Mr.Hugo, your videos helped me a lot as a mechanical engineering student... love the way u go about explaining the theory and solving the example problems.. got many of my concepts clear.. thanks a lot!! :) I would like to knw if u have explanatory videos other than thermodynamics..
Very glad to hear that you found them useful. I would like to develop my fluid mechanics and heat transfer courses in a similar manner but have not yet had the time to do so. For now it is only Thermodynamics ...
Hello Mr. Hugo, hope you're doing well. When you find the mass flow rate of dry air, you divide the mass flow rate of MOIST air by the specific volume of DRY air. This is confusing and seems inaccurate. It'd be great if you could clarify this for me. Thanks.
Hi, Hugo, your lecturers are really excellent, it helped me a lot, and the knowledge will stay in my mind for a long time, thanks from Australia!
Me too
From Pakistan
Mr.Hugo, your videos helped me a lot as a mechanical engineering student... love the way u go about explaining the theory and solving the example problems.. got many of my concepts clear.. thanks a lot!! :)
I would like to knw if u have explanatory videos other than thermodynamics..
Very glad to hear that you found them useful. I would like to develop my fluid mechanics and heat transfer courses in a similar manner but have not yet had the time to do so. For now it is only Thermodynamics ...
there is no mass adition but the question says 1.16 m^3 enters then we find air mass 1.3639? how could it possible
Hello Mr. Hugo, hope you're doing well. When you find the mass flow rate of dry air, you divide the mass flow rate of MOIST air by the specific volume of DRY air. This is confusing and seems inaccurate. It'd be great if you could clarify this for me. Thanks.
sir, where did you get the value of 1.1666 m^3/s in that question?
That comes by converting the volumetric flowrate expressed in m^3/min into m^3/s.
+Ron Hugo thank you.. ok got it.