Wheatstone Bridge Problem

Physics Ninja shows you how to solve for an unknown resistance using a Wheatstone Bridge. We first use Kirchhoff's rules to get an expression for an unknown resistance and then look an at example problem

[@AARUSHI-iz6vf]

Example 1- 750 ohms
Example 2- 55.5 ohms
Thanku so much for that explanation

[@divineobot1605]

Ahhhhh.....I'm just going to be more truthful right now. You are the only person who has been able to explain this to me😭😭😭😭😭😭, thank you so much sir. God Bless You. Please don't stop bringing out videos like these. Thank you so much sir.

[@judyhopps1324]

Thanks for suggesting! It's really helpful 😁

[@WhySoGhostly]

hi. RA is my (RX) whilst my RB is my variable resistor. RC and RD are known. How would I go about calculating this?

[@nitinshikare215]

high precision Wheatstone bridge are capable to measure the resistance between ?

[@cubes7242]

thanks mate. got ready for my test

[@TheVirtualLab]

Thanks so much! My university professor did not explain this well at all, but with this video I now completely understand it.

[@kanchanthakurkt8437]

Love you
What an explanation......
👍👍👍👍

[@Ailmas4545]

Thank you so much
750ohm
55.5 ohm

[@zaidenRYUZAKI]

If R3 doesnt showed/tell any kilo ohms or ohms... How to solve it?

[@user-yc5mw1ww2x]

thank youu so much I finally see why those potential differences are equal ! my uni professor couldnt be more useless

[@PhysicsNinja]

Thanks! You got this!

[@thineshkumaranananthan]

Thank you sir !

[@trackfieldworld_s.g8767]

When the current flow through the resistor and the current is opposing the loop direction. Shouldn't the voltage drop be positive and not negative.

[@RamisaAnjum]

Thanks a lot !

[@seungminlee5037]

Thank you for your video explanations.
im not goot at neither physics nor english,
but you helped me both !!!! \^-^/

[@user-kw7hs3bu7w]

I have AB=1ohm, BC=4ohms, CD=5ohms, DA=3ohms and AD=2ohms.
Find value of current in branch AB, AD, and BD

[@magnusmeldgaard9089]

Kirchhoff’s loop rule states that if you travel against the current over a resistor, then +IR and if you travel with the current over a resistor then -IR. So im confused as to how you get the opposite at 4.20 in your video

[@abenphilip4283]

Yea..
I think he switched the signs...

[@silverubica]

Basicly its same thing,if u go your way E-I1R1+I3R3=0 or if u go his way E=I1R1-I3R3 he just should wrrite at end E not 0.I also use this way,if u have + of E following the direction of loop it will stay +,also if your current follow direction of loop on resistor it will be +,but u will write +E=+IR and not +E+IR

[@tyronekim3506]

Simple and concise explanation. Thanks.

[@user-jx9mx9fl3l]

Thanks sooo much merrr

[@Ra-Endimion]

Seems to help, let's see if I retain it

[@Funyt2006]

Thanks bro

[@nsk6914]

Is it ok to arrnge the r1 r2 r3 rx randomly

[@PhysicsNinja]

No! Be careful. If it’s balanced only some ratios will balance the bridge

[@nsk6914]

@@PhysicsNinja how to find the parallel equivalent resistance and capacitance

[@jadlakkis5795]

Actual king

[@unheardvoice6217]

thanx

[@Frostoo7]

Ex1 Rx = 750 ohms Ex2 Rx = 55.5 ohms. Is this corrects? Perhaps you could have showed us the answers on your video😬

[@PhysicsNinja]

Boom, you’ve mastered the Wheatstone bridge! Well done.

[@kanchanthakurkt8437]

Yeah me too

[@anuja6990]

ex 1 x=750
ex 2 x=55.5
is it right??

[@PhysicsNinja]

Nicely done!

[@rohith.n5413]

❤😊

[@robinhossain5073]

From Bangladesh

[@walterharrison1555]

Example 1: Rx= 75 ohms, example 2: Rx=55 ohms

[@PhysicsNinja]

Ex 1: 750 :) close enough

[@jousif650]

8:09 for lazy people. Jump there :)

[@hercules1066]

🖕🏿

[@jdog9025]

Exteremly Confusing

[@503jmn]

15 goes into 900, 60 times. Missed a 0 in your example. Because 6 times 50 is only 300

[@503jmn]

But great video none the less.

[@acayipisler2458]

Türkçe anlat lo