Everything is alright, but do note that at 12:04 you won't have complex roots for the over damped system, but you'll have distinct real roots lying on the left half plane.
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Thanks a ton for uploading the tutorials , especially for the semester subjects! It is very precise and more than sufficient for Engineers like me.. :)
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There is a factor attached to the wn^2 of the numerator which is :- ratio of the constant attached to the input to the constant attached to the output of the system, and for some reason in every control lecture it's always assumed to be unity and that's where the confusion begins. It's of not much importance as we are only concerned with the denominator and that is the characteristic equation
@Srinu Janke ..For conceptual understanding you can refer K. Ogata. Modern Control Engineering Control system engineering by I J nagrath and M gopal For practice problems (exams) Many books as..control system books by Nagoor kani, Hasan shaheed, Ramesh Babu , etc.
@@ashish6097 Actually it's not the case. 1) wn^2 is the not the factor. wn is just the natural frequency. 2) there is a factor attached to the wn^2 of the numerator which is :- ratio of the constant attached to the input to the constant attached to the output of the system, and for some reason in every control lecture it's always assumed to be unity and that's where the confusion begins. It's of not much importance as we are only concerned with the denominator and that is the characteristic equation
@@AdityaMishra-pp1gw buddy , I was talking about the standard second order system . The factor term here I used is for value of wn^2 . The factor you are talking about is actually dc gain of system . If the function is not a standard second system , then some formulas will not directly work , one of them is overshoot and to use the same formula we first make standard second order system then extra constant we get will work as dc gain. If you still have any doubt , just search my name at quora . We can discuss there . Have a nice day
@@ashish6097 Hi buddy! Yes, I was talking about the DC gain but did not wanted to mention the term as this term is defined by 'us' when working with steady state response. What I thought the Jack Kabir was asking is whether the constant term attached to both the wn^2 should be equal. And ofcourse the constant attach to the numerator will only come to play when we are giving some response to the system. In the standard second order system as mentioned by you both the constnat of wn^2 will be equal. Still I am not convinced how you told him to multiply and divide by the factor wn^2. If you are mentioning the value of natural frequency as the factor why would one divide and multiply the equation with natural frequency.
@@AdityaMishra-pp1gw the thing I have mentioned about divide and multiply is just to make it standard second order system and that's it . Nothing more than that . As to deal with standard function is much easier as compare to some other function which is not standard . Don't extend the topic and I got your point ;)
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She has saved my life many times. Thank you
Laura
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The look she gave at 9:36, damn I thought she caught me eating Pasta in the class! .....Dead😂
I was using my phone for a sec to check message at that moment only
😂
😂😂
Yes yaar
Damnn.... It's been 10months... I am still scared of that look.. Lmao
@@USMan21 scary look😅
Everything is alright, but do note that at 12:04 you won't have complex roots for the over damped system, but you'll have distinct real roots lying on the left half plane.
i was also thinking same bro
I agree. I headed to comment section after observing this mistake. I thought it would be addressed here but they haven't corrected it.
She corrected her mistake later
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I too thought the same bro...... I think you are one year future version of me :)
mam....your teaching style is best ,I feel better after understanding your class
I wish my professor would be like you.Very clear explanation 👍
Congratulations ma'am for 1M+ Subscribers 🖤 we all love you
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video related to time response analysis of second order system
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Thanks a ton for uploading the tutorials , especially for the semester subjects! It is very precise and more than sufficient for Engineers like me.. :)
ua-cam.com/video/-N2lLMWQ-WQ/v-deo.html
video related to time response analysis of second order system
each and every que related to GATE of time domain anlysis discussed
must watch and subscribe the channel
Superbly explained. A very good reference video for old engineers
Here the value of G(S) is wrong ..it should be Wn^2/ s(s+2JWn)... There is 2 missing
yaa what you said is correct
Tnx bro
thnkuu
@@freeecetcoachingtq
I was wondering how two get into formula
You have saved me again.
I love you ❤️
for over damped 2nd order system roots are real and distinct
please elaborate
@@amirulasyraf9900 geta >1 square will be greater than 1 the term under root is positive we will get positive root
Very informative lecture, thank you ma'am. greeting from AOA.
Thank you soo much your videos have helped me a lot.You are sooo informative and on point in everything.
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U have to put 2 in the ( G(s)) like
S (S+2gwn).. Even though the there is mistake why some people act smart. Without even knowing the mistake..
Clean and lucid explanation
Thanks madam !! You are the best💯🙏🙏
Thank you very much for the explanation
Really nice explanation, Ma'am.
great explanation! thank you so much. request you to work on your accent as sometimes it gets difficult to understand
Very Very Very Very Very Very Very Very good teacher
Thank you very much ❤️💙
Madam you are missing the number 2 on the block diagram
which you have written on the final transfer function.
Exactly, it really confused me where this 2 came from xD
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Mhmm..
I confused..
at the end of the video you can just let your students see the board.
sry to interrupt ma'am....
but you are wrong in finding the poles for a over damped system.
These roots are real and unequal.
Very nice lecture for easily understanding
Thank you very much.
because of this i never hated india. thanks madam
student ruttifying concept ,teachers like her in future
Thanks mam😊
Thank you mam 🔥
I have small doubt madam i.e if u attend to gate exam,then u will get good rank or not?
For g>1, the roots are real, but it is irrational
But u said that the roots are complex
thank you madam
Mam how u got T(s) can u explain ones
How u got 2getaw^2n
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Thanks.
gain is 2gWn not gWn 0:00
2 will not come in the above transfer function equation in the denominator...
Yes , 2 won't be there
Mam how do found the roots of underdamped condition .Will u plz explain it to me mam.
Keep going madam
Thank you
I am looking for equation examples on this lesson but can't find any
s(s+2gwn) try to corracte that and thank you for explenig
In G, denominator 2 is missing
please. I ask you to give us an example of a sliding mode controller application with this 2nd order transfer function
Mam can you suggest any book on control system engineering?
Palm
Nice
Explain about underdamped second order system
It is told in video
siraa madam g
Overdamped me glt btaya ma'am aapne
mam please explain in details you were missing many points ......................
what if it is -ve ? how the roots will be?
then system will be unstable . and practical control system is always stable
Among these systems which one is desirable and why
Good madam
in complex roots there is no sufficient explanation
dear mam,
is necessary to equal both wn^2? (numerator and denominator)
yes
but when unequal then what can i do?
Jack Kabir yes
There is a factor attached to the wn^2 of the numerator which is :-
ratio of the constant attached to the input to the constant attached to the output of the system,
and for some reason in every control lecture it's always assumed to be unity and that's where the confusion begins. It's of not much importance as we are only concerned with the denominator and that is the characteristic equation
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Madam I want full concept of second order system madam
@Srinu Janke ..For conceptual understanding you can refer
K. Ogata. Modern Control Engineering
Control system engineering by I J nagrath and M gopal
For practice problems (exams)
Many books as..control system books by Nagoor kani, Hasan shaheed, Ramesh Babu , etc.
The closed loop pole of a stable second order system could be....???? plz ans it
left half of s plane
Link of Transfer function of second order RC circuit. ua-cam.com/video/fdwinxWORdQ/v-deo.htmlsi=se1YY-i6a1HI9uu1
What is S?
Why is everyone calling her madam
then what should she be called?
Good English more effective
IN 10.07 how she get -out .if we took out ζ Has already square how underroot 1-ζ2 Plz can anyone explain me i am confused
How u told the transfer function
if numerator and denominator's wn^2 are not equal, then?
then that equation would not be called standard second order equation .. to make that standard eqn we need multiply and divide by factor wn^2..
@@ashish6097 Actually it's not the case. 1) wn^2 is the not the factor. wn is just the natural frequency.
2) there is a factor attached to the wn^2 of the numerator which is :-
ratio of the constant attached to the input to the constant attached to the output of the system,
and for some reason in every control lecture it's always assumed to be unity and that's where the confusion begins. It's of not much importance as we are only concerned with the denominator and that is the characteristic equation
@@AdityaMishra-pp1gw buddy , I was talking about the standard second order system .
The factor term here I used is for value of wn^2 .
The factor you are talking about is actually dc gain of system .
If the function is not a standard second system , then some formulas will not directly work , one of them is overshoot and to use the same formula we first make standard second order system then extra constant we get will work as dc gain.
If you still have any doubt , just search my name at quora . We can discuss there .
Have a nice day
@@ashish6097 Hi buddy! Yes, I was talking about the DC gain but did not wanted to mention the term as this term is defined by 'us' when working with steady state response.
What I thought the Jack Kabir was asking is whether the constant term attached to both the wn^2 should be equal. And ofcourse the constant attach to the numerator will only come to play when we are giving some response to the system. In the standard second order system as mentioned by you both the constnat of wn^2 will be equal.
Still I am not convinced how you told him to multiply and divide by the factor wn^2. If you are mentioning the value of natural frequency as the factor why would one divide and multiply the equation with natural frequency.
@@AdityaMishra-pp1gw the thing I have mentioned about divide and multiply is just to make it standard second order system and that's it .
Nothing more than that .
As to deal with standard function is much easier as compare to some other function which is not standard .
Don't extend the topic and I got your point ;)
Teacher :May I go to washroom 💩💩💩
Hey u r wrong in many points
Thank you