your projections thanks
Ur teaching is very understandable sir and really 👌👌👌
Waww u r great sir..... U learnt me very easiest way of ED😊😊
Really proud of you sir supr teaching. ....
7. A circular lamina of diameter 40 mm rests on one of its circumference point on H.P. the
diameter containing the point inclined 45° to V.P. The surface of the lamina is inclined 40° to
H.P. Draw its projection
sir i have to ask u in case 2 why u have drawn angle of 30 from middle of circle Sir plz reply me thank you
should have keep some margin up the question since we can't' read question when we pause video
Please provide some more basic videos on projection of plane and auxiliary plane
Sir really ap mere eg ke sir bhot accha padhte hai😊jab bhi koy problem hoti hai m open your chennal😆thanks sir👍
Hi Neel.......First of all....Thanks for appreciating my work....
I always focus on giving you guys excellent quality free education....
All the best in life and do let your friends know about this channel on drawing and mechanics so that they can also benefit....
Sir u always asked us to take the line perpendicular to XY which is going to inclined in 3rd step then in this question why did u kept AB parallel to XY, why didn't we took point A at point 5 in fig.
Thankyou
Yes edges which will be inclined in final step has to be kept perpendicular to xy line.....
But this is diameter ok......
Edge is different from a diameter
shows a thin plate
of negligible thickness. It rests on its PQ edge
with its plane perpendicular to V.P. and inclined
40° to the H.P. Draw its projections.
Sir can you plz explain this question.....
Good teaching sir loved it
Thank you so much. Your explanations are superb. Locus and its uses needs a deeper look in my opinion, Request you to consider if you have time.
thank you very much sir these videos are very helpfull for learning e.d in short time
Sir ek questions h sir plsss help nahi ban raha h vo plsss ND bhatt projection of plane exaple no. 12.15
Sir, In earlier videos you said that whichever edge gonna be with any plan (HP or VP) that edge should be perpendicular to xy line in step 1 . But here ab (diameter of circle) is parallel to xy , why ?
Coz A point is in HP so if you try to take AB perpendicular to VP then half of the circle would go below HP
But i think it would have been too late for you 😅
what is the case of circular plane with surface inclined to VP with 2 cases
Superb explanation sir I had learned very well and I have no words to express as it is very helpful and I too had shared with my friends sir and they too got helped from you tutorial sir
“THANKS A LOT SIR”
Keep learning and all the very best
Sir amazing video sir
Very helpful
My god, what an explanation.... Unbelievable, tq so much sir🥰
Thank you sir l was initially confused in both cases but now l am able to solved it. 👍💪
Manas Patnaik sir in second case why do we take the true length of diameter on the 30° line and then cut an arc with top view ab's distance on the straight line from b?
+opposer
The answer to your question lies in the video itself.......And its in a way related to projection of lines as in diameter as a line.....Remember if its top view length is inclined we use beta and when its true length is inclined we use theta.....
Thanks a lot sir..you helped me and my friends a lot..Respect from NITK Surathkal
Hi Vibhu........
I am sure that these videos are helping u learn...
Keep watching and do let your friends know about this channel so that they can also benefit.......
Really well explained Manas sir.
I totally messed up there. Mistakenly I did case 1 whilst I had to do case 2 😞
It happens but i am sure after watching this you will do equally well for both cases.
@@ManasPatnaikofficial Thank you 🙂
At the end of the first question you have the front view and the top view how would you then create a side view (same as front but turned 90 degrees)?
sir... In case 2 of this problem, we are asked to make a true length of a diameter inclined to VP, so have you found out the inclination of the reduced diameter with VP. Sir this can be done as it is done in case 1 right????
You are reason I understood this topic very easily, befor the exam day! Thank you! Deserves a subscribe! 🤗
In this 3 rd step arc is not cutting on the locus line with ab radius and with center a while we try to cut locus line the arc is cutting at point b original position?????
A circle, rotated once, looks like an ellipse. Rotated a 2nd time, it again looks like an ellipse, which we draw using the spline function. Find a method to draw the second ellipse exactly.
I an from BIT Mesra and watching this question amazing explanation🎉
V v v useful
sir why took extra line for top view at 10:50
Some people leave their legacies........Hats off sir..just not make them paid
Thanks for appreciating my work...
All the best...
Teaching is my passion.....And dont worry all the content that i upload can be accessed for free forever.....
Sir the last recreating one of the true length i did understood but I didn't understand why are we taking ab of the top view as radius any reason behind that?
Sir...what is the distance between the cicle in the first position and reference line
sir can you please tell why you have taken the angle inclined to VP below the reference line.
Sir for different planes there is a different method for drawing the third step (edge inclination) how to remember these process