An Application of Cross Products: Torque

This video explains how to solve a problem involving torque using cross products as well as another method.
mathispower4u.y...

[@alexandgarciacalle]

In min 5:21, isn't it supposed to be negative torque? Since the determinate signs go ---> T= (0)-(0)+(-37.6k)=-37.6k. Thank you

[@powerllesss2672]

He said take the sum of the blue products subtract the green products which results in T= (0) - (-37.6k)= 37.6k

[@luigianchondo7241]

Or I did way simpler than what he did
180°-110°=70°
So 40lbs*1ft*sin(70°) = 37.6 lb-ft

[@maskd3515]

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[@everythingispossible5431]

i wanted this

[@theBasilDestiny]

megnitude

[@sadiaaa1373]

Mengitu