MIT 2024 Integration BEE Regular Season, Problem 12
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- Опубліковано 27 кві 2024
- We solve a very fascinating problem from the 2024 MIT Integration Bee Regular Season! This was problem 12 in that problem series. We hope you enjoy following along. #mit #calculus #integration #maths #mathematics #recursion #recursive #logarithm
Actually from the quadratic equation, one obtains
x=(1+u-u^2)/u
dx=-1/u^2-1
Which turns into an integral wrt u
That would also work!