@Pat's Perovskites - Hi Patrick, for the phase diagram at 11:47, I found the following additional phases for points c & d: Point C is in the triangle with vertices Al2O3, ZrO2, ZrTiO4. It is also in the triangle with vertices ZrO2, TiO2, Al2TiO5. Similarly, point D is also in the triangle with vertices Al2O3, ZrO2 & ZrTiO4. Are these also valid answers? If not then why not? Thank you. For your last question, I proceeded as follows: The compound with the closest composition to the target Y2Ba2Cu4O9 is compound 123 (YBa2Cu4O7), subtracting 123 from the target gives BaCu3O4, which is BaO + 3CuO. So our target lies inside the triangle with vertices 123, BaO, CuO; which are also the phases present. So to make the target, we combine 1 mole each of 123 & BaO and 3 of CuO. Is this answer valid?
The only video that made me understand the tertiary diagrams thanks alot
Thanks a lot! You made it very clear and simple that anyone can understand!
So good, answered questions that were not clear from my class.
Thank you so much. Beautiful explanation.
@Pat's Perovskites - Hi Patrick, for the phase diagram at 11:47, I found the following additional phases for points c & d: Point C is in the triangle with vertices Al2O3, ZrO2, ZrTiO4. It is also in the triangle with vertices ZrO2, TiO2, Al2TiO5. Similarly, point D is also in the triangle with vertices Al2O3, ZrO2 & ZrTiO4. Are these also valid answers? If not then why not? Thank you. For your last question, I proceeded as follows: The compound with the closest composition to the target Y2Ba2Cu4O9 is compound 123 (YBa2Cu4O7), subtracting 123 from the target gives BaCu3O4, which is BaO + 3CuO. So our target lies inside the triangle with vertices 123, BaO, CuO; which are also the phases present. So to make the target, we combine 1 mole each of 123 & BaO and 3 of CuO. Is this answer valid?
Simple and understandable. Thank you so much.
thank you sir
how to get the simulink of this diagram
helpful， thx！