How did my professor manage to tell this in 5 weeks of lectures and I still didn't get it, while I'm watching a 10 minute video about it and instantly grasp it. Great video man.
1. Time variant 2. Time invariant 3. Time variant because at first when input is passed from system we get y=cos(t)+x(t) and after passing from delayed to system we get y(t)=cos(t-to)=x(t-to). Second when input passed from delayed system we get x(t)=x(t-to) and after passing through system we get y(t)=cos(t)+x(t-to).so its not equal hence it TIME VARIANT .
@@mrherrada797 For the first 1) The system is sub each t by sin(t) 1) x(t)----> x(t-t.) --->y1(t)= x(sin(t) -t.) 2) x(t) --->y(t)= x(sin(t)) ---> y2(t) = x(sin(t-t.)) Hens, y1(t) not= y2(t) ---> TV sys
in third homework question step 1) Will the cos(t) becomes cos(t-t0) when we perform delay by t0? The thing which is confusing me is, since the input signal is x(t) and cos(t) is a coefficient but at the same time cos(t) also depends on t. So, if we are giving the output signal in a system which performs delay on that signal, so should this system on perform delay on x(t) part of the output or should cos(t) also be included? Explanation will be appreciated.
I got your problem. you are confused becoz in causal video, Sir said,we should ignore coefficient while checking causality but here we have to shift cos 't' also by 'to'. So answer of 3rd question will be Time Invarient.
1) y(t)= x(sint) is time variant 2) y(t)=x(t+2) is time invariant 3) y(t)=cost+x(t) is variant the first and 3rd one is just depending on delay of time so time variant and the 2nd one has time with constant on both depending so its time invariant
Sir, when we delay the signal y(t) by time to, the new signal will be y(t+to). But why are you taking y(t-to) Sir? It will then become advancing the signal right?
Clearly watch the time shifting video posted by neso. I am also stuck with this confusion. Put the operations of time shifting on paper, then you will get a clear idea about it and you won't confuse again.
Time delayed by to, means what we used to get at t=t1 will now get at t=t1+to. So, signal in y(t) we get y(0) at t= 0 but in y(t-to) we will get y(0) at t=to( by putting t-to=0). And you can also look by signal plot delay by to means plot will shift to right by to, which will result into y(t) --> y(t-to)
First I found 1. to be TIV but further reasoning results in 1. being TV: In step #1 provide the delay t0 to the output y(t), giving y(t-t0). As y(t) is equal to x.sin(t), t is replaced by t-t0, giving y(t-t0) = x.sin(t-t0) = x[sin(t).cos(t0)-cos(t).sin(t0)]. In step 2, instead of providing the delay t0 to the output it is provided to the input x(t), giving x(t-t0). This is fed as input to the system which has the characteristic of performing the time scaling operation. The operation is taking the sinus of the time which is then multiplied by x. The time scaling operation is only performed on the time t itself, not on the constant t0. The resulting output of the system, therefore, is x.sin(t) - t0. This result is unequal to the result of step 1 above. Therewith 1. is TV. Correct me if I'm wrong. Thnx.
According to my best knowledge, this is just a notational difference, all three notations meaning the same thing, i.e. x(sint) means: "x multiplied by the sine of the value for t" where the multiplication is implied by the opening bracket ( after x; then next x.sin(t) means: "x multiplied (the dot .) by the sine of the value for t where in this case t is put between brackets ( ) to make the notation more clear, that is sin(t) instead of the seeming word sint which could mean something else such as saint; and finally your notation x(sin(t)) which also means: "x multiplied by the sine of t" where the multiplication is implied by the opening bracket ( after x.
If however, there is a difference between the three notations in that they produce different results, then please explain this to me. Also what would be the effect of your notation on the addition of the delay t0 before and after the system performs the time scaling operation? Thanks in advance for your response.
In first example, Step1 ---> since Y(t) = X(2t), when the output Y(t) is delayed by t* shouldn't the output of the system be X(2t-t* ) and in the Step 2 ----> Just like the step 1 in the video????
thank you dear for your video and learn this to we poeple. but i have question about : X(2t) I ask about your answer: that write this: x(2t-2t0) please describe for me at here about my question. Thank you dear teacher
Hello I want to ask, sorry if the question are little bit weird (because im still 12), but Delay by t。is mean what?, are basically mean t - t。?, and what is x(t) exactly?, what the paramaeter t do there?, are the value is actually the t and the x or y is just the name function?
all are time invariant. In 1st question, time shifting doesn't affect the result and in 3rd question, we only have to take x(t) because it is the input not cos(t).
Hi, in the first case, after going through the system the output y(t)= x(2t). Now if we provide a delay wouldn’t it be x(2t-to)? Similarly, in the second case the delayed input is x(t-to), and when this input is given to the system, wouldn’t it scale the whole parameter of the input and become x(2(t-to))? System is variant either way, but just for the clarification of the concept...
can anyone one explain me mathematically the 3 question i.e, how y(t³) = x(t) is a TV system. Please mail me the picture of the solved problem. Thanks in advance
Please someone can write the conclusion i'm studing in frensh but i don't make diffrence between the TIV and TV i really need them i'll pass my exam on this week so please help me
I guess the first example is wrong. It is TIV because the output for x(t-t0) will be x(2t-2t0) and not x(2t-t0). The reason given in S-2 that the scaling applies to only the independent variable is wrong. The scaling applies to whatever is the argument inside x()
Why do we denote delay as negative? For eg if a system is taking 5 s and I give a delay of 5s...shouldnt that be 10s....so why are we subtracting... It might be silly but please help
Somewhat Crazy X(t-t0) is right shift, if we subtract it gets equated as t=t0 on othr hand x(t+t0) is left shift it gets equated as t=-t0, so fr delay as u said gets added up so cant b negative i.e it cant b t=-to hence we need t=t0 so u hv to take delay as x(t-t0) in order to get t=t0...
How did my professor manage to tell this in 5 weeks of lectures and I still didn't get it, while I'm watching a 10 minute video about it and instantly grasp it. Great video man.
That's what school teach what to learn but not how to learn
u have got great school we had to learn this whole control system in our school under 3 months , in 5 weeks of lecture we had to complete 35% course
your prof took 5 weeks for teaching just one concept?
Here the topic is same but, your interest is place important role to understand certain topic
It's matter of priority and interest...
Great explanation. Totally a great one that our college's lecturers cannot give.
clear, eloquent, organized and straight to the point
Thank you sir.... generally I have fear of signals subjects.....but because of these lectures it make me Soo comfortable
1. TV
2. TIV
3.TV
For anyone facing difficulty in solving the HW problems, finish the next lecture and you'll easily complete this problems.
*these XD
thankyou so much miss
@@watchmerolliin4896 chup baye chutyay
Thanks
3 will be tiv
I have about 20 hours until my first systems and signals exam. This explained it very well. Thank you.
Update: The exam was rough for everyone that took it
Exactly 13 hours for me, thinking to pull an all-nighter
@@varun_4125 Exactly 19 hours for me to prepare for my own exam
16 hours for me
Update Got an 87
Your way of teaching is so much satisfying. You made me not get bored while listening. Thank you.
1. Time variant
2. Time invariant
3. Time variant because at first
when input is passed from system we get y=cos(t)+x(t) and after passing from delayed to system we get y(t)=cos(t-to)=x(t-to).
Second when input passed from delayed system we get x(t)=x(t-to) and after passing through system we get y(t)=cos(t)+x(t-to).so its not equal hence it TIME VARIANT .
how bout you explain the previous two that are obviously harder
@@mrherrada797
For the first 1)
The system is sub each t by sin(t)
1) x(t)----> x(t-t.) --->y1(t)= x(sin(t) -t.)
2) x(t) --->y(t)= x(sin(t)) ---> y2(t) = x(sin(t-t.))
Hens, y1(t) not= y2(t) ---> TV sys
awesome teaching ....
thank u sir...
keep updating the channel
u dont know how much we are benefited by your lecture videos
1.TV
2.TIV
3.TV
In 3rd problem, x(t) is input and cost is the term obtained from the system's output.
great
Hi could you expand more your answer for no. 3?
Thank you
@@julilacart3692 y'(t) = cost + x(t-to) and
Y''(t) = cos(t-to) + x(t-to)
Thus y'(t) and y''(t) are not equal. Hope it helps !
@@vishvakapadiya3051 can solve 1st one is it time variant
@@aravindhgunti yes it is Time Variant. y'(t) = x(sint - to) and y"(t) = x(sin(t - to)) thus y'(t) and y"(t) are different. Hope it helps :)
TV System
TIV System
TV System
❤
u are a truly a gem sir👌👌ur teaching is helping a lot of students like me..
2 min in: Great explanation, that was all I needed!
@NesoAcademy its a very humble request please post answers of HW questions.
brilliant way of teaching - student from China
the transformation t->-s reveals, essentially that any function of (-t) will transform backwards in time with a time shift.
Sir thank you I really understand your lectures, I'm currently on a binge watch for my upcoming exam next week
Pro tip: Watch at 1.25x speed for best results
1.75x is the best
I watch in 2x
2x goes brrr
@@varun_4125 3x is far better
I watch at 2x 🤭
1. TV x(sint - sint0) != x(sint - t0)
2. TIV x(t-t0+2) == x(t-t0+2)
3. TV cos(t-t0) - x(t-t0) != cost - x(t-t0)
In the 1st case x(sin(t-t0)) != x(sint - t0).
it'd be very helpful to know the answers to the hw problems, because reading others answers is making confused.
For all time. Always
in third homework question step 1) Will the cos(t) becomes cos(t-t0) when we perform delay by t0? The thing which is confusing me is, since the input signal is x(t) and cos(t) is a coefficient but at the same time cos(t) also depends on t. So, if we are giving the output signal in a system which performs delay on that signal, so should this system on perform delay on x(t) part of the output or should cos(t) also be included? Explanation will be appreciated.
I got your problem. you are confused becoz in causal video, Sir said,we should ignore coefficient while checking causality but here we have to shift cos 't' also by 'to'.
So answer of 3rd question will be Time Invarient.
My left ear really enjoyed that.
sir, you presented the concept very clear!
then why we multiply 2 with t (naught) in the first step of number 1 example? 7:00
First one is TV as time scaling is performed
Second one is TIV as amplitude shifting is performed
Third one is Tv
You are genius sir !
Thanks for making study easy :)
TIV
TIV
TV
is the final and true answer
Very clear explanation...thank you so much Sir
Great explanation
1) y(t)= x(sint) is time variant
2) y(t)=x(t+2) is time invariant
3) y(t)=cost+x(t) is variant
the first and 3rd one is just depending on delay of time so time variant and the 2nd one has time with constant on both depending so its time invariant
Great! Greeting from Bulgaria!
nice teaching sir
Great explanation, thank you
Really cool explanation very clear and catchy 🤩🤩
much useful video for student sir Thank you very much
@Neso Acadmey ...please post the answers of the homework problems too!!!!!
Thank you sir
Earlier we studied that in time transformation the order ( shifting & scaling) doesn't matter.
But isn't this property somehow contradict that point?
your work is excellent...!!! :)
The videos are really helpful. But it would be complete if answers are given for verifying. Thanks!
1. TV
2. TIV
3. TV
please tell whether I have done it correct or not.
Tiv tiv tv plz check it
No its TV. Most probably the mistake you are doing is you are also scaling constant in step 2.
sin is not scaler guys..its a function...simple sine has no value ..it always comes with a variable like time t
Kritika Deshmukh so 1 question is TIV right
Question 1 is TV bcz any operation on variable makes the system time variant.. such as x(logt), x(cost) or x(|t|) except time shifting
Sir, when we delay the signal y(t) by time to, the new signal will be y(t+to). But why are you taking y(t-to) Sir? It will then become advancing the signal right?
Clearly watch the time shifting video posted by neso.
I am also stuck with this confusion.
Put the operations of time shifting on paper, then you will get a clear idea about it and you won't confuse again.
Time delayed by to, means what we used to get at t=t1 will now get at t=t1+to.
So, signal in y(t) we get y(0) at t= 0 but in y(t-to) we will get y(0) at t=to( by putting t-to=0).
And you can also look by signal plot delay by to means plot will shift to right by to, which will result into y(t) --> y(t-to)
Thank you...the best lecture for SAS ...
1:TV
2.TIV
3.TV
Keep it up! Honestly helped a lot.
Thank you so much ❤
First I found 1. to be TIV but further reasoning results in 1. being TV:
In step #1 provide the delay t0 to the output y(t), giving y(t-t0). As y(t) is equal to x.sin(t), t is replaced by t-t0, giving y(t-t0) = x.sin(t-t0) = x[sin(t).cos(t0)-cos(t).sin(t0)].
In step 2, instead of providing the delay t0 to the output it is provided to the input x(t), giving x(t-t0). This is fed as input to the system which has the characteristic of performing the time scaling operation. The operation is taking the sinus of the time which is then multiplied by x. The time scaling operation is only performed on the time t itself, not on the constant t0. The resulting output of the system, therefore, is x.sin(t) - t0. This result is unequal to the result of step 1 above.
Therewith 1. is TV.
Correct me if I'm wrong. Thnx.
Using the same reasoning, I find 2 = TIV and 3 = TV.
Bro its not x.sin(t), rather it is x(sin(t))
So ur reasoning is not correct i guess. Correct me if i am wrong.
According to my best knowledge, this is just a notational difference, all three notations meaning the same thing, i.e. x(sint) means: "x multiplied by the sine of the value for t" where the multiplication is implied by the opening bracket ( after x; then next x.sin(t) means: "x multiplied (the dot .) by the sine of the value for t where in this case t is put between brackets ( ) to make the notation more clear, that is sin(t) instead of the seeming word sint which could mean something else such as saint; and finally your notation x(sin(t)) which also means: "x multiplied by the sine of t" where the multiplication is implied by the opening bracket ( after x.
If however, there is a difference between the three notations in that they produce different results, then please explain this to me. Also what would be the effect of your notation on the addition of the delay t0 before and after the system performs the time scaling operation? Thanks in advance for your response.
Super jiii .. it helped me a lot .....👌👌
Home work questions
Q1,2 are Time invarient & Q3 is Time invarient
In first example, Step1 ---> since Y(t) = X(2t), when the output Y(t) is delayed by t* shouldn't the output of the system be X(2t-t* ) and in the Step 2 ----> Just like the step 1 in the video????
yes i have the same question
Bro ur great
thank you dear for your video and learn this to we poeple. but i have question about : X(2t) I ask about your answer: that write this: x(2t-2t0)
please describe for me at here about my question. Thank you dear teacher
1-TV
2-TIV
3- Because cos t is coeff. it does not matter so TIV
3 is TV since the extra term i.e cost is not a constant
@@afsarabenazir8558 it doesnot matter .The only x(t) matters in determining the nature of the system.Watch previous lectures attentively.
sir plz for our confirmation plz also upload the answers of end problems
Wow I love this ❤😂🎉
Hello I want to ask, sorry if the question are little bit weird (because im still 12), but Delay by t。is mean what?, are basically mean t - t。?, and what is x(t) exactly?, what the paramaeter t do there?, are the value is actually the t and the x or y is just the name function?
all are time invariant. In 1st question, time shifting doesn't affect the result and in 3rd question, we only have to take x(t) because it is the input not cos(t).
Neatly done sir...
Very nice explanation thank you (:
Keep going. Reall nice
Thank you very much!
You are awsome sir
U R THE BEST
sir Did u r complete fouries series and transforms and laplce transforms in this course
1- TV
2- TIV
3- TIV
TV
TIV
TV
Bencho.......kal exam hai bachaliya sir aapne😉
قبول داریم تهدیدهای امنیتی دارند روز به روز مغلق ترو پیچیده می شوند عابد قاضی زاده
absolute excellence
1 =non causal
2=non causal
3=causal
🤡🤡
1.Tv system
2.Tiv system
3.Tv system
please upload the answers of home work problems
homework solving
1) TV
2) TIV
3)TV
Thank you
1.TV
2. TIV
3 TV
you are legend
Sir plz give the answers of the questions in the task
Thanks
1)TV
2)TIV
3)TIV
U r amazing
sir which model should v prefr on the basis of log likelihood value ..the time variant or time invariant ?pls answer
will delay apply to cost making it cos(t-to)?
For y(t-to) it will be cos(t-to)
But for x(t-to) only the input values will get affected e.g Cost.x(t-to)
lkk
@@MuddasirJahangir22 i think for x(t-to) it will be Cost+x(t-to)
really skilled to use mouse as a pen
Hi, in the first case, after going through the system the output y(t)= x(2t). Now if we provide a delay wouldn’t it be x(2t-to)? Similarly, in the second case the delayed input is x(t-to), and when this input is given to the system, wouldn’t it scale the whole parameter of the input and become x(2(t-to))? System is variant either way, but just for the clarification of the concept...
I agree with you but either way I don't have a clear answer for this.
bro, did you get the answer?
Thank u sir......
1. TV
2. T.IV
3. TV
1.TV
2.TIV
3.TV
IT's
1.TIV
2.TIV
3.TV
please check your answer
My solution for 1. was also TIV. Thnx for confirming.
But then again, it became TV after further reasoning. See above.
Avinash Dogra sir how 3 one became tv
Acc to me it should b tiv
Sir plz explain
it will be TV. check the 1st problem in the next video
second example should be time variant i suppose. Because after delay in output the result should be 2(t-t0)x(t-t0)
Vo + h , t nhi
x(t)->system->x(2t)->delay->x(2t-t0) why is this logic wrong for solution number 1?
can anyone one explain me mathematically the 3 question i.e, how y(t³) = x(t) is a TV system. Please mail me the picture of the solved problem. Thanks in advance
Guys tell me if you are getting some other answer to the H.W Qs.
1) Time Variant
2) Time Invariant
3) Time Variant
NITian/ IITian..!!
Please someone can write the conclusion i'm studing in frensh but i don't make diffrence between the TIV and TV i really need them i'll pass my exam on this week so please help me
1)T.V
2)T.I.V
3)T.V
I guess the first example is wrong. It is TIV because the output for x(t-t0) will be x(2t-2t0) and not x(2t-t0). The reason given in S-2 that the scaling applies to only the independent variable is wrong. The scaling applies to whatever is the argument inside x()
No, you guessed it wrong. The scaling is happening for time 't' only. Please watch the earlier lectures to understand these operations well.
if it's delayed by t0 why is it y(t-t0) not y(t+t0)??
It must be y(t+to)...I have no idea why Sir is taking y(t-to)!
t-to=0 then t=to(delay)
t+to=0 then t=-to(advance)
Hope it helps u .
@@kksrikrishna7906 thanks a lot
Why do we denote delay as negative? For eg if a system is taking 5 s and I give a delay of 5s...shouldnt that be 10s....so why are we subtracting...
It might be silly but please help
Somewhat Crazy
X(t-t0) is right shift, if we subtract it gets equated as t=t0 on othr hand x(t+t0) is left shift it gets equated as t=-t0, so fr delay as u said gets added up so cant b negative i.e it cant b t=-to hence we need t=t0 so u hv to take delay as x(t-t0) in order to get t=t0...
Hello, could you explain please why the delay is substracted but not added?
delay means behind something so negative sign is used.
Daiict student attendance here
Can anyone let me know the physical significance of Time variance? what does it represent?
1,3 tv
2 tiv