Parametric Equations : Differentiation : ExamSolutions

Differentiating parametric equations tutorial.
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[@malakmoataz1293]

I would've never got an A* in my exam if it weren't for your amazing videos! Thank you so much

[@ExamSolutions_Maths]

You're welcome and well done on getting an A*.

[@danleprince7856]

Hi

[@BeenThroughShitLikeAPinky]

​@@danleprince7856😂😂😂

[@ExamSolutions_Maths]

The 2 from the half does not go up to the top. It is 1/2 multiplied by (-3) which gives -3/2.

[@finjosherpa2071]

To get this much of knowlwdge for free, you re like a guardian angel to me.And not only mine,also to the whole A level students of Nepal. Thanks Mr. Stuart

[@ExamSolutions_Maths]

You are more than welcome

[@abyusem2659]

ماشاء الله بارك الله فيك ❤❤

[@addy583]

Thanks man! I like how you can explain this so much better than my actual lecturer in uni

[@ExamSolutions_Maths]

+addy583 No probs. Pleased to help out.

[@مسترعلاءخطَّاب]

Thanks sir, I have learnt too much from your videos
❤

[@ahmedhersi9188]

Y doesnt the two go up since it is the coefficient of t

[@edwinsamuels5420]

thanks this was to the point and extremely useful

[@ExamSolutions_Maths]

@MrLiverwurst As far as I am aware yes. Americans tend to say factor out.

[@AM-xf8mu]

5:11 why is it not -4sint

[@bedigaravinder2848]

thank u
and it was an excellent explaination
i like to watch some more videos regarding maths
because it was easy in understanding ..................................

[@lolzomgz1337]

I'm massively stuck on one question at the moment:
x= (2e^t)-5
y=(8e^-t)+(3e^t)-4
Find the value of t when dy/dx =1
I got dy/de to be: (-8te^-t-1)+(3te^t-1)
and de/dx to be: 1/(2te^t-1)
Putting these together gives me
dy/dx = [(-8te^-t-1)/(2te^t-1)]+[(3te^t-1)/(2te^t-1)]
Ultimately, simplifying this and rearranging for dy/dx =-1 I get
-1 = (-4e^-2t) + (3/2)
By that is apparent ally impossible to solve.
Can anyone help?

[@bedigaravinder2848]

+lolzomgz1337 once try with logarithimic differrentiation if not then u can use parametric

[@kazskx]

Hello:) I am wonderin, when you do the differentiation of -1/2t^3, doesn't it come out with 6t^-4 which also=6/t^4?

[@abyusem2659]

I got 20/20 on my exam thank you you ❤❤

[@ExamSolutions_Maths]

Too complicated to do.

[@tabithambulwa1909]

X=sin2thita y=cos3thita evaluate dy/dx+3/2 Y^1/3

[@stauns7642]

hey man thanks a lot , but how do I know which one divides the other? I really suck at math

[@ByGTee07]

y=2-3t/1+t, x=3+2t/1+t can you help me with this?

[@shen7984]

hello
parametric equations x=f(t),y=(t)
where y is also a differentiable funtion of x
then dy/dx=(dy/dt)/(dx/dt)
what if i can't eliminate the parameter t (to express the parametric curve in terms of x and y) , can y still be treating as a function of x???
for example x=t*exp(t) , y=t*sin(t)
how do you say that y is a function of x [y=h(x)] ?
the term dt/dx be used when t is considered as a function of x,but what if I can't express t in terms of x
The formula can still be used?

[@MilahMee]

for the differentiation of x=3sin(t) why isn't the product rule used? Am I missing something?

[@ExamSolutions_Maths]

+MilahMee Because we are not multiplying two variables together. 3 is a constant.

[@tylorfrancois8838]

u the best bro

[@Zannydude]

it's not spelled with a z as far as I am aware so being pedantic the awnser to your question is no but factorise is definately a word in the oxford dictionary.

[@PO1S0N-1]

you spelt 'answer' and 'definitely' wrong and the z spelling is the American way, so technically it's still correct.

[@goitseone8836]

You are the best!! so in this topic we don't apply product rule?

[@ExamSolutions_Maths]

I did when I found dy/dx. dy/dx = dy/dt x dt/dx = [dy/dt] / [dx/dt]

[@arif_alias2033]

i'm enjoy with this video

[@brianheadley4121]

thanks... nice job mate

[@TheRedGoldfish]

To save time I just do y dot / x dot

[@TheNetkrot]

thanks this was great

[@theshayanproduction]

does the sint/3cost not cancel out to 3tant? or can you not do that?

[@parkourandfreerunning4214]

I haven't watched the whole video yet so idk what part is this but if it's simply just sint/3cost it would be 1/3tant because sint/3cost is the same as saying 1sint/3cost. So if it was 3sint/1cost it would be 3tant. If it was 3sint/3cost it would be tant.
Edit: Oh the part you're talking about, -sint/3cost would be -1/3tant

[@DxFaa22]

You are great ! thanks a ton

[@-scieng-6592]

great vid

[@acanthe3]

It would cancel to (1/3)tant

[@parkourandfreerunning4214]

Would -sint/3cost not cancel to -1/3tant?

[@riyajadhav1911]

thank you sir👍

[@ExamSolutions_Maths]

Appreciated - thanks