5V to 1.5V Converter for Wall Clock

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  • Опубліковано 5 чер 2024
  • This circuit is very simple and can be used to run any wall clock for years.
    This circuit has many other applications where 5 volts to 1.5 volts conversion is needed such as in toys etc.
    The Schematic includes only three main components
    BC547 Transistor & two 10K Resistors
    A 18650 Battery is required to run the circuit or any source can be used such as a 5V charger. This circuit has a tendency to tolerate 12V input and convert it into 1.5 volts easily.
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  • Наука та технологія

КОМЕНТАРІ • 89

  • @Vic7bd
    @Vic7bd 27 днів тому +7

    Тоже самое делал, но применяя спец. стабилизатор SMD. И лучше было бы крепить снизу, а не сбоку, т.к. противовес будет не верный.

  • @ekpower
    @ekpower 28 днів тому +11

    The title should be 3.7V to 1.5V for wall clock not 5V which is using USB power input. Its clearly mislead.

  • @noelaruldas1152
    @noelaruldas1152 26 днів тому

    Thank you very much for the video!

  • @lmwlmw4468
    @lmwlmw4468 26 днів тому

    Great idea.

  • @kosolh
    @kosolh 27 днів тому

    Thank you.

  • @JustMe-dx5xl
    @JustMe-dx5xl 29 днів тому +15

    The sooner UA-cam bring back the thumbs down count the better so rubbish like this does not get recommended will make UA-cam a useful site again.
    Circuit analysis:
    SIMPLE ......... nothing more than a emitter follower voltage divider which does not do what the creator claims.
    Calculate: Output Voltage = ( R1 / (R1 + R2)) X Vin - Vbe drop of transistor.
    3.7 Volt input = approx 1.3 Volt output (dependent on load current draw)
    5 Volt input = Approx 2 V output (dependent on load current draw)
    12 Volt input = Approx 5.5 V output (dependent on load current draw)
    If a creator does not explain their circuit or verify with calculations they have no idea about what they are talking about. Not even a multimeter to proove output voltage !

    • @srh2301
      @srh2301 28 днів тому +3

      The Firefox AddOn "Return UA-cam Dislike" brings back thumbs down. They do still exist, the display in your browser is just supressed. Btw, for the price of one average 18650 I get 10-15 standard AA batteries in my local supermarket. This is sufficient to run the clock for around 20 years in theory. Without any botched job. I hope the 18650 also will run for about 20 years until the first recharge is needed... 🙂

    • @sergeysydorov5410
      @sergeysydorov5410 26 днів тому

      @@srh2301 это точно!

    • @JustMe-dx5xl
      @JustMe-dx5xl 25 днів тому

      @@srh2301 Unfortunately the add on only uses extrapolated data & not real data. It also has no feedback or affect on the UA-cam algorithm which recommends videos.

    • @xuanuchoang8970
      @xuanuchoang8970 12 днів тому

      Ok

  • @jorgeaparicio4762
    @jorgeaparicio4762 26 днів тому +2

    There is another issue that it is not Electronic :
    If you glue the battery on a side position, the clock will unbalance and turn around its centre.
    It should be glued at the center top, so to point a bit inclined (tilt) with an angle towards ground . But centered correcto y to preserve balance.

  • @user-rb2iy2mk2j
    @user-rb2iy2mk2j 29 днів тому

    Gracias

  • @DavidCase-ov5uo
    @DavidCase-ov5uo 21 день тому +1

    What’s the point? A lithium battery will self discharge over a period of time (!). A Alkaline cell runs for at least a year and the shelf life of an alkaline is several years if not yet used.. In addition the voltage regulator will also drain the lithium cell.

  • @vivetu
    @vivetu Місяць тому +9

    And serial 3 diodes 1N4007? It works too and it is more simple to built isn't it?

    • @tijitwar7071
      @tijitwar7071 29 днів тому

      How?

    • @Max_Carabelt
      @Max_Carabelt 29 днів тому +1

      yes with capacitor

    • @sohotcall
      @sohotcall 27 днів тому

      @@tijitwar7071 Battery 18650 is 3.7V. Each diode 1N4007 drops voltage by 0.7V. Thus, resulting 3.7V - 3 * 0.7V = 1.6V.
      The battery should use 1S BMS battery protection to avoid over discharge.

    • @sergeysydorov5410
      @sergeysydorov5410 26 днів тому +1

      5-0.7-0.7-0.7=2.9V
      2.9=1.5 ?

    • @K2teknik.
      @K2teknik. 25 днів тому

      The issue is to build an efficient circuit, the shown circuit is not, nor using diodes.

  • @g.k.6451
    @g.k.6451 Місяць тому +1

    👍👍👍

  • @Freeman666Gordon
    @Freeman666Gordon 29 днів тому +1

    Dropper capacitor with rectifier from mains is much more effective device for this, just calculate and insulate it properly.

    • @JustMe-dx5xl
      @JustMe-dx5xl 29 днів тому +2

      And much more dangerous as clock is not isolated from mains.

    • @Freeman666Gordon
      @Freeman666Gordon 28 днів тому +1

      @@JustMe-dx5xl should wall clock mecanism be daily touched by everyone? Just unplug its cord from AC socket before adjusting time.

    • @Freeman666Gordon
      @Freeman666Gordon 27 днів тому

      @@JustMe-dx5xl also, these cheap mechanisms have no exposed metal parts but contacts in battery holder the whole circuit with end of power cord can easily fit into and be sealed with blue tape.

  • @МихаилМирошниченко-ю3щ

    Зачем городить огород если есть специальный стабилизатор 6206а с выходом 1,5 вольт,причем с очень низким потреблением.Входное напряжение от 3-х до 6 вольт,подходит как раз для переделки часов на литиевый аккум.А в данном случае транзистор много потребляет

  • @abubakarshaikh1638
    @abubakarshaikh1638 28 днів тому

    Very nice and very compact circuit...

  • @SooriyanCinema
    @SooriyanCinema 29 днів тому

    How to buy this device or where to buy this one?

  • @Vit_Kh
    @Vit_Kh 29 днів тому +1

    1117-1.5 enjoy

  • @incognito7882
    @incognito7882 11 днів тому

    No sería más fácil poner una pila recargable de 1,5 voltios?

  • @SebastianXD-hc7nl
    @SebastianXD-hc7nl 22 дні тому

    Output current?

  • @vencdee
    @vencdee 12 днів тому

    Constant drain of 0.2mA and risk of over discharge of the cell. Rather use diodes in series or other passive way. Or Mosfet instead simple transistor.

  • @rajeshkumrpshah
    @rajeshkumrpshah 28 днів тому +2

    In your first ad 5 volt in put but you are showing in video 3.7 v battery. Please let me tell about what is correct

  • @rishisheikhar8518
    @rishisheikhar8518 27 днів тому +1

    power loss kitna hai..

  • @mlikogito1954
    @mlikogito1954 29 днів тому +3

    Cześć! Mogę powiedzieć że realizujesz mój pomysł ☺️ ponieważ ja stosuję go już od wielu lat.
    Początkowo też stosowałem dzielnik napięcia, ale później zastosowałem 3 lub4 diody (np. 1N4148) w szereg z zasilaniem zegara - należy dobrać doświadczalnie.

  • @mikebond6328
    @mikebond6328 29 днів тому +6

    If only there was a clock that needs 5 volts input.

  • @mikebond6328
    @mikebond6328 29 днів тому

    If only there was an ic that could do this.

  • @robsonmontoya4311
    @robsonmontoya4311 28 днів тому +4

    This batery is 3,7 volts, not 5 volts

    • @sergeysydorov5410
      @sergeysydorov5410 26 днів тому

      как я понял, там драйвер 18650.

  • @carlosceschini4104
    @carlosceschini4104 28 днів тому +1

    E se a gente coloca uma pilha de 1,5 V e mede com um microamperímetro o consumo e depois coloca uma resistencia que com 5V deixe passar a mesma amperagem se evita toda essa construção.

    • @Hudsonkem
      @Hudsonkem 28 днів тому

      né, tem tanta forma de fazer sem precisar usar um transistor.

    • @carlosceschini4104
      @carlosceschini4104 28 днів тому

      @@Hudsonkem um zener de 3.5v em serie?

    • @Hudsonkem
      @Hudsonkem 28 днів тому

      @@carlosceschini4104 não daria certo, o zener é um estabilizador de tensão por assim dizer, vc precisar fazer um divisor de tensão só que ao invez de dois resistores você vai usar um resistor em seria com a carga ao mesmo tempo que o zener vai esta em paralelo com a mesma carga. vc pode usar aqueles calculos simples de resistor para LED, vou chutar um valor de 100k Ohms por exemplo. (5v-1.5v)/0.00005A=70000 ohms. se o consumo do relogio for em torno de 50µA ou seja, um resistor de no minimo 70k ohms em serie.

    • @carlosceschini4104
      @carlosceschini4104 28 днів тому +1

      @@Hudsonkem
      Os 5V da fonte menos a tensão de zener de 3.5 V teremos os 1.5V que precisamos para alimentar o relógio independente da sua carga que atuará como uma resistência em série fechando o circuito.
      O consumo do relógio é ridículo pena que disciparemos uma potência de
      3.5V × i (r) = Wz em calor.

  • @hendrikslijkhuis86
    @hendrikslijkhuis86 29 днів тому +1

    gewoon één weerstand van 10 k er tussen en spanning meten en anders twee er tussen en aanpassen.

  • @test-rj2vl
    @test-rj2vl 28 днів тому

    If it can take 5v and output 1.5v then better ditch the battery altogether already and use 5v usb charger for infinite power.

  • @vulutherockstar.
    @vulutherockstar. 27 днів тому

    Can you make 9v volt amplifier for fm radio

  • @SouthGBA
    @SouthGBA 29 днів тому +2

    Next idea: how about using a capacitor or supercapacitor instead of a battery? 🤔

  • @ianhosier4042
    @ianhosier4042 Місяць тому

    Surely simpler to use a nimh rechargeable AA cell?

    • @k4hin918
      @k4hin918 29 днів тому

      Yes. I have been using the same nimh battery for 15 years.

  • @user-pm8jb6mw7i
    @user-pm8jb6mw7i 28 днів тому

    Can anybody explain me why clocks like these start to go forward or backward? I have one that used to go back, then went OK and lately goes forward???? Does temperature or humidity has anything to do with that?

    • @DavidCase-ov5uo
      @DavidCase-ov5uo 21 день тому

      Don’t know about a battery clock but a mains clock can go backwards as they have a start up capacitor that kicks the motor into life. If you turn it on at a certain point in the mains cycle then it can be kicked in the wrong direction mains clocks use an AC motor.

    • @user-pm8jb6mw7i
      @user-pm8jb6mw7i 21 день тому

      @@DavidCase-ov5uo By "goes backward" I mean it stays back in time.. not that that the hands go counterclock...

  • @ranjankumarbhattacharyya9941
    @ranjankumarbhattacharyya9941 Місяць тому

    Full charge karneke baad kitna hrs chalneke bad fir se charge karna parega 18650 battery ko?

  • @davidfalconer8913
    @davidfalconer8913 28 днів тому +1

    I will try this ... but .... These style of videos NEVER add a circuit diagram ( why ? ) .... this would help building and also appraise the circuit ( a multiple diode dropper would be SO MUCH simpler ! ) Electronic engineer = DAVE™🛑

  • @muhammadshahid-ww7db
    @muhammadshahid-ww7db 28 днів тому

    Sir i want 1.80v output not 1.50v pls make it video thanx

  • @yatspb2612
    @yatspb2612 15 днів тому

    Пользуюсь более простой схемой: один кондей и один резюк. Недавно выяснил, что разные механизмы могут иметь разные потребности. Поэтому сначала вместо резюка впендюриваю потенц и определяю какого хрена ему надо. И только потом впендюриваю именно нужный по размеру резюковый хрен.

  • @sanitaires
    @sanitaires 25 днів тому

    Ток покоя?.

  • @isoria07
    @isoria07 Місяць тому +1

    Your video title is 5V to 1.5V and you are using a 18650 battery (3.7V) Is this good for 5V input also ?

    • @AuxticsTechnologies
      @AuxticsTechnologies  Місяць тому

      Yes of course it can be used with 5V

    • @isoria07
      @isoria07 29 днів тому

      @@AuxticsTechnologies Thanks

    • @JustMe-dx5xl
      @JustMe-dx5xl 29 днів тому +1

      The circuit as presented will NOT work for 5V input. It will output around 2 Volts rather than 1.5V

    • @isoria07
      @isoria07 28 днів тому

      @@JustMe-dx5xl Ok thanks, but what to change to get to 1.5V ?

  • @marcelobahl7655
    @marcelobahl7655 29 днів тому +2

    Mostra 5Volts mas faz uso de apenas 3,7 V consequentemente ao fazer uso de 5Volts esta tensão de saída será maior que os 1,5V mostrado, caso ainda queira fazer o circuito, utilize um LM317, mais estável e confiável e poderá fazer uso normalmente dos 5 à 9 volts sem alterar a saída em nada. Boa sorte

  • @kgs9291
    @kgs9291 28 днів тому

    how to charge this

  • @jorgealvesdocarmo8748
    @jorgealvesdocarmo8748 15 днів тому

    Não seria melhor colocar a pilha certa

  • @derymaulana7198
    @derymaulana7198 27 днів тому

    I never buy bc547 for FM transmiter homemade, and i like

  • @albertoemiliosiles9900
    @albertoemiliosiles9900 28 днів тому

    Perfecto , la salida es 1,48 v ; pero la entrada nunca la mediste .

  • @ketas
    @ketas Місяць тому +2

    is it a wall clock? so wire it to mains!

  • @shaikibrahim2304
    @shaikibrahim2304 13 днів тому +1

    Video is rong

  • @SHShahab
    @SHShahab 6 днів тому

    5 V to 1.5 V ? better to correct the title to : 3.7 V to 1.5 V !

  • @Devendradixit125
    @Devendradixit125 Місяць тому

    Bol bhi diya karo yaro

  • @mikebond6328
    @mikebond6328 29 днів тому +1

    That don’t make no sense.

  • @user-ee1ou8lq8q
    @user-ee1ou8lq8q 11 днів тому

    Какая глупость, купи аккумулятор по типу используемой батарейки в ЧАСАХ и зарядное к нему. И ни каких проблем, а с этой байдой надо ещё баланс подобрать так чтоб часы ровно висели.

  • @zhenniurthpiteruriel
    @zhenniurthpiteruriel 27 днів тому +1

    👎🏻👎🏻👎🏻👎🏻👎🏻👎🏻
    Fake.

  • @vencdee
    @vencdee 12 днів тому

    Constant drain of 0.2mA and risk of over discharge of the cell. Rather use diodes in series or other passive way. Or Mosfet instead simple transistor.