10.09 Stereochemistry of the Wittig Reaction

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  • Опубліковано 8 січ 2025

КОМЕНТАРІ • 7

  • @Puffbrause123
    @Puffbrause123 3 роки тому

    What a clear explanation. Thank you very much

  • @nourhanmohamed5796
    @nourhanmohamed5796 17 днів тому

    ❤❤❤❤ very simple

  • @IntroChem
    @IntroChem 5 років тому +3

    What about the size of the triphenyl phosphonium group? Wouldn't if often be larger than the R1 group?

    • @mevansthechemist
      @mevansthechemist  5 років тому +4

      This is certainly true, and it's something I didn't consider until after making the video. However, note that even if the triphenyl phosphonium group is anti to R2 in the transition state-probably more reasonable than what I drew in many cases-this would place R1 and R2 gauche, and less rotation would be needed for P-O bonding. As a result, R1 and R2 would still end up cis! Only the transition state in which hydrogen is anti to R2 leads to the trans product.

    • @mevansthechemist
      @mevansthechemist  5 років тому +1

      Great question, by the way!

    • @dlvivlviv
      @dlvivlviv 4 роки тому +1

      @@mevansthechemist I have a question, why do we assume that the phosphorus ylide is in R conformation? S conformation would be energetically preferred, the R1 group would end up in gauche position only towards R2.

  • @PrakashPulse4573
    @PrakashPulse4573 Рік тому

    Thank you very much