sir why 0.693 is used at the time 13.37, we are analyzing for 50% of Vdd. 0.693 is for (100- 63)% discharge time of capacitor. i have confusion about this. please explain.
since Vdd is very high so i is directly proportional to Vdd therefore Vdd/Vdd will be cancelled out from the equation and it will be independent of Vdd.
sir why 0.693 is used at the time 13.37, we are analyzing for 50% of Vdd. 0.693 is for (100- 63)% discharge time of capacitor. i have confusion about this. please explain.
Use discharge equation of capacitor.
Vc(t) =Vo*e^(-t/tau)
Put Vc(t) /Vo=1/2 for 50℅ discharge. We get
t=ln2*tau=0.693*tau
@@alraghuschannel4023 thanks
sir how Req is not a function of vdd ? 21:42
since Vdd is very high so i is directly proportional to Vdd therefore Vdd/Vdd will be cancelled out from the equation and it will be independent of Vdd.