In the previous exercise F=150 Nw was the Force necessary to maintain v=constant in upward direction. So I thought that with149Nw the block went in downward direction but you demonstrated that 73Nw are necessary. What happens with F between 73 and 150?
Not a stupid question at all. This confuses many students. The magnitude of a force cannot be negative, thus the magnitude of the normal force is F sin(theta). But as a vector it points to the left in this problem, thus the direction would be negative.
In the previous exercise F=150 Nw was the Force necessary to maintain v=constant in upward direction. So I thought that with149Nw the block went in downward direction but you demonstrated that 73Nw are necessary. What happens with F between 73 and 150?
So if F>73Nw the block goes in upward direction; if F
Very well explained! Thank you!
Stupid question, is the normal force equal to Fsinceta or -Fsinceta?
Not a stupid question at all. This confuses many students. The magnitude of a force cannot be negative, thus the magnitude of the normal force is F sin(theta). But as a vector it points to the left in this problem, thus the direction would be negative.
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