Balanced and Unbalanced Bridge Circuits
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- Опубліковано 8 лип 2024
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This video explains how Thevenin's Theorem can be applied to simplify specific circuits. The type of circuit being simplified in this example is called a Bridge circuit (Wheatstone Bridge) and Thevenin's Theorem is used to firstly find the Thevenin equivalent circuit and then to determine whether or not the bridge is balanced.
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This is the first time ive been able to clearly visualize this analysis method ever, right before my major exam at that. Thank you.
Glad you found it helpful, Abraham - best of luck with your exam.
You saved me from one my greatest confusion that I never knew how to come out of, thank you!
This is really well done! Thank you for going through the step by step.
never seen a better explanation than this . Thank you so much.
The resistance redrawing blew my mind... man... it socks to be as stupid as I'm for not being able to see the circuit like that from the beginning
Thank you so much! This helped me a lot!
Great content, sir. Thank you.
Thanks, man. Now I understood it.
Great video. Thanks for the effort.
Great video!
Thanks so much sir u have safe my grades
Thanks it really helped 😀
thanks a lot for simplifying
You are the star brother.. 🎉
Thank you!!!!
Excuse me, why? we choose R3 and R4 , so R1 and R 2 how? . We take V4 - V3 , why? I dont understand, hope so u reply!!
low volume
love that
Please answer my question if the question is find current across this resistor instead of voltage. Then what is the formula to find mid current? Kindly answer please
Ohm's Law: Current = Voltage divided by Resistance
why is the vltage through R3 and R4 the same as the points at which we want the voltages for?
If we take point D as being 0V, then the voltage at point A must be equal to the voltage measured across R4, relative to point D. Likewise, the voltage across R3 gives the voltage at point B.
What if R_L isn’t given
Hi Francisco, though we do use RL to calculate the value of current at the very end of the video, you'll notice that RL isn't required to calculate the Thevenin Equivalent circuit. In the absence of RL, this would just be an open circuit at the end, without RL, and the terminal voltage would be VTH.
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