Assume the voltage after Z1 is V. I1 =(Vi - V)/Z1-----(eq 1) and I2 = (V - Vo)/Z3------(eq 2). we can write V = Z2(I1-I2)-----(eq 3) and Vo = Z4*I2-----(eq 4) Substitute eq 3 in eq 1 && eq 3, 4 in eq 2. You should get the answer C with Z2 and Z3 interhanged
Horizontal branch Z3 is Z2 & Vertical branch Z2 is Z3. Make this correction to get answer. Answer Hint :- KVL eqns in both loops & I2(s) eqn from S.G.F
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∆ = 1 - (sum of all individual loop gains) + (sum of gain products of all possible combinations of two non touching loops) - (sum of gain products of all possible combinations of three non touching loops) +...... +((-1/sCR1)×(-sL/R2) = +sL/sCR1R2 = +L/CR1R2
4:50 i think P1 should be L/R1*R2*C
ha bhai ,ye sahi h
Option (B) is correct
Solved problem? More like "Super wisdom!" Thanks again for such an amazing series.
Highly Helpful. Thanks
Sir 5:10. Where did the sl and sc go for the forward path?
Assume the voltage after Z1 is V.
I1 =(Vi - V)/Z1-----(eq 1) and I2 = (V - Vo)/Z3------(eq 2). we can write V = Z2(I1-I2)-----(eq 3) and Vo = Z4*I2-----(eq 4)
Substitute eq 3 in eq 1 && eq 3, 4 in eq 2. You should get the answer C with Z2 and Z3 interhanged
Can u share solution
Sir plz provide solutions of homework problems
Nice tutorial 👌
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Horizontal branch Z3 is Z2 & Vertical branch Z2 is Z3.
Make this correction to get answer.
Answer Hint :- KVL eqns in both loops & I2(s) eqn from S.G.F
5:08 where did L go?
Sir please upload the complete playlist of this subject. I am following your complete courses of digital and network theory. And i want to complete all the electronics subject from your channel only. If course is paid also i am ready so Please inform if neso academy has a paid platform where all the courses are available. If you have a web or app where all course are available i am ready to access the paid course too. 😍😢
Sir,
Please upload the solution.
I can't solve your homework problem.
I'm confused.
Please sir.
Can this be resolved using voltage divider rule?
thank youuuuuu
H=Z2/(Z1+Z2)
G2=Z2/(Z2+Z3+Z4)
Using voltage divider I had the same for the transfer function except mine was without the R1 in the denominator 😢
@nesoacademy what happened to the big loop ? Formed by adding the 3 small loops? Is it not a loop?
A loop only passes each node once except the start/end
Sir 7.51 delta value will be (1/R1Sc+1/R2Sc+SL/R2-SL/ScR1R2)
But your are putting +SL/ScR1R2
How sir?
∆ = 1 - (sum of all individual loop gains) + (sum of gain products of all possible combinations of two non touching loops) - (sum of gain products of all possible combinations of three non touching loops) +......
+((-1/sCR1)×(-sL/R2) = +sL/sCR1R2 = +L/CR1R2
Option C would be correct if Z2 and Z3 get interchange
How did you solve it? Can you tell plz?...
I think the position of z3 and z2 are flipped in the question. I was getting wrong answer bcz of it. Please correct it.
How to solve it can you tell plz...
This is the complex system or not