really grateful for such a well and detailed video about this, sir! mabilis po kasi mag-discuss yung prof ko pero dahil sa mga examples niyo naintindihan ko na po! thank you so much po ❤
Thank you. I am glad that this channel have helped you in your studies. Please continue supporting this channel by subscribing and sharing this to your classmates and friends.
Salamat sa iyong napakagandang comment. Sana ay suportahn ninyo itong channel ko by subscribing and telling your friends about your experience here in my channel. Yong tungkol sa tanong mo na ano ang gagamitin sa pagcompute nang Length of curve. Actually, they are both correct. Iyong formula na 20I/D ay na-derived lamang using chord basis. Iyong namang formula na sinasabi mo ay formula using arc basis. Kung iaanalyze mong mabuti ay parang magkaiba ang magiging results nung dalawa.. totoo iyan na medyo mayroong small difference lalo na kung ang radius ng curve ay maikli lang. Pero habang humahaba ang radius na gaya ng ginagamit sa highway ang results ng dalawa approaches each other na nagiging equal sila. Kasi kapag malaki ang radius, iyong subtended arc nito approaches a straight line.
The back tangent (t1) forward bearing is due East. The common tangent forward bearing is S 51° 17' 17" E. The forward bearing of the forward tangent (t2) is N 88° 22' 33" E. The radius for the first curve is 200.00' and the radius of the second curve is 150.00'. The station of the BC is 10+00.00. Diagram, label and solve for all curve elements shown & the PRC and EC stations. how would you solve. for curve two I have R2=150 L=105.5997. C=103.4325 T2= 55.0943. E=9.7979. M=9.1972.
For this kind of speed, it is not recommended to use reversed curvature. One recommendation is to establish the desired superelevation and from which the safe radius of curvature is computed based on that speed. And then spirals are used connect the two curvatures to provide enough transition when changing directions. Or you may consider the other approach. If you are given the velocity, establish what could be the maximum possible radius you can use . And then compute the required superelevation for that speed and radius and then apply spiral that would connect the curves.
If the degree of curve is not given, then it is possible that other elements of the çurve may be known. Then compute for the radius using its relationship with the other elements.
Two tangents converge at an angle 27.9 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 124.85 meters. What is the ratio of the shorter radius to the longer radius in percentage if the bearing of the common tangent is S 37.5 E. Take into consideration that the length of the first tangent is half the length of the second tangent. Station PC is at Sta 10+620. Hello sir, this was the problem I’m referring to the question po. Hoping for response to this, I really need to determine what I was missing out while solving it
Thanks for watching my video...sana ay nakatulong sa inyo itong channel ko. Tungkol sa iyong concern. Malaking tulong if you will be able to draw the reversed curve. Doon mo kasi makikita ang relationship ng mga elements involved in the problem. But anyway, let me guide you in solving your problem. If you will be able to draw the figure, you will find that your I sub1 will be equal to (90-27.9-37.5)=24.6...Then your I2 will be the sum of the angle of convergence and I1. Or simply it can be taken as 90-37.5=52.5. furthermore, you can find in the figure that T2=124.85 sin I2. Then T1 can be computed as its relation with T2 is given.. then the rest can be solved
@@willerdayahan2865 good day sir, I have a follow up question, does I sub1 & I sub2 applicable in getting the long chord and total length of the curve? i was trying to compute it po pero mas baba nakukuha ko sa correct answer po.
Two tangents converge at an angle 28.8 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 184.35 meters. What is the value of the total curve in meters if the bearing of the common tangent is S 35.3 E. Take into consideration that the length of the first tangent is one third the length of the second tangent. Station PC is at Sta 10+620.
Two tangents converge at an angle 25.6 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 150.38 meters. What is the value the long chord in meters if the bearing of the common tangent is S 37.7 E. Take into consideration that the length of the first tangent is half the length of the second tangent. Station PC is at Sta 10+620.
Hello sir, ask ko lang po typo po ba iyong sa Problem 2 sa D1 at LC1 po? Nakukuha ko po kasi sa D1 ay 1.29 po kaya iyong L1 po ay 412.76m po. Thank you.
Oh ... I am sorry.. i had an error on that portion of the solution. That error started when i computed for the radius. When i checked my calculation the value that i used was 1155.916 instead of 1145.916. But I hope that the video helped you understand the process of dealing reverse curvature problems... Thank you for viewing...
really grateful for such a well and detailed video about this, sir! mabilis po kasi mag-discuss yung prof ko pero dahil sa mga examples niyo naintindihan ko na po! thank you so much po ❤
Thank you for your nice comments.. please support my channel by sharing it to your classmates and learn more from here...
Thank you Sir! These playlist about curvatures you made helped me on my review for our midterm exams. Have a good day!
Thank you. I am glad that this channel have helped you in your studies. Please continue supporting this channel by subscribing and sharing this to your classmates and friends.
Hi! If only provid two tangent lines. How can I fit a revise curve or compound curve to joint those tangent? Thank you!
Hello po sir, unang-una po, salamat sa pagtuturo dito sa yt. As in po salamat talaga sa pag lelecture, magaling po kayong prof
Salamat sa iyong napakagandang comment. Sana ay suportahn ninyo itong channel ko by subscribing and telling your friends about your experience here in my channel. Yong tungkol sa tanong mo na ano ang gagamitin sa pagcompute nang Length of curve. Actually, they are both correct. Iyong formula na 20I/D ay na-derived lamang using chord basis. Iyong namang formula na sinasabi mo ay formula using arc basis. Kung iaanalyze mong mabuti ay parang magkaiba ang magiging results nung dalawa.. totoo iyan na medyo mayroong small difference lalo na kung ang radius ng curve ay maikli lang. Pero habang humahaba ang radius na gaya ng ginagamit sa highway ang results ng dalawa approaches each other na nagiging equal sila. Kasi kapag malaki ang radius, iyong subtended arc nito approaches a straight line.
Thankyou sir 🤗
The back tangent (t1) forward bearing is due East. The common tangent forward bearing is S 51° 17' 17" E. The forward bearing of the forward tangent (t2) is N 88° 22' 33" E. The radius for the first curve is 200.00' and the radius of the second curve is 150.00'. The station of the BC is 10+00.00. Diagram, label and solve for all curve elements shown & the PRC and EC stations. how would you solve. for curve two I have R2=150 L=105.5997. C=103.4325 T2= 55.0943. E=9.7979. M=9.1972.
thank you po sir !!
Welcome Claire...
Thank you sir
Welcome.... Paki support naman nitong channel by subscribing and sharing...
for road safety , please suggest specifications of length of common tangent on reverse curve for speed of 100 kmph
For this kind of speed, it is not recommended to use reversed curvature. One recommendation is to establish the desired superelevation and from which the safe radius of curvature is computed based on that speed. And then spirals are used connect the two curvatures to provide enough transition when changing directions. Or you may consider the other approach. If you are given the velocity, establish what could be the maximum possible radius you can use . And then compute the required superelevation for that speed and radius and then apply spiral that would connect the curves.
Hello sir, what if there’s no degree of curve given? How am I able to determine the radius ?
If the degree of curve is not given, then it is possible that other elements of the çurve may be known. Then compute for the radius using its relationship with the other elements.
Two tangents converge at an angle 27.9 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 124.85 meters.
What is the ratio of the shorter radius to the longer radius in percentage if the bearing of the common tangent is S 37.5 E. Take into consideration that the length of the first tangent is half the length of the second tangent. Station PC is at Sta 10+620.
Hello sir, this was the problem I’m referring to the question po. Hoping for response to this, I really need to determine what I was missing out while solving it
Thanks for watching my video...sana ay nakatulong sa inyo itong channel ko. Tungkol sa iyong concern. Malaking tulong if you will be able to draw the reversed curve. Doon mo kasi makikita ang relationship ng mga elements involved in the problem. But anyway, let me guide you in solving your problem. If you will be able to draw the figure, you will find that your I sub1 will be equal to (90-27.9-37.5)=24.6...Then your I2 will be the sum of the angle of convergence and I1. Or simply it can be taken as 90-37.5=52.5. furthermore, you can find in the figure that T2=124.85 sin I2. Then T1 can be computed as its relation with T2 is given.. then the rest can be solved
@@willerdayahan2865 thank you sir, nakuha ko na po super thank you po!!
@@willerdayahan2865 good day sir, I have a follow up question, does I sub1 & I sub2 applicable in getting the long chord and total length of the curve? i was trying to compute it po pero mas baba nakukuha ko sa correct answer po.
Two tangents converge at an angle 28.8 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 184.35 meters.
What is the value of the total curve in meters if the bearing of the common tangent is S 35.3 E. Take into consideration that the length of the first tangent is one third the length of the second tangent. Station
PC is at Sta 10+620.
Two tangents converge at an angle 25.6 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 150.38 meters.
What is the value the long chord in meters if the bearing of the common tangent is S 37.7 E. Take into consideration that the length of the first tangent is half the length of the second tangent. Station PC is at Sta 10+620.
Sa last problem po, hindi po ba length of the common tangent is equal to 219.285?
Hmm ..sorry i could have made a computational error ..
Hello sir, ask ko lang po typo po ba iyong sa Problem 2 sa D1 at LC1 po? Nakukuha ko po kasi sa D1 ay 1.29 po kaya iyong L1 po ay 412.76m po. Thank you.
Oh ... I am sorry.. i had an error on that portion of the solution. That error started when i computed for the radius. When i checked my calculation the value that i used was 1155.916 instead of 1145.916. But I hope that the video helped you understand the process of dealing reverse curvature problems... Thank you for viewing...
Same concern. Buti nakita ko 'to tsaka yung clarification ni Sir.
Sir yung example number 2 sir sa may Lc 1, sta. PRC at sta. P.T ..typo error po ata sir.
Thank you for viewing and giving me this to my attention...but i still hope that you are able to understand and follow the solution to the problem.
@@willerdayahan2865 Eto na pala sagot sa question ko po sir, salamat, ngayon ko lang nabasa sa comment section hehe