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Thanks for the interesting question. I didn’t quite follow at a step around 3:04 into the video. Could you please explain how did you derive at a^3 + b^3 = 5 and 3ab(m) = -m?
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Input interpretation8^log(2, 0.1×1.6^_ (repeating decimal) ((540 + 12 sqrt(2037))^(1/3) - (-540 + 12 sqrt(2037))^(1/3))) + 2^log(2, 0.1×1.6^_ (repeating decimal) ((540 + 12 sqrt(2037))^(1/3) - (-540 + 12 sqrt(2037))^(1/3))) = 5ResultTrue
It’s in my head.
I think I heard the Azan?
😂۸۸😂😂۹😂
No one is going to ask this question!!Its about the SAT or ACT.
8^k+2^k=5 8^Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]-Cbrt[-540+12Sqrt[2037]])]+2^Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]-Cbrt[-540+12Sqrt[2037]])]=5 k=Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]]k≈0.600250937153109895025675916185478806891182386473553200822310588836959732897222429018450987078179896723590050206204838137086421288128371444381412557762999734577088787200897875675141342246792001603745898764962347586326119360534973723747869563434695686706323300603688868284350174073642832706702148821568889568615127656329460358304304628476265942774467383189467310779820486547581752406523469896875652760625215360936860730565466753107600001712769148056737530522317820857
But how cube root of negative number can be real
Cube is a odd number. That's why!
Thanks for the interesting question. I didn’t quite follow at a step around 3:04 into the video. Could you please explain how did you derive at a^3 + b^3 = 5 and 3ab(m) = -m?
Am your fellow Mathematician content creator ❤❤ you are doing good work.❤❤❤❤i have subscribed
Thanks for your support and subscribing! 🙏💯💕I appreciate you checking out my channel! 🥰💪
Input interpretation
8^log(2, 0.1×1.6^_ (repeating decimal) ((540 + 12 sqrt(2037))^(1/3) - (-540 + 12 sqrt(2037))^(1/3))) + 2^log(2, 0.1×1.6^_ (repeating decimal) ((540 + 12 sqrt(2037))^(1/3) - (-540 + 12 sqrt(2037))^(1/3))) = 5
Result
True
It’s in my head.
I think I heard the Azan?
😂۸۸😂😂۹😂
No one is going to ask this question!!Its about the SAT or ACT.
8^k+2^k=5 8^Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]-Cbrt[-540+12Sqrt[2037]])]+2^Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]-Cbrt[-540+12Sqrt[2037]])]=5 k=Log[2,0.1(1.6 recurring)(Cbrt[540+12Sqrt[2037]]]
k≈0.600250937153109895025675916185478806891182386473553200822310588836959732897222429018450987078179896723590050206204838137086421288128371444381412557762999734577088787200897875675141342246792001603745898764962347586326119360534973723747869563434695686706323300603688868284350174073642832706702148821568889568615127656329460358304304628476265942774467383189467310779820486547581752406523469896875652760625215360936860730565466753107600001712769148056737530522317820857
But how cube root of negative number can be real
Cube is a odd number. That's why!