I am trying to study physics for next year since I'm stuck at home, and these videos are really helpful. I am taking notes and you explain really well and use pictures and diagrams (so they get suck in my head). Thank you!! : )
Wow! Such a hard worker. You might also enjoy the Lesson Notes for each video. They are linked to in the Description section. Wishing you much success in the upcoming school year!
ty for these videos have a nephew goin into physics and he told me about your videos they are so hes trig and pys insightfull , im by no means smart , but i understand ididot can understand
Learned the same topic in a very new & untold manner ❤️. Here, I've completely enjoyed just only manner by which you presented those shits which I read almost 100 times. But enjoyed first time.
In the first example (at 2:10) it says that the acceleration is 8 ms/s, but (according to me) the data in the table does not agree with this, as in the first second it moved only 4 m. If this were a case of non uniform acceleration, wouldn't the final distance be 120 m (8+16+24+32+40)? Would you mind to explain where I am wrong? Many thanks.
I'm not really sure where you got your numbers from. For instance I don't know where the original 8 came from. Further you can't just add a bunch of instantaneous velocities up (which it appears you are doing) and presume that the sum is the final distance. There's no such rule for that. You can use the average velocity during a short time period to calculate the distances traveled during that time period and then sum all those distances up over the course of time. For instance, 4+12+20+28+36 = 100 using 1 second time periods.
@@PhysicsclassroomVideos The original 8 comes from the statement that appears from 2:02 onwards: "A car accelerates at 8.0 m/s/s for 5.0 seconds." The numbers I provided are my assumption for the case of that statement, but let's forget that. I guess my question is: how a car travelling with an acceleration of 8 m/s/s have a displacement of 4 m after 1 second. I think all the rest is clear to me. Many thanks for taking the time to reply. I have been consulting The Physics Room for over a year and I think it is the best resource online. Many thanks to all the collaborators for making it possible!
So if an object accelerates at 8 m/s/s starting from rest, it will have a speed of 8 m/s at the end of the first second. During that first second, it will have averaged a speed of 4 m/s during that 1 second of time. If an object averages 4 m/s for 1 second, it will have a distance traveled of d = vave*t = 4 m/s * 1 s = 4 meters. One must always be cautious of taking a speed at an instant (8 m/s at 1.0 seconds) and using it to find the distance traveled over a span of time (from 0 s to 1 s). To related d to a v, you must either have a constant v or an average v or a kinematic equation.
Hi👋 thankyou very much 🙏🙏😇I have seen too much videos but I understand none of them your explanation is awesome 😍It helped me lot😭Can you please give me your website for chemistry and biology class 😊 Thanks again
Sorry it wasn't helpful. We're just getting started with making videos so some details would help us. What made it "not helpful." ... for instance, "it was too long" or "the difficulty level was too much for me" or "I don't like being made to watch videos by my teacher" or "Mr. H makes me fall asleep" or ... etc. Anything helps. We'd love more feedback.
![Uniformly Accelerated Motion [IB Physics SL/HL]](/img/n.gif)
Sir, you are a lifesaver. I took Physics online... never will I do that again and you have filled the role of my teacher. Many thanks!!!
I am trying to study physics for next year since I'm stuck at home, and these videos are really helpful. I am taking notes and you explain really well and use pictures and diagrams (so they get suck in my head). Thank you!! : )
Wow! Such a hard worker. You might also enjoy the Lesson Notes for each video. They are linked to in the Description section.
Wishing you much success in the upcoming school year!
ty for these videos have a nephew goin into physics and he told me about your videos they are so hes trig and pys insightfull , im by no means smart , but i understand ididot can understand
I'm glad your nephew told you about the videos.
my favorite channel for physics
You made my day. Thanks for your kind words.
Sir, please add all the units of class 11th and 12th to ur physics tutorial section and also to video section especially alternating cur
Eventually I'll have them all done.
Loved it :) Thank you
Thank you.
Thank you so much!
Please I wish my physics teacher taught like you. Great video.
Thanks for your kind words.
The best of the best
Learned the same topic in a very new & untold manner ❤️. Here, I've completely enjoyed just only manner by which you presented those shits which I read almost 100 times. But enjoyed first time.
Superb
Very good video.... saved my life...waaaaaaaaaaay better than crah course
Thank you.
Thank You!
Youre welcome.
Excellent 👍 God bless you 😇
This is an awesome explanation. Thanks!
Thank you for your kind words.
In the first example (at 2:10) it says that the acceleration is 8 ms/s, but (according to me) the data in the table does not agree with this, as in the first second it moved only 4 m. If this were a case of non uniform acceleration, wouldn't the final distance be 120 m (8+16+24+32+40)? Would you mind to explain where I am wrong? Many thanks.
I'm not really sure where you got your numbers from. For instance I don't know where the original 8 came from. Further you can't just add a bunch of instantaneous velocities up (which it appears you are doing) and presume that the sum is the final distance. There's no such rule for that. You can use the average velocity during a short time period to calculate the distances traveled during that time period and then sum all those distances up over the course of time. For instance,
4+12+20+28+36 = 100 using 1 second time periods.
@@PhysicsclassroomVideos The original 8 comes from the statement that appears from 2:02 onwards: "A car accelerates at 8.0 m/s/s for 5.0 seconds." The numbers I provided are my assumption for the case of that statement, but let's forget that. I guess my question is: how a car travelling with an acceleration of 8 m/s/s have a displacement of 4 m after 1 second. I think all the rest is clear to me. Many thanks for taking the time to reply.
I have been consulting The Physics Room for over a year and I think it is the best resource online. Many thanks to all the collaborators for making it possible!
So if an object accelerates at 8 m/s/s starting from rest, it will have a speed of 8 m/s at the end of the first second. During that first second, it will have averaged a speed of 4 m/s during that 1 second of time. If an object averages 4 m/s for 1 second, it will have a distance traveled of d = vave*t = 4 m/s * 1 s = 4 meters.
One must always be cautious of taking a speed at an instant (8 m/s at 1.0 seconds) and using it to find the distance traveled over a span of time (from 0 s to 1 s). To related d to a v, you must either have a constant v or an average v or a kinematic equation.
@@PhysicsclassroomVideos many thanks! All understood.
thank you and love u
Very helpful
Hi👋 thankyou very much 🙏🙏😇I have seen too much videos but I understand none of them your explanation is awesome 😍It helped me lot😭Can you please give me your website for chemistry and biology class 😊 Thanks again
Don't have a biology site. Have very little in Chemistry. The Chemistry is on The Physics Classroom site. See Concept Builders.
thank you !!!! so much !
You're welcome. Hope you can find some more helpful vids in our collection.
I love your video
Thanks.
Is it bad that I'm almost 40 and watching this to learn? My middle school science teachers would facepalm so hard...
Not bad at all.
not helpful
Sorry it wasn't helpful. We're just getting started with making videos so some details would help us. What made it "not helpful." ... for instance, "it was too long" or "the difficulty level was too much for me" or "I don't like being made to watch videos by my teacher" or "Mr. H makes me fall asleep" or ... etc. Anything helps. We'd love more feedback.
far more than helpful !!!