I cannot thank you enough for this brother. I am struggling in AP Physics and needed a good grade on this online test to improve my grade for the quarter, I had no clue how to solve this problem until I found this video.
Ok then I have a question that.. As the two blocks are separated i.e attached by string.. thats why on 1 block the downward forward isn't (m1+m2)g? It is m1g and similarly it is m1a? Not (m1+m2)a? So if they were attached with each other i.e both are sticked with a glue or something they the downward force will be (m1+m2)g? And other is (m1+m2)a?
There is a conquering gre textbook which says that the ratios of T1 and T2 is the the ratio of the masses of the blocks m1 and m2. In that case they consider the blocks hanged by a person stationary. But in your case the ratio of tensions is (m1+m2)/m2. Who is correct? I think they should be right but I don’t understand how it comes out
Instead of setting acceleration = 0 in the equations, set it to the appropriate acceleration value (mind also the sign of the acceleration as direction matters)
Aaron Adair ohhhhh. Because one of the problems, the numerator- you subtract the masses(kg) and times it by the earths mass but on the denominator, you add them. I don’t get why u add them in the denominator but u subtract them on the numerator
Fundamentally, you will do the same things: make Free Body Diagrams of each object, and then do the algebraic steps to find all of the tensions. Basically, it's the same as with two objects, but with more work.
There is Fg, one for each block. However, there is no Fn, because a normal force only exists for surfaces in contact. Had either mass been on the ground, there would have been an Fn. In this problem, tension is doing the same sort of thing that Fn does, so if you imagine tension as the same as Fn you’ll get the expected results.
I cannot thank you enough for this brother. I am struggling in AP Physics and needed a good grade on this online test to improve my grade for the quarter, I had no clue how to solve this problem until I found this video.
BLESS YOU , MAN . My exam's in two days and I don't know what I would do in it if I didn't understand this. So thanks!!
It really helped me a lot to understand this kind of quesions! THANK YOU SOOO MUCH!!!
omg this is the only video i can find with this problem thank you much
Same here...
It helped a lot.......thanks......
Thank you!
Really helpful
Ok then I have a question that..
As the two blocks are separated i.e attached by string.. thats why on 1 block the downward forward isn't (m1+m2)g? It is m1g and similarly it is m1a? Not (m1+m2)a?
So if they were attached with each other i.e both are sticked with a glue or something they the downward force will be (m1+m2)g? And other is (m1+m2)a?
what happens to the weight exerted by m1 and m2 u need to consider this too think practicallly,,,,,,,, PLZ REPLY
thankyou so much!!!!
Thank u sir for solving this physics problem
This really helped! Thanks!
There is a conquering gre textbook which says that the ratios of T1 and T2 is the the ratio of the masses of the blocks m1 and m2. In that case they consider the blocks hanged by a person stationary. But in your case the ratio of tensions is (m1+m2)/m2. Who is correct? I think they should be right but I don’t understand how it comes out
Useful bro👍
saving lives frfr
Where does the upward force applied play into this?
Normal force
If you were a given a question with acceleration involved how would you handle it?
Instead of setting acceleration = 0 in the equations, set it to the appropriate acceleration value (mind also the sign of the acceleration as direction matters)
really helped thanks!
I love you.
Great video but how would u find the acceleration?
Because it's just handing, the acceleration is zero.
Aaron Adair yes Ik, but other questions in general.
They ask you about acceleration
ABDUL cherchar you would need to be given that information or else derive it from other given info (e.g., a tension force)
Aaron Adair ohhhhh. Because one of the problems, the numerator- you subtract the masses(kg) and times it by the earths mass but on the denominator, you add them. I don’t get why u add them in the denominator but u subtract them on the numerator
what if there's three objects hanging, how to considered the tension?
Fundamentally, you will do the same things: make Free Body Diagrams of each object, and then do the algebraic steps to find all of the tensions. Basically, it's the same as with two objects, but with more work.
Shouldn't m1 really be m1 + m2 because the string is actually supporting 2 masses?
Only if you want to consider the two masses as one body. But then you won’t be able to describe the second string tension.
so there is no FN and no Fg?
There is Fg, one for each block. However, there is no Fn, because a normal force only exists for surfaces in contact. Had either mass been on the ground, there would have been an Fn. In this problem, tension is doing the same sort of thing that Fn does, so if you imagine tension as the same as Fn you’ll get the expected results.
Aaron Adair goated man thanks🙏
you save me😅