#10. How to Solve an Equation with Two Square Roots

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  • Опубліковано 21 жов 2024
  • #10. How to Solve an Equation with Two Square Roots
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КОМЕНТАРІ • 16

  • @YousefFN
    @YousefFN 4 роки тому +2

    That was awesome thank you taking psat this Saturday October 17th

  • @davidellis1929
    @davidellis1929 4 роки тому +3

    The presence of sqrt(x-6) forces x >= 6. But then 2x+5 >= 17 and its square root exceeds 4, so you can't have any real solutions.

  • @lauralevely3245
    @lauralevely3245 9 місяців тому

    thank you 🙏

  • @alaechoulli6111
    @alaechoulli6111 4 роки тому

    can you please explain to me the factorisation trick

    • @MClilypad
      @MClilypad 4 роки тому +1

      When you expand the brackets you see that the 2 numbers we are looking for add up to -32 and multiply to 220. So we now look what numbers multiply to 220, and then look which of these add up to 32.

    • @alaechoulli6111
      @alaechoulli6111 4 роки тому

      Could this apply to any numbers or there is a condition

    • @MClilypad
      @MClilypad 4 роки тому +1

      @@alaechoulli6111 In general you can always apply it, as long as the quadratic equation has 2 solutions, but you are not guaranteed to always find integers, only if the equation has integer roots.

    • @alaechoulli6111
      @alaechoulli6111 4 роки тому

      @@MClilypad thanks a lot

  • @rontiemens2553
    @rontiemens2553 3 роки тому

    No real solutions, so how do you find the complex solutions?

  • @tiggetty
    @tiggetty 11 місяців тому

    Double 15 second ads.... Gfy

    • @godlymime8047
      @godlymime8047 8 місяців тому

      Oh no 30 seconds for 10 minutes of free content oh the agony 😂

    • @tiggetty
      @tiggetty 8 місяців тому

      If I have to watch ads, its' not free.

    • @godlymime8047
      @godlymime8047 8 місяців тому

      @@tiggetty No, not being free would mean you having to pay for it. This isn't you having to pay for it; it's just you having the attention span of a goldfish lmao.