We need more appreciation for Kali in these comments. They show up every single video and are always HILARIOUS. Kali’s comments are a highlight for me everytime, and I think at some point we need a Kali Supercut.
Recently made it to ante 12 for the first time with a bootstrap and bull run with over $500 and a 10x mult from a constellation and blueprint along with playing almost solely 5 of a kinds with half of my deck being 8’s! Learned a TON from watching your videos. Keep up the great work!
This run is shockingly similar to the run I got yesterday to complete completionist++. Had 3 Tribulets, a blueprint, and picked up The Order as my last gold sticker Joker. Ended up getting to Ante 20 for my best gold stake ever
33:39 fun fact, with how shops work, he still would've gotten the triboulet on the next shop, shops are rolled in a set order per seed, just like any booster pack
I feel like a Lucky 9's build could theoretically work with Cloud 9 and bootstraps/bull alongside something like a constellation for mult, but you're gonna have a really rough time making the stars align for that
Did some math on this (albeit 2 months late). Without red seals you get 2^45 with 3 S&B and 2 Trib and 2^40 with the opposite. But if all your cards have red seals you get 2^60 either way.
mathematically it's better to have all of your blueprints/brainstorms on trib when you have a hanging chad, but only for 5 kings/queens. in the scenario where you have 1 blueprint on the hanging chad the mult is multiplied by (2^3)^4 * (2^3)^5, or 2^27 in the scenario where you have 0 blueprints on the hanging chad the mult is multiplied by (2^4)^4 * (2^4)^3, or 2^28 for 4 kings/queens, its even at 2^24, for 3, the blueprint on the hanging chad has 2^21 and with 0 blueprints on the chad has 2^20. this doesn't take into account mult, lucky or glass cards because i don't want to spend more time on this than i already have you can also prove this by using differential calculus, where x is the number of triggers of trib and 15-2x is the number of times a card is scored. multiplying them together gives you the power of the base 2 that you're multiplying the mult by. if you differentiate x(15-2x) with respect to x and equate it to 0 (to get the maximum of the function) you get the root x=3.75, because the function is symmetrical due to being quadratic, we can safely assume that the function will be higher when x=4 than when x=3, i.e. it is better to put all of your blueprints/brainstorms on your trib
we can also use differential calculus to show that having 2 brainstorms on the s&b and 1 blueprint on the trib is the same as 2 brainstorms on the trib and 1 blueprint on the s&b. once again, x is the number of triggers of trib, 25-5x is the number of triggers of cards caused by s&b. the root of derivative of x(25-5x) is x=2.5, and because the function is symmetrical, f(x+0.5) is equal to f(x-0.5), so cool beans!
Hi, this might be a late reply, but I have a few questions Firstly, are we also excluding red seals? Because let's take this situation starting at 46:55, we start at base 25 mult Looking at the scenario where you have 1 blueprint on the hanging chad, including the red seal on the Jack, I calculated it to be (2^3)^5 * (2^3)^5 or 2^30. When we multiply by 25, we get 26,843,545,600, which is very close to roffle's final score of the round Also, I'm curious as to how you got the expression 15 - 2x for the number of times a card is scored Other than that, I really like the math you did!
@@cyberz55 thank you for your reply. i am in fact excluding red seals because i hate doing more math than i want to. i might come back to this scenario with the red seal later if i feel like it. im sure there's an algebraic way to get the number of triggers as 15-2x however i did it by inspection because i was lazy.
@pinkduck4782 Okay, I finally found an algebraic way to get 15 - 2x with the information you gave me. Get ready! First, I split the exponent of 2^27 to be 2^(3*9), then I looked at what it was equal to: (2^3)^4 * (2^3)^5. Then I looked at the expression when you have zero blueprints on the hanging chad and realized that the 4 as the exponent in (2^3)^4 was actually a constant (this makes sense, because hanging chad always does its thing twice for the 1st card, not the rest of the cards you played in scoring) So I let 's' be the number of times a card was scored. s needed to be defined in terms of x, where x is the number of trib triggers. We have the constant 4 currently, but we still need to find something else to get our desired expression. Then I found a pattern: If the trib triggers 3 times on the 1st card, then the 1st card scores 5 times (1 naturally, 2 from HC and 2 from BP) But if the trib triggers 4 times, the 1st card scores 3 times, implying that we have 0 BP's on the hanging chad like you said. This BP moves to the trib, so the amount of trib triggers goes up by 1. So I tried seeing what would happen if there were 2 trib triggers, and turns out, the 1st card scores 7 times, but this can only happen if we had 2 BP's on the hanging chad, or 2 hanging chads and 1 BP which roffle could theoretically have during his run if he found negatives of them. Using this assumption, if we keep reducing the number of trib triggers we get by 1 (and stopping at 1 because we don't want 0 tribs being triggered), the amount of times we score on the first card increases by 2. Now we have an arithmetic sequence! Starting at 9, then 7, 5, 3 and finally 1. Using the arithmetic sequence formula nth term of sequence = a + (n - 1)d where a is the first term and d is the common difference, we get 9 + (n - 1)(-2), which simplifies to -2n + 11 Also, n = x here, because of the relationship between trib triggers and number of times the 1st card scores. _Also_ also, we can represent this relationship with a linear equation as well, where the gradient is -2 and the y - intercept is 11. Therefore s = 4 + (-2x + 11) , which is 15 - 2x hurray
Not backseat, just a question. Would it be economically better to copy sock 3 times, rather then once for the extra lucky hits and gold seals, and as the trib still gets resets on the extra hits? If not, why is it better to spread?
Idk what you mean about the trib getting resets, but copying sock is def better for Econ and when he has the headroom optimal play is definitely doing that. Copying the tribs is better for scoring though
Genuine question - Can someone explain why he didn’t take s&b at 9:03? Wouldn’t that be objectively better than having Wee? I’m fairly new to the game btw so don’t crucify me
I think your setup late game would’ve been better if you kept the money scoring hand and mult hand joker order the same. Sock and buskin retrigs trib and the glass red seal foil combo again I believe. I think this would result in more mult than just the trib ability. Could be wrong will prob test this w mods at some point.
that small blind at the start was very difficult to watch not because you did anything wrong i just hate it when that happens like i would've reset right then and there
I’m confused, why not always have them all copy sock? Don’t the retriggers retrigger the triboulet anyway but also retrigger the gold seals a bunch more? Or do I not understand how it works
it's a thing of higher base (trib) to lower power (triggers) vs the opposite. There's a sweet middle spot that's about an even distribution for high score, but when you want to farm some money you do all the retriggers to do the gold seals over dedicating some copies to scoring (trib)
this is how I think of it: so there's a sock, trib, 2 brainstorms and 2 blueprints. if you do 4 retriggers of trib and nothing on sock, that's 4x1=4. but if you do 3 tribs and 2 socks, that's 3x2=6. it's best to get the number of copied abilities as close as possible to maximize scores. however, I would agree to copy all socks when he was getting gold seals :)
1:38:04 Negative Tag results in Rental Ride the Bus. I don't think anyone answered him on the stream (Which I was hoping for since I wanted to see his smug reaction to how useless negative tags are).
1:36:23 I was literally mumbling in a cold sweat "streamer streamer please streamer don't do it streamer stop" as he talked to that chatter, ya girl was terrified.
Know I’m late to the party, but I also have a fun seed I found playing unseeded. Gives a final joker lineup of x30 yorick, double triboulet, blueprint, and brainstorm. XS8X3QAX
We need more appreciation for Kali in these comments. They show up every single video and are always HILARIOUS. Kali’s comments are a highlight for me everytime, and I think at some point we need a Kali Supercut.
I strongly agree about the Kali supercut
Ironically playing the jester to Roffle's king, kept around solely because they manage to make the king laugh.
@@Spacialvekter Implying if Kali wasn't funny they would be executed
Kali alt account found
Every seeded run was once unseeded
That's not true if you put random numbers and letters in
@@VinCactusAH0L33NB8
@@VinCactus you know what else puts random letters and numbers in
@@totallynotaferret my
@@NtheTrulyAlmighty cat
Since im currently 3 seconds in i can tell you all that this is indeed a youtube video
Edit: 3 minutes in and now im certain
Any updates?
@@jesuschrist1718 might be a movie will update with more details as they unfold
30 minutes in and ive confirmed this is actually a video about poker i think
@@de_fenestrator2470anything?
Idk man this looks like Vimeo to me
I can't believe Roffle keeps talking about Sockin his Buskin on stream
i love it when i buskin my socks after a hard day of work
Man that Hack just kept on showing up. He made sure we never forgot our wee.
In an alternate timeline, that polychrome Ace becomes a 2 and it becomes a *different* silly run. Hell of a seed to stumble across.
The hack that keeps on hacking
The most important part of a strong run is the Hanging Chad opener
I swear the hanging chad buff was life changing, it even made it into my first successful gold run! Before it was not a chad at all.
Man I just realized 20:00 "the ox" looks like "the 0x" which makes sense since it takes your money and multiplies it with 0 when you play the hand 😮
that's how they get ya
i thought it was called the 0x for like 70 hours of playing
No joke, when I started this video I was fumbling so hard on the yellow deck and while watching this I won and got several achievements. thanks
You know, it took me this long to realize that brainstorm and blueprint are just copies of each other.
7:41 Roffle's editor deserves an Oscar; never has human anguish been captured on film in such soul-wrenching, vivid detail!
I’m fairly certain Roffle edits these himself, which makes it even better
Recently made it to ante 12 for the first time with a bootstrap and bull run with over $500 and a 10x mult from a constellation and blueprint along with playing almost solely 5 of a kinds with half of my deck being 8’s! Learned a TON from watching your videos. Keep up the great work!
I got to ante 12 once. Had two Canios, one came from an Invisible. I also had 8 jokers.
Each Canio gave me *8 mult.
The Plant tried to end the run early. But it could not deny the power of the Weeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee.
WEEEEE!!!
This run is shockingly similar to the run I got yesterday to complete completionist++. Had 3 Tribulets, a blueprint, and picked up The Order as my last gold sticker Joker. Ended up getting to Ante 20 for my best gold stake ever
Casual three legendary haver
oh yes, the hanging chad photograph combo, what a nice new combo
"going Nancy mode" is tied with "i'm all dry for you" with the worst sentences to hear right before the deed
bravo 6 going dark
If you think about it, green deck is yellow deck but you don’t start with 10 extra buckaroos
If you think about it, it isn't at all
Without interest sure
If you think about it, every deck is the same except for the differences
if you think about it red deck is just blue deck but a different color
If you think about it,
13:35 YOOOOO FUNNY FROG STRIMMER AGAIN HELL YEAH SHAYY IS AWESOME
Exactly
First I see him in a pizza tower gdq and now here
@Robert-pk4jjthat was certainly a fun time, glad I got to meet him
It's wild that with all of those procs, the first time you got a money payout from your lucky cards is 28:57. At ante 8
29:10 "Lets see if we can get this going a little bit further". Barely a 1/4 of the way through the video. You know some good content is coming.
Who up scaling they wee joker
He's never gonna beat the Streamer Luck allegations.
Not a chance
After watching him all this past week, he's beaten them to me 😂😂
No, this is Patrick.
Best comment.
I've started just falling asleep to these videos lmao, it's so chill and long enough that I fall asleep before it ends
Roffle getting cranky at chat will never not be funny
33:39 fun fact, with how shops work, he still would've gotten the triboulet on the next shop, shops are rolled in a set order per seed, just like any booster pack
They reset each ante but yes
man that HARD pivot into triboulet just. that gave me whiplash
I feel like a Lucky 9's build could theoretically work with Cloud 9 and bootstraps/bull alongside something like a constellation for mult, but you're gonna have a really rough time making the stars align for that
Did some math on this (albeit 2 months late). Without red seals you get 2^45 with 3 S&B and 2 Trib and 2^40 with the opposite. But if all your cards have red seals you get 2^60 either way.
the way i pray before i go to sleep at night to see a dna in one of my shops and you skipped it on autopilot hurts my soul
55:19 It's so over
58:01 We're so back
"streamer the seed money!" had me yelling
mathematically it's better to have all of your blueprints/brainstorms on trib when you have a hanging chad, but only for 5 kings/queens.
in the scenario where you have 1 blueprint on the hanging chad the mult is multiplied by (2^3)^4 * (2^3)^5, or 2^27
in the scenario where you have 0 blueprints on the hanging chad the mult is multiplied by (2^4)^4 * (2^4)^3, or 2^28
for 4 kings/queens, its even at 2^24, for 3, the blueprint on the hanging chad has 2^21 and with 0 blueprints on the chad has 2^20.
this doesn't take into account mult, lucky or glass cards because i don't want to spend more time on this than i already have
you can also prove this by using differential calculus, where x is the number of triggers of trib and 15-2x is the number of times a card is scored. multiplying them together gives you the power of the base 2 that you're multiplying the mult by. if you differentiate x(15-2x) with respect to x and equate it to 0 (to get the maximum of the function) you get the root x=3.75, because the function is symmetrical due to being quadratic, we can safely assume that the function will be higher when x=4 than when x=3, i.e. it is better to put all of your blueprints/brainstorms on your trib
we can also use differential calculus to show that having 2 brainstorms on the s&b and 1 blueprint on the trib is the same as 2 brainstorms on the trib and 1 blueprint on the s&b.
once again, x is the number of triggers of trib, 25-5x is the number of triggers of cards caused by s&b. the root of derivative of x(25-5x) is x=2.5, and because the function is symmetrical, f(x+0.5) is equal to f(x-0.5), so cool beans!
Hi, this might be a late reply, but I have a few questions
Firstly, are we also excluding red seals? Because let's take this situation starting at 46:55, we start at base 25 mult
Looking at the scenario where you have 1 blueprint on the hanging chad, including the red seal on the Jack, I calculated it to be (2^3)^5 * (2^3)^5 or 2^30. When we multiply by 25, we get 26,843,545,600, which is very close to roffle's final score of the round
Also, I'm curious as to how you got the expression 15 - 2x for the number of times a card is scored
Other than that, I really like the math you did!
@@cyberz55 thank you for your reply. i am in fact excluding red seals because i hate doing more math than i want to. i might come back to this scenario with the red seal later if i feel like it. im sure there's an algebraic way to get the number of triggers as 15-2x however i did it by inspection because i was lazy.
@pinkduck4782 Okay, I finally found an algebraic way to get 15 - 2x with the information you gave me. Get ready!
First, I split the exponent of 2^27 to be 2^(3*9), then I looked at what it was equal to: (2^3)^4 * (2^3)^5.
Then I looked at the expression when you have zero blueprints on the hanging chad and realized that the 4 as the exponent in (2^3)^4 was actually a constant (this makes sense, because hanging chad always does its thing twice for the 1st card, not the rest of the cards you played in scoring)
So I let 's' be the number of times a card was scored. s needed to be defined in terms of x, where x is the number of trib triggers. We have the constant 4 currently, but we still need to find something else to get our desired expression.
Then I found a pattern: If the trib triggers 3 times on the 1st card, then the 1st card scores 5 times (1 naturally, 2 from HC and 2 from BP)
But if the trib triggers 4 times, the 1st card scores 3 times, implying that we have 0 BP's on the hanging chad like you said. This BP moves to the trib, so the amount of trib triggers goes up by 1.
So I tried seeing what would happen if there were 2 trib triggers, and turns out, the 1st card scores 7 times, but this can only happen if we had 2 BP's on the hanging chad, or 2 hanging chads and 1 BP which roffle could theoretically have during his run if he found negatives of them.
Using this assumption, if we keep reducing the number of trib triggers we get by 1 (and stopping at 1 because we don't want 0 tribs being triggered), the amount of times we score on the first card increases by 2.
Now we have an arithmetic sequence! Starting at 9, then 7, 5, 3 and finally 1.
Using the arithmetic sequence formula nth term of sequence = a + (n - 1)d where a is the first term and d is the common difference, we get 9 + (n - 1)(-2), which simplifies to -2n + 11
Also, n = x here, because of the relationship between trib triggers and number of times the 1st card scores.
_Also_ also, we can represent this relationship with a linear equation as well, where the gradient is -2 and the y - intercept is 11.
Therefore s = 4 + (-2x + 11) , which is 15 - 2x
hurray
I love when video games require differential calculus to be properly optimized
1:03:33 The French Revolution be like:
Had the exact same thought lmfao
the last glass was a paid actor
Not backseat, just a question. Would it be economically better to copy sock 3 times, rather then once for the extra lucky hits and gold seals, and as the trib still gets resets on the extra hits? If not, why is it better to spread?
Idk what you mean about the trib getting resets, but copying sock is def better for Econ and when he has the headroom optimal play is definitely doing that. Copying the tribs is better for scoring though
the sock that keeps on buskin
All seeded runs start unseeded
1:03:33 why did this go so hard
"We want death and we want justice"
49:30 hey roffle what was the game jam game that daniel mullins made that turned into inscryption?
I think it would be neat if glass cards chance to break was each time it is "tapped" during scoring with a much lower probability to break
Drinking zacappa to this
6:33 kinda funny how all 4 of ur jacks were in this pack
1:03:34
me: i so do love being an aristocrat exploiting the poor townspeople to gain even more riches
the protestors outside my mansion:
Me when my dad wants us to listen to his favorite album again: 49:37
Genuine question - Can someone explain why he didn’t take s&b at 9:03? Wouldn’t that be objectively better than having Wee?
I’m fairly new to the game btw so don’t crucify me
The boss debuffs all face cards, so s&b would be useless against the boss there
Man, I bought the banana once and lost it on the very next hand. I was disappointed 😂
1:07:24
Wouldn’t Baron be really good there too?
I think your setup late game would’ve been better if you kept the money scoring hand and mult hand joker order the same. Sock and buskin retrigs trib and the glass red seal foil combo again I believe. I think this would result in more mult than just the trib ability. Could be wrong will prob test this w mods at some point.
Just lost a run at ante 16 with baron negative Chad blueprint 2 brainstorms and a 30x constelation
that small blind at the start was very difficult to watch
not because you did anything wrong i just hate it when that happens
like i would've reset right then and there
these e runs being more tense
53:05 this is peak comedy
Half an hour in thr Sawk my Buskin waiting room, get offered a temporary rental. A+ contemt
13:34 shay jumpscare in my balatro video?????
Anyone know what “we’re gunna be rich” is originally from? It almost sounds like a line from crimson skies to me but I’m not sure
It's Reno Jackson from Hearthstone.
@@PkerHaezel that’s a shame. I like crimson skies, need more crimson skies references
0:48 balatro can be so frustrating when you are stupid, which i very much am
buskin: socked
Bro is not beating the photochad allegations
Bro the negative drivers license skip in a deck all about enhancements made me so upset
yes this is unseeded
What if Chico jonkler reversed each boss blind like +1 instead of -1 or it could just give some money
Why didn't he take the sock and buskin? 55:20
The two tags on the card would’ve made it cost him a lot of money and be less effective over time making it not as good as dusk after a few rounds
I’m confused, why not always have them all copy sock? Don’t the retriggers retrigger the triboulet anyway but also retrigger the gold seals a bunch more? Or do I not understand how it works
it's a thing of higher base (trib) to lower power (triggers) vs the opposite. There's a sweet middle spot that's about an even distribution for high score, but when you want to farm some money you do all the retriggers to do the gold seals over dedicating some copies to scoring (trib)
this is how I think of it:
so there's a sock, trib, 2 brainstorms and 2 blueprints.
if you do 4 retriggers of trib and nothing on sock, that's 4x1=4.
but if you do 3 tribs and 2 socks, that's 3x2=6.
it's best to get the number of copied abilities as close as possible to maximize scores.
however, I would agree to copy all socks when he was getting gold seals :)
For scoring purposes, you always want the number of glass/idol/trib triggers to be more or less equal to the number of retrigs on a card
@@aatwob Yeah, okay, I figured that out by the end. Retriggering a card doesn’t also retrigger trib, just the glass.
By looking at the thumbnail I had a similar run but got slammed by the face cards are debuffed
Every single one of my runs like this end that way 😂
Can somebody explain to me why he didn't take the negative Driver's Licence?
i think its because of gold stake and it was a rental card?
craziest thing is that this run is on gold stake
I could make some joke about using the chad and photo but it sounds like it had been a couple of annoying runs before this
In New York I millie rock, Buskin in my Sock
Actually fact checking this allegation
Can we not have an ad every 5 mins smh
Streamer you missed a Baron...
Yoooo first
Love you and the content roffle!!!
At least once a video, every single damn video, I hover over a card to see it's effect, or go to click a next round button. Stupid brain.
Thirteenth :D
Me when
1:38:04 Negative Tag results in Rental Ride the Bus. I don't think anyone answered him on the stream (Which I was hoping for since I wanted to see his smug reaction to how useless negative tags are).
Second?
1:36:23 I was literally mumbling in a cold sweat "streamer streamer please streamer don't do it streamer stop" as he talked to that chatter, ya girl was terrified.
13:32 omg shayy undertale ????
confirmed I only watched starting at 1:34:19 just like you said
Know I’m late to the party, but I also have a fun seed I found playing unseeded. Gives a final joker lineup of x30 yorick, double triboulet, blueprint, and brainstorm. XS8X3QAX
1:05:30 100 Gold