There was a simple mistake that was done in taking the derivative of question 2. [ ln(2x+3) = 2/(2x+3) ]. However , I like your the way you teach and that music sound of yours😂😋
I like this logarithmic differentiation a lot. Thanks for pointing out this approach. (And I'm sure you threw in the little glitch at 8:24 just to keep us on our toes!)
Very nice video! Thanks. Just wanted to note that there is a way to differentiate the first example, without using higher level concepts. You can rewrite to y = e^(ln(x^2 + 3)^x). That becomes y = e^(x*ln(x^2 + 3)) . Then differentiate. You get an application of the product rule inside the chain rule. And the same answer. The advantage is that you don't need to use implicit differentiation (just laws of logs), the disadvantage that there things in the exponent and that's possibly more annoying notation.
Personally I'm okay with either the quotient rule (a special case of the product rule) or logarithmic differentiation. Although in most cases logarithmic differentiation is quite a bit easier and to be honest I'm fundamentally lazy. 😎
There was a simple mistake that was done in taking the derivative of question 2. [ ln(2x+3) = 2/(2x+3) ]. However , I like your the way you teach and that music sound of yours😂😋
Oh noooooo! I just looked at it. You're correct. Thank you.
I like this logarithmic differentiation a lot. Thanks for pointing out this approach. (And I'm sure you threw in the little glitch at 8:24 just to keep us on our toes!)
Fascinating! Well done, sir!
ln(2x+3)'=2/(2x+3)
Oh no! What was I thinking! Thank you.
U are the best🎉
Thanks ! This video helps me to understand the basics really well....!❤❤
Awesome, this is the best method I ever learned.
Glad it was helpful!
very much easier than quotient rule😍, really like this method ,I wish I knew it last time I was in high school 🤩
I think you're right, about logarithmic differentiation being better, but still in some cases the quotient rule can be the better option.
Very nice video! Thanks.
Just wanted to note that there is a way to differentiate the first example, without using higher level concepts.
You can rewrite to y = e^(ln(x^2 + 3)^x). That becomes y = e^(x*ln(x^2 + 3)) .
Then differentiate. You get an application of the product rule inside the chain rule. And the same answer.
The advantage is that you don't need to use implicit differentiation (just laws of logs), the disadvantage that there things in the exponent and that's possibly more annoying notation.
You're correct. The purpose of the video was to show that it could be done using logarithmic differentiation as an alternative method.
I just found the derivative of sec^-1(x) using logarithmic differentiation. Sweet. 🤓
شكرا لكم على هذا المجهود الكبير
LOGARITHM DIFFERENTIATION IS THE BEST
Thanks Mr. Newton
Waaw nice exmpe and explnton❤❤❤🇸🇴🇸🇴🇸🇴🇸🇴
Personally I'm okay with either the quotient rule (a special case of the product rule) or logarithmic differentiation. Although in most cases logarithmic differentiation is quite a bit easier and to be honest I'm fundamentally lazy. 😎
You are right. Sometimes, we just like to do our thing our way.
Thank u sir now I understand
Thank you very much sir lots of love from india
Very good content 👌❤️
thanks for explaining each step!
Thank you!
in example 1. Why did you not go further with determining ln(x^2)+ 3? why stop there?
Good job.
Do you have teachings on Parametric Differentiation
Not yet. But if you email me a question, I can do a video. Message my channel on Instagram.
Alright, send me your email address
Primenewtons@gmail.com
The lesson on the board needs to come closer to the viewers,and visually amplify for clarity.
I hope you find the newer videos closer.
Did you make a mistake or I am missing something?