1. Time variant sys. y[n]=x[-n] Because if we do time shifting by -k in input side then output will be y'[n]=x[-n-k] But if we do time shifting by -k in output side then output will be y[n-k]=x[-(n-k)]=x[-n+k] And x[-n-k] is not equal to x[-n+k] 2. TIV system 3. TV system (time scaling) 4. TV system (time dependant coefficient)
i think, It is non linear because of y(t)dy(t)/dt , as per superposition if we separately add it gives y1(t)dy1(t)/dt+y2(t)dy2(t)/dt ,but if we combine y1(t)+y2(t) dy1(t)+y2(t)/dt it gives 4 terms so it is nonlinear term
1) TIV because it is a special case of time scaling which is time reversal remaining 3 are TV ..... sir plz correct me if i am wrong because HW problem page of SS is not accessible !!
@@vaibhav_pal.vp. I think 4th is TV Because last term will be cosn×x(n) that means second condition not be satisfied That is coff is not constant that is cos(n) is variable hence time is variant.
1. TV
2. TIV
3. TV
4. TV
1. Time variant sys.
y[n]=x[-n]
Because if we do time shifting by -k in input side then output will be y'[n]=x[-n-k]
But if we do time shifting by -k in output side then output will be y[n-k]=x[-(n-k)]=x[-n+k]
And x[-n-k] is not equal to x[-n+k]
2. TIV system
3. TV system (time scaling)
4. TV system (time dependant coefficient)
how second one is TIV
Second question also time variant, since there is a time scaling
If you don't provide correct answer how can we verify our answers??
1.TV, 2.TIV, 3.TV, 4.TV
sir plz a complete video on Microprocessor
1.Tv, 2.tiv, 3. Tv, 4. Tv
1) TV
2) TIV
3) TV
4) TV
sir, pls provide the solution for HW problem
What if the expression already has a time shift? for example, x|(2m-3)|. Is this T.V. because it has the 2m ( Time scaling)?
sir, HW problem page of SS and AE is not accessible !! sir plz make it accessible...ty
Hw Problems
1. TV
2. TIV
3. TV
4. TV
Sir is the following system linear or non linear
y(t).dy/dt + 3y(t)=x(t)
in your lectures u hv concluded that linearity is independent of amp scaling . so how this system is being Non.Linear?
i think, It is non linear because of y(t)dy(t)/dt , as per superposition if we separately add it gives y1(t)dy1(t)/dt+y2(t)dy2(t)/dt ,but if we combine y1(t)+y2(t) dy1(t)+y2(t)/dt it gives 4 terms so it is nonlinear term
1) TIV because it is a special case of time scaling which is time reversal
remaining 3 are TV .....
sir plz correct me if i am wrong because HW problem page of SS is not accessible !!
Bhai 1 TV hoga conditions dekhle ek bar. SCALING NHI HONI CHAIYE TIV K LIYE
Aman Sajwan ok
TV , TIV , TV , TV
All except 2 are TV
brother, I think this is an additivity case that you have written.
@@raviprakashmeghwanshi5802 Yaa, sorry!! Got confused between linearity and Time Variance.
It is time invariant.
1. TIV 2.TIV 3.TV 4.TV
Only 2 is TIV others are TV
Ok
1. TV
2. TIV
3. TV
4. TIV
All TV
All 4 problems have same answer, TV
Wrong
1.tv
2.tv
3.tv
4.tv
Wrong
2 , 4 tiv
@@vaibhav_pal.vp. I think 4th is TV
Because last term will be cosn×x(n) that means second condition not be satisfied
That is coff is not constant that is cos(n) is variable hence time is variant.
1.tv
2.tiv
3.tiv
4.tv
3rd me time scaling h
4 tiv
1. TV
2. TIV
3. TV
4. TV
4 is also tiv
1.TV
2.TIV
3.TV
4.TIV
1.TV 2.TIV 3.TV 4.TV