Modelling of mechanical system in control system problems

[@greekgaming3806]

hey thanks buddy...l great explanation failed 4 times this subject but got confidence
i appreciate ur work

[@SakshiSingh-de9of]

Perfect explanation. Saved me hours.😊

[@NaveenReddy-zk7of]

TO PASS IN JNTU UR VIDEOS IS MANDATORY ❤

[@ShaikFaizan-ht4ge]

Hi bro miku exams unnaya

[@NaveenReddy-zk7of]

HOO LAST YEAR E PASS AYA BRO CS​@@ShaikFaizan-ht4ge

[@vamsidwibhashyam4454]

Superb explanation sir.. Thank you so much

[@smartEngineerShinton]

Welcome🤗 and do share to your class group

[@masterrasul9058]

Well explained thank you so much♥️

[@306namrta]

Well explained thankyou sir 🍀

[@jayanthis1505]

Very good morning sir.I am very glad to see your videos. Sir a kind help.I beg up please recommend the text book in which these problems are available. Many of us are suffering without good books.Please suggest the book sir.Thank you

[@smartEngineerShinton]

Control system engineering by Nagoor kani

[@sal_diaz5964]

Perfect Explanation keepitup

[@Cookie_handler]

this is gem!!!!!

[@vikramgogoi3621]

What do you mean by opposing force due to mass? Do you mean friction?

[@ViratKohli_545]

Sir want immediately reply, transfer function is output/input na sir. Then in problem it is f(S)/X1(S).

[@blakurls]

Watch this 20:14

[@mukkudapallisuryachandra6211]

Super explanation tqqq brother

[@navaneethdesai]

Sir why do you treat F(s) as constant , while solving the equations? It's varying with time '[f(t)]'......and with frequency [F(s)]
If it is a variable then there will be three variables right sir?

[@navaneethdesai]

Sir, please reply to this.....

[@navaneethdesai]

Sir can you please answer this....

[@anushambhat3147]

Thanku so much sir..that was very helpful

[@ravi-321]

Thanks Bhai appreciate your work I like it

[@ArunAllapur-q3m]

Thank you sir ❤

[@emmanuelofori7898]

Superb!!!

[@mecrajib]

Thank you brother. Learned it.

[@manfredbogner9799]

Very good

[@navaneethdesai]

Can we solve the equations using Cramer's?

[@vamsigameingzone9967]

Tq sir ❤❤

[@mecrajib]

Thank you

[@bobosentsima9310]

would please explain to me why you cross-multiplied but you ddnt bring[BS+K]^2 to the denominator?
and even so we would be having the same value at the numerator and denominator therefore they'd cancel each other out

[@alexanderchosenokon4492]

you can find the LCM instead of cross-multiplying for better understanding. I hope this helps.

[@KavitaKumari-if2mj]

Thank you so much sir

[@ajayitsme3903]

Exlent

[@vamsigameingzone9967]

❤

[@GebreTekleweyni]

well

[@ViratKohli_545]

Output will be force na sir ?

[@abhishekrs2647]

No cos we apply force....so force is given as input...and the displacement is the result of input...so displacement is the output

[@artisybeatssa]

Uyindoda nkabi, waishaya lento

[@yoimtv1945]

20:13 TranSfErFuNcTIoN

[@gle6354]

Thank you

[@devika015dasari8]

thank you so much sir