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willer dayahan
Philippines
Приєднався 20 бер 2020
Additional Friction Problem 2
This sample problem explains how friction problems may be solved
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Відео
Additional Friction Problem 1
Переглядів 556Рік тому
Learn the Basics of Friction. This sample problem will help you understand the underlying concepts about friction and will let you solve problems on friction easily
Reverse curve with intermediate tangent
Переглядів 6 тис.2 роки тому
A detalled and step by step solution on how to solve reverse curvature problems with intermediate tangent
How to solve Boyle's Law Problems
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How to solve Boyle's Law Problems. Here are some illustrative problems that may guide you on how to solve Boyle's Law Problems
Sample Problem on Spiral Transition Curve
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Helpful tips to how to determine the elements of Spiral Transition Curve. This video will help viewer to easily understand how to solve the different elements of Spiral Transition Curve
Elements of Simple Curve 2
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Detailed approach on how to compute the different elements of simple curve. Computation of the new elements of simple curve when the position of the center of the curve is changed.
Hydrostatics Force on Plane Surface by Integration
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Helpful discussion on how to determine using intergration the total Hydrostatic force acting on plane surface.
Application of Pascal's Law, Boyle's Law and the Principle of Variation of Pressure
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Helpful guide in dealing Hydraulics Problem using the Principles of the Pascal's Law, Boyle's Law and the concepts of the Variation of Pressures.
Kinetics of Rigid Bodies Sample Problems 2
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Kinetics of Particle-Sample Problem
Civil Engineering Pre Board Exam Problems Part4
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Algebra and Worded Problems
CE Pre Board Problems Part 2
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Free Online Civil Engineering Pre-Board Exam Problems
CE Pre Board Problem 1
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Free-Online CE Pre-Board Problems.... If you wanted to test your preparations, Go ahead take this Pre-Board Problems
Curvilinear Motion Sample Problems
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Learn how to solve Curvilinear Motion Problems. This video demonstrates how to deal with them.
Tangential and Normal Components of Acceleration
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Learn here how to determine the Tangential and Normal components of Acceleration and to determine the radius of curvature of a curve path at any time .
Poisson's Ratio Part 3- Sample Problem
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Poisson's Ratio Part 3- Sample Problem
Poisson's Ratio Part 2-Sample Problem
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Poisson's Ratio Part 2-Sample Problem
Statically Indeterminate Member Part 4
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Statically Indeterminate Member Part 4
Statically Indeterminate Member Part 3
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Statically Indeterminate Member Part 3
Statically Indeterminate Members Part2
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Statically Indeterminate Members Part2
Axial Deformation - In What Direction will joint B move? Let's find it here!!!
Переглядів 2,8 тис.2 роки тому
Axial Deformation - In What Direction will joint B move? Let's find it here!!!
Allowable Stress Design of Materials Subjected to Normal Stresses
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Allowable Stress Design of Materials Subjected to Normal Stresses
Mechanics of Deformable Bodies- Simple Stress 2
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Mechanics of Deformable Bodies- Simple Stress 2
Mechanics of Deformable Bodies Simple Stress Sample Problem 3
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Mechanics of Deformable Bodies Simple Stress Sample Problem 3
Sir how did you get the value 6.5 for cy in example no. 1?
Hi .. you can have it solved by taking moments about A equal to zero or you can have it by inspection that is half of 8 plus one-fourth of 4 plus three-fourthts of 2. You can discover the second approach if you practice working on equilibrium of parallel forces . Thanks for viewing..
2:34 hellow sir,..Paano po naging √3?
That was taken using Pythagorean theorem.
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Thanks..
Yown ty po sir, pagpatuloy nyo po
Thanks..
Thank you po, Sir !!
Welcome...
Sir, okay lang po ba malaman reference book ninyo? Salamat po
Oh i cannot recall anymore.. the lecture I prepared came from different sources.
This topic is not easy! It's really hard to find angles and dimensions in such a strange geometry! Although am a civil engineer but still struggling
sir what if the tangents are diverging? pano po e drawing yun
The concept is just similar to the reverse curve having converging tangents. It is just that the intersection of the two tangents in is the PC side.
I've gained a lot of knowledge from your spiral curve series lecture Sir! Words aren't enough to express my gratitude to you. Thank you sir. You're a good teacher 💯
Thank you...
20:37 Hindi po ba pwedeng gamitin nalng ang cosine function to get the horizontal distance po sir?
7:27 Hindi po ba dpat 20 I/ Dc iyon Sir?
sir how do u get the value of area of steel wc is 1398.9?
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2024 sep.2🎉
Thank you po, Sir!
Thank you so much for the detailed lecture sir! Very clear po ang derivation, big help sa current subject ko po na hydraulics.
Sir, ask ko lang po kung yung sa solution 2 niyo po sa may part ng cos theta = OC/AC, ay cos theta = OC/OA?
Ano pong reference book ang gamit niyo dito sir?
ua-cam.com/video/2ESroOOlpx8/v-deo.html hahaha cutie
Thank you for the detailed approach sir, but I have a concern on 22:51 of the discussion. Beta should be 72.5 degrees to complete the total of 180 degree angle of triangle PC-v-Oo. Using the corrected angle the new intersection angle should be 37.9250 degrees
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Sir sa problem 2 yung sa pag kuha ng force F same concept lang po ba
salamat po sa lecture video, Engineer! malaking tulong po ito.
Excelent , thank you for share
Thank you too
finally na gets ko na yung value ng D
Good pm sir ask kolang sir bakit po 1.375 nalabas sakin hinde kopo makuha yung 1.143? Ask kolang sir pano nyo po nakuha yun
ang galing thank you po
Thank you.. please share this channel to your friends..
sir pahelp po dun sa last problem ung angle part po hehe
salamat po
Welcome. .hope you learned from this channel. By the way . Baka naman pwede mai-share mo itong channel ko to your friends
thank you sir ang galing ng turo po ninyu
Very helpful po.
Thank you...
Sir napakagaling nyu po mag turu, Godbless you sir. Pati visual presentation ang galing.
Thank you for this appreciation...I will try later on to upload more video.. hindi ko lang magawa lately because I have to attend to a more important concerns.
thank you for the clear process in solving the problem sir! However, I have a slight correction with the calculation of the maximum and minimum stress. Upon checking multiple times on my calculator, the maximum and minimum stress are 80.804 and 41.11 Mpa respectively
Ganoon ba...thanks for calling my attention here...
Sir thank u. U saved my review. ;)
hello, sir. what about po if si Ax naman yung missing and si Ay how would we know if ano ang direction niya? always po ba along sa tangential and normal components?
Thank you sir! pwede po malaman ano po book reference niyo po.
good day... there are a lot of reference materials that you may use.. you can use the book authored by Singer, you can also use the one by Hibeller.
Sir tanong kulang how exactly did you get the 1.143kn sir nahihirapan ako mag solve paano kinuha ang Fab
Hi Sir, you're the best. I think the problem is difficult to solve if you're only referring to a textbook. Your explanation and solving approach/ technique with the subject matter is the smartest and easiest way of comprehension. Together with a brilliant illustration. Thank you sir for your humble and kind knowledge that you're sharing. Godbless
Thank you for the detailed approach in solving the problems sir! However, I have a slight correction in 43:32. The derivative of (9/2 t)^2/3 is actually (9/2) ^2/3 times 2/3 t^-1/3. By using chain rule of differentiation, the original exponent of the function will be subtracted by 1, hence 2/3 - 1 is -1/3. Hence the velocity of the particle is 1 m/s upon using t = 6s. The same derivative is used in finding the acceleration which is 1.8171 t^ -1/3 which when applied the same process of differentiation will become -0.6057 t ^ -4/3 which yields an acceleration of -0.0555 m/s. Based from this calculation the particle is decelerating.
Thank you for this sample problem sir, but I have a slight correction on 19:47 . BG as indicated is 3.0 + 2.571(0.6) should be equal to 4.5426. The horizontal displacement of B is therefore 4.5426 - 3.72 which is equal to 0.8226 mm. The same with the vertical displacement which is GD + DH should equal to 4.8486 when added.
I am also concerned about the horizontal movement. I think its horizontal movement is the sum of change AC + (BG-FH) w/c is equal to 4.54.
thank you sir❤
you are welcome... there are more topics to learn here.. please subscribe and share your learning experiences to your friends and classmates... thank you.
Question lang po, bakit di kasali yung area BC for shearing stress?
Thanks for watching. I hope that you learned something from this channel. Please share your experiences to your friends and classmates. Now, tungkol doon sa iyong concern, the area that you are referring has no capacity to resist shear load. The horizontal component of the load is resisted in shearing by the area BD in the illustration.
THANK YOU SIR!
Welcome!!! Please share your experiences here to your friends and classmates...Thank you.
Thank you po
Welcome... Please share naman...
Thank you po
please subscribe and share your experience with this channel to your friends
thumbs up po sir! Madali ko po nakuha yung concept
thank you very much...
thankyou po nagets ko na po concept dahil sainyo
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