That was extremely helpful, my Chem teacher asked us to get the % error on a density lab we will be doing, but I had never heard the term before. You saved a life.
You’ve been very clear through your explanation especially upon providing a comparison; the comments connected to something being measured is 17 ft vs. 500 ft. Great clarity.
Hey, thanks for making this video. I was quite a bit confused of what my highschool teacher was teaching me, but now I understand a little bit more better. Thanks again!
@JesusLover077 i don't know, i guess i just wasn't in the mood. i did two out of three. so look at how i solved the first and the third errors, and you can figure out how to solve for the second one, right?
Love u!!thank you so much I learned days I was te listening in class and thanks to my friend I’m passing chemistry and I wanna help so I’m teaching myself sun
Thank u u make chemisty easier. My teacher take 1 hour of lecture but u took only 10 time . Make more chemisty video cuz it does help us alot to understand better. Thank u .
Oh Thought this was gonna explain standard deviation as well. I thought that for the problem to be accurate it had to be on a range of 10% of the actual value.
Excuse me but I need to know what exactly to do if I have the percent error and a question asks me to find the missing unit. For example you record a mass of 24.3g and the broken balance reads 30.0%? How do we find the missing measurement?
thank you for explaining what it is and why its useful rather than just going over the math. I always do better feeling like i know why im calculating something
@TiteNYC if u dont have the accepted value, then find the precision of your measurement. % uncertainty of measurement = (uncertainty of reading/reading recorded) x 100% uncertainty of reading depends on the precision of your instrument used
Dear, Can u please tell me how to calculate % error when actual value is negative lets say -100 and experimental value is positive like +50 ? please explain, do we still need ignore minus???
Yes, the formula for percent error is: (measured-accepted)/accepted value •100. This results in the number sometimes being positive and negative. Since we are considering the size of the error, you have ignore the + or - signs
How do you tell if a number is more accurate than two other numbers in a group based on the numbers themselves; not based on an actual value? Example: Which value is more accurate? a.) 810.13 b.) 7.132 C.) 60.1
Okay I get percent error and we learned it in class today but can you please tell me how to find the accepted value when you’re given the percent value and our value to find the accepted value
We got told (and i may just be wrong if i am forgeting something but i think i am not) that random uncertianty is calculated by talking the biggest recorded value and talking away the smallest value and dividing it by the number of values we recorded
If you're doing a lab and your values have uncertainties, do you put an uncertainty on your percentage error? It seems really strange to do so, but I'm not sure. :/
ok but how do i get it with multiple mesured into a single error calculation that is what my teacher wants is how to turn 3 triles to get a single error percentage
Good presentation! But! The use of percent sign is a bit ambiguous. You multiply the error by 100 to get the percent error, not by 100 %. Because 100 % would be just 1. So 3.5/500.0 would be 0.007 and you multiply that by 100/100, which is 1, and you still get only 0.007. That's 7/1000. To write it in terms of 100 (per cent) you have to divide numerator and denominator by 10, and you get 0.7/100. It's only when you write out the percent sign that you get 0.7 %. You have to write out the % sign to keep the same value. By dimensional analysis, the feet units cancel out, and percent remains. So technically, it is correct. But to make it less ambiguous I would probably put it in parentheses and let % sign sit outside of the right parenthesis, and I would not read it out as "times 100 percent", I would rather say "times 100". Either way works, but I find it less confusing or less ambiguous this way. People are hardly taught to view % as a unit of measurement, so they may not understand what's going on.
+Samir Gunic It is correct to multiply by 100%, not 100. I believe it is important to teach that the % is just another unit of measurement and that 100% is just another conversion factor like 1000 mg/1 g, which equals 1. Why teach something that is wrong because they didn't learn it correctly the first time? The only comment I would make is that I would like to see a leading zero in 0.7%, not .7%
That was extremely helpful, my Chem teacher asked us to get the % error on a density lab we will be doing, but I had never heard the term before. You saved a life.
I’m doing this right now!
Same lol
Literally me right now
Who else is binging these videos because they got a test of quiz tomorrow
midterms
Ye
Me
Me
@@owenthompson6558 goodluck homie. I took my quiz on that stuff 2 years ago. now I’m a senior. Wish I could go back :(
this dude is a hero. he saved me from my chemistry teacher
Seriously, my chemistry teacher gave us both equations and told us to solve so I literally didn’t understand it until this 😂
Please never stop making videos. You have a gift of explaining things so clearly. You're a life saver.
You actually just get straight to the point. That's why I love online videos.
Thanks!
U are saving my life
mee too
you saved my life
You’ve been very clear through your explanation especially upon providing a comparison; the comments connected to something being measured is 17 ft vs. 500 ft. Great clarity.
Thank you man! Your effective teaching ability more than makes up for my inability to concentrate very well! YOU'RE AWESOME!!!!!
Hey, thanks for making this video. I was quite a bit confused of what my highschool teacher was teaching me, but now I understand a little bit more better. Thanks again!
I love your videos. you make complex things so simple. Please make one on relative average deviation!
This is so easy and comprehensive. Thanks dude!
@masterchief9064 yes it is
this is just wonderful, youre a natural teacher. thank you so much
Thank you for the video! It made things incredibly clear.
THANK YOU SOO MUCH, I REALLY APPRECIATE THIS. Yes, I did not understand it when my teacher ATTEMPTED to teach it to me last year.
@lovingnepal you cannot calculate error or percent error unless you know the actual value.
Thank You so much Sir. I'm so grateful for these videos. YOU literally SAVED My LIFE.
Watching this 7 yrs later haha
But found it really really helpful.
Thank you.
you will be my savior through this semester.
Thank you so much! I was asked to calculate this not even being told how, so this makes more sense.
@JesusLover077 i don't know, i guess i just wasn't in the mood. i did two out of three. so look at how i solved the first and the third errors, and you can figure out how to solve for the second one, right?
Love u!!thank you so much I learned days I was te listening in class and thanks to my friend I’m passing chemistry and I wanna help so I’m teaching myself sun
really a good job i just understand every thing for chemistry from you thanks for help
@TiteNYC you cannot calculate error or percent error unless you know the accepted value.
What does the "actual value" mean? Thanks for help!
I just love the way u explain😊
Really helpful and so easy to understand!
when i have 3 trials, am i to get the average of all the error of each trials for me to get the experimental value or am I to add all of them?
I have aspergers so things like this are a bit difficult but you explained it better.
Thank you.
This helps so much thank you!
sir pls reply what does this question mean n how to solve it: find the relative error of the number 8.6 if both of its digits r correct
I feel so stupid that I didn’t get if before this! 😂 You just saved my test grade. Thank you! 🙏
Wow you really helped me out thanks!
nobody:
Americans: ft, F, Oz, gallons
@@slayerryan Its funny making fun of your dumbass measuring system invented by a drunk guy in the 1800s
lizard exactly idk why we had to adopt this dumb system
You forgot the funny
OMGGG Hanamichi sakuragi. I love your pfp
Thank u u make chemisty easier. My teacher take 1 hour of lecture but u took only 10 time . Make more chemisty video cuz it does help us alot to understand better. Thank u .
What will be the “actual” value if the test have triplicate assay? Is it the average?
thanks a lot for this video it's very useful
👍👍👍👍👍👍👍👍👍👍
Great video. Thanks a lot!
great....simple...but effective....thanks a
lot
u have earned my subscribe
can you do a video about the percent yield?
Oh Thought this was gonna explain standard deviation as well. I thought that for the problem to be accurate it had to be on a range of 10% of the actual value.
Thanks this was a big help!!!!!!!
How do we express percentage error resulting from measurements with different accuracy ?
Excuse me but I need to know what exactly to do if I have the percent error and a question asks me to find the missing unit. For example you record a mass of 24.3g and the broken balance reads 30.0%? How do we find the missing measurement?
What if the actual value is not given then we have to first find it by taking the means of all measured values
Is actual and measured value the same as Accepted and Experimental Value?
I wish u were my Lecturer... You the best
u are a man Tyler thnks
THANK YOU SIR U HELP ALOT!
something tells me that's not typed correctly...
thanks, I have to say you are actual scientist because you share what you know
@Aspen70000000000 actual = accepted; measured = experimental
thank you for explaining what it is and why its useful rather than just going over the math. I always do better feeling like i know why im calculating something
How to calculate theoretical value for Complexometric titration
Thanks Tyler. God bless.
thanks helped a lot
U are the best 💯
How did you get the actual value?
So when is the percentage error large enough to “worry about it”? When it becomes a whole number?
Do you multiply it by 100 or 100% because when i plug it into my calculator it gives me two different answers
u make it so simple
THANK YOU mate
i legit love you man xD
@TiteNYC if u dont have the accepted value, then find the precision of your measurement.
% uncertainty of measurement = (uncertainty of reading/reading recorded) x 100%
uncertainty of reading depends on the precision of your instrument used
i dont think im getting ur website can u put a link plz
Thanks For Saving My Life Sir
Dear, Can u please tell me how to calculate % error when actual value is negative lets say -100 and experimental value is positive like +50 ? please explain, do we still need ignore minus???
Yep. Negative % error is impossible. You cant be higher than the actual. Because the highest is the actual. Make sense?
Take the absolute value
Yes, the formula for percent error is: (measured-accepted)/accepted value •100. This results in the number sometimes being positive and negative. Since we are considering the size of the error, you have ignore the + or - signs
So is the actual always 500.0?
You can also calculate percent error by taking the absolute value of the estimated value and true value , dividing true value, multiplying 100.
yes you are right baby
Very good explanation
How do you tell if a number is more accurate than two other numbers in a group based on the numbers themselves; not based on an actual value?
Example: Which value is more accurate?
a.) 810.13 b.) 7.132 C.) 60.1
thanks a million!
Why are you not my Chem teacher? :( You explain so perfectly.
What's mean absolute error and relative error?
10 years later this is still helpful
Amazing job cuh you know how to teach
What happens when i don't know the Actual value its for my physics assignment i dont know what i am doing
look it up
i love this man
Okay I get percent error and we learned it in class today but can you please tell me how to find the accepted value when you’re given the percent value and our value to find the accepted value
A way to calculate another estimate for the percent of error is by subtracting the total by the new amount given and completing the percent equation.
We got told (and i may just be wrong if i am forgeting something but i think i am not) that random uncertianty is calculated by talking the biggest recorded value and talking away the smallest value and dividing it by the number of values we recorded
thank you so much
but what if we were not given the actual value...can we divide by the average of the values.......?
I was also wondering about that problem
What is the actual value
If you're doing a lab and your values have uncertainties, do you put an uncertainty on your percentage error? It seems really strange to do so, but I'm not sure. :/
Excellent
Thank you so much
Can u be my teacher
ok but how do i get it with multiple mesured into a single error calculation that is what my teacher wants is how to turn 3 triles to get a single error percentage
Is the percent error the same as the relative error? Because i watched another video and the dude did relative error by doing the same thing
please come back.
Good presentation! But! The use of percent sign is a bit ambiguous. You multiply the error by 100 to get the percent error, not by 100 %. Because 100 % would be just 1. So 3.5/500.0 would be 0.007 and you multiply that by 100/100, which is 1, and you still get only 0.007. That's 7/1000. To write it in terms of 100 (per cent) you have to divide numerator and denominator by 10, and you get 0.7/100. It's only when you write out the percent sign that you get 0.7 %. You have to write out the % sign to keep the same value.
By dimensional analysis, the feet units cancel out, and percent remains. So technically, it is correct. But to make it less ambiguous I would probably put it in parentheses and let % sign sit outside of the right parenthesis, and I would not read it out as "times 100 percent", I would rather say "times 100". Either way works, but I find it less confusing or less ambiguous this way. People are hardly taught to view % as a unit of measurement, so they may not understand what's going on.
+Samir Gunic It is correct to multiply by 100%, not 100. I believe it is important to teach that the % is just another unit of measurement and that 100% is just another conversion factor like 1000 mg/1 g, which equals 1. Why teach something that is wrong because they didn't learn it correctly the first time? The only comment I would make is that I would like to see a leading zero in 0.7%, not .7%
big thanks
Thanks maaan
very nice
If u multiply by 100% u get 1.0
wait so how do i find actual value?
Why didn't you solve for the the second error: +2.8 ft ?
Please make a vedio of absolute error. . relative error. And percentage error
@tdewitt451 Yes, thank you.