Finding Equivalent Resistance

[@sanjitabiswas804]

Better than teaching vids 50 mins of vedio with basic scrap.
This was effective

[@quinncorrigan7939]

someone make this man head of the School system for this! been looking for answers for hours!!! by the end of the video I could pause it and solve them all on my own.

[@owendoge23]

We let bro cook and he cooked us a whole thanksgiving dinner. That was fire.

[@hasaniqbal233]

I never comment on teaching videos but my god this was so good, you made like a week worth of class into ~10 mins. I love your teaching style too, none of that "hey guys its x here, today we're gonna learn....", very straight forward and simple. Thanks so much omg

[@DamienGolding]

1 year of electronics summed up in under 9 mins, thanks.

[@leomrex]

better than my physic teacher thank u!!!!

[@ruatachhangte]

This video is very helpful. You didn't go too fast or too slow and you showed the basics at the start which makes understanding this a lot easier. Good work!

[@oluwatosinogunjobi6264]

THANK YOU!!! I WAS ON THE VERGE OF CRYING BUT I GET IT NOW

[@TheADHDFarmer]

best way to quickly and easily prepare myself for my test next week! Thanks sooo much!!!

[@gopinaths5490]

Very much thanx sir.
Now i am very much clear about this topic.
Thanx a lot sir

[@subi3351]

Thank you now I am clear in solving the problems in circuit analysis😊😊

[@benjaminangel638]

Very good video, easy to understand. Easier to follow than many teachers I have experienced.

[@johanvanderwesthuizen9834]

Great info in the beginning and very simple explanation, almost "a circuit for dummies"!
Thanx!!

[@trentonandrews8314]

This was easier to understand than 2 weeks of resistors in my phys106 class!

[@anas0502299]

Better than my electronic circuits teacher .. I would recommend you to my university

[@amirulhakimi1913]

Thank you bro, your explanation makes me understand clearly

[@chessmagicianschannel6373]

thank u very much for this video. It is very helpful, simple and easily understandable.

[@jirehag5140]

You saved me on deadline day. Thank you.

[@emoster7195]

thanks muchly, never had a proper physics class in highschool so this is very helpful.

[@fahimainfark3797]

Great explanation 👍🔥

[@nischay4760]

Thanks! Please make a video on Wheatstone Bridge too!

[@janmarttenedora6829]

Very good video, well explained and simple. Thank you!

[@dwaipayandattaroy9801]

So you mean the pattern is first do parallel pair, then series pair, then parallen and then series..., you are a okay good teacher

[@xmen987gaming2]

thanks bro understood it clearly and never gonna forget
and yeah better than my physics teacher

[@deepanjarlekar8331]

THANK YOU FOR THIS CLEARED ALL MY DOUTS REGARDING SERIES AND PARALLEL

[@ENGRTUTOR]

See video on" Finding Equivalent Resistance of a complex network using nodal analysis"

[@hanexen]

U made it easy to understand it's just flawless thank you very much 😊😊

[@induprakash2324]

Loved it😍🥰😍🔥🔥

[@RafaSyed]

at 6:57 why did you add 4+4 rather then doing 4+9 in series? then why cant you add result in parallel with the 4 on the rightmost?

[@RidwanurRahmanextreme]

Thank you very much for making my brain some bit of free from junks.

[@factsveritas]

The last example simply has 3 resistors in parallel at the end, so those can be simplified in one pass instead of two:
(1/R) = (1/18) + (1/9) + (1/6) ==> (1/R) = (6/18) ==> R = 3.

[@harshsahu3734]

absolutely great video

[@ikhlazxoxo2291]

For the parallel circuit is it still correct if your product is a decimal like 2.7 ohm or something like that

[@brandonharris305]

Ikhlaz xoxo yes as long as the other that is in series or parallel adds up to be the total resistance

[@manasbora3785]

Awesome Bro Nailed It..... Good Explanation....

[@abdullahbukhari1469]

Great Video one for the engineers

[@ech_eff]

*You saved my life! Thank you*

[@faisalsaleem21]

Thank you sir. Especially with the parallel resistors.

[@camtonyray666]

I can understand much clearer now, thank you :)

[@rahebalmouaamen3030]

you saved my life, thank you.

[@dhullasrinu5543]

Superb sir

[@kammarisankaraiah4277]

Good explained

[@________4423]

You're a good man, thank you.

[@ProToolsAvidSchool]

Very Well best explained!!!! Amazing!!!!

[@rawr6796]

thanks for the video! it was very helpful

[@vickabingo7005]

i have problem of my ultrasound Siemens all circuit work properly except but fan not working

[@lqvetaehyung4248]

Very well explained! Thanks! :)

[@saikrishnadouluri4433]

Better than my phy sir thank you sir

[@gauravashre6137]

Clearly Explained :) Thanks.

[@Mikers629]

Thank you, it was very clear and helpful

[@hcinterviews9820]

vedio proved to be helpful Ty sir

[@frb6gw]

Clear, and helpful. Thanks much!

[@allrounder2454]

Sir a big salute to u

[@GadolElohai]

What program is this?

[@MrNutiu]

if you have voltage/current sources is it ok to set them to zero?

[@ashwingautam8514]

thanks man keep the good work up!

[@megha6718]

How do you group those? Please explain that first.

[@tmxyz0]

What techniques would you use to find the equivalent resistance of a circuit with no parallel or series resistors?

[@JKLProject]

Very well said and explained!

[@Drawingsofmadhav]

Wow excellent video.it helped me a lot

[@v.anjireddyreddy6353]

Super explanation

[@Arnob127]

Epic explanation. Thanks a lot

[@NghiaTran-Smol]

i had a question, in this circuit,i thick it have two situation. First situation just like you did. Other situation is that resistor 6 paralel 9 paralel 18, so the circuit is 8 + ( 6 // 9 // 18 ). Sorry if i have mistake somewhere

[@tanaymishra1723]

very good examples are given,thank u !!!!!

[@ceroy_ak]

Superb

[@Doctorshahvlogs]

God bless you!

[@jayshreejanmanchi7902]

thank u so much :-) helped a lot

[@IrfanAli-mg9gf]

Thanx...one of the best videos on resistance...

[@p.rsujitha9160]

Tq super please some more examples

[@abhisheksachdeva9397]

Great video. Thanks

[@dhairyshrivastava988]

Why at the end parallel resistance was not taken out in ex 1

[@ENGRTUTOR]

IT was - the two 6 ohm resistors in parallel gave an equivalent of 3 ohm at the 4m4s mark ua-cam.com/video/fOJn1C125JI/v-deo.htmlm4s

[@AnilKumar-rf6to]

Very simple u understand.
Thanks

[@vickabingo7005]

good lecture

[@herbertsmith9950]

i feel like these are always way more simple than my homework

[@mazenarafa23]

Thank u very much your video helped me

[@subzero5853]

amazing video, thank you!

[@Adrian-cz2ob]

A little shortcut:
Whenever you are going to find the equivalent resistance of two resistors in parallel, whose values are exactly the same, the result is half of the value of the two resistors.
Ex: Req= (6)(6)/6+6 = 3Ω
to show you that it is the same case with every value,
Ex2: Req= (3,000)(3,000)/3,000+3,000= 1,500Ω

[@vivechanasen4519]

thank you so much! Very helpful

[@sarah_belightinthedarkness]

Thank you for the help!

[@prashantbansfore9588]

great video

[@navinsandiya3765]

Simple and easy.... thanks

[@tamkeen2011]

Do u have tutoring. I would like tutor tha ks

[@mahnoor2061]

Can somone tell why did he write 1 over Rt and all for the second circuit?

[@ENGRTUTOR]

Parallel Resistors: the reciprocal of the overall resistance (Rt) = the sum of reciprocals of the individual resistors.

[@rawshitt]

this was extremely helpful thanks :P

[@mitchellwaltmann1872]

Why is this so much simpler than my class

[@Cristiano_Skills-ur]

thank you You helped me

[@DarkGamerA]

thanks a lot my dude

[@santramsharma790]

Nice video

[@arpanghosh1998]

how we identify series and parallel in a circuit

[@princ399]

I cannot thank you enough!

[@AlfaisalAlhajri]

nice 💙. thanks bro

[@masterman280]

Thank You very much.

[@HayDayEveryday]

I cant understand help me pls

[@ifragouri1571]

thank u so much .....man... 😎

[@Allisyes]

you are amazing :D thank you

[@moazelsawaf2000]

Thanks a lot sir

[@MongiNTS3YT]

Thank you buddy!!

[@micoyap100]

very helpful!!

[@vengadakrishnanr2327]

Thanks.... Helpful

[@genevievefernandes2397]

very nice thanks a lot

[@ModernEducationYt]

every thing is good but ur voice is too low pls try to increase ur voice then everything will be perfect

[@zhaoqiwu7621]

AWESOME!