Centripetal Acceleration & Force - Circular Motion, Banked Curves, Static Friction, Physics Problems

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  • Опубліковано 10 січ 2025

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Рік тому +28

    Circular Motion - Free Formula Sheet: bit.ly/4gIUL3r
    Physics 1 Final Exam Review: ua-cam.com/video/CwkhvFlNFp0/v-deo.html
    Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html

  • @iconic410
    @iconic410 4 роки тому +2577

    Timestamps for this lesson:
    Note: He sometimes teaches concepts(Kepler's third law, tangential acceleration...)during the practice problems so make sure to look out for those
    0:00 - Intro
    0:15 - Centripetal Force
    14:31 - Centripetal Acceleration
    15:22 - Period and Frequency
    16:32 - Tangential Velocity
    32:40 - Vertical Circle Problem(Varying centripetal acceleration)
    1:10:59 - Gravity and Newton's Law of Gravitation
    Problems:
    1. 18:50
    2. 23:42
    3. 26:27
    4. 35:26
    5. 38:05
    6. 40:17
    7. 46:31
    8. 50:15
    9. 58:12
    10. 1:01:41
    11. 1:07:31
    12. 1:15:51
    13. 1:22:29
    14. 1:24:35
    15. 1:31:22
    16. 1:36:53
    17. 1:43:24
    18. 1:47:45
    19. 1:50:34

  • @chovvyy
    @chovvyy 6 років тому +2010

    I know it’s too much too ask, but timestamps in these kinds of long videos would be extremely helpful. Other than that, very well explained and you’re a without a doubt a lifesaver!

    • @tx2sirk466
      @tx2sirk466 6 років тому +3

      Sad Toad +

    • @rei___l
      @rei___l 4 роки тому +15

      click open transcript in the three dots next to the save button, you'll see timestampss

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      but you are Elon Dusk surely you know like everything :)

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      @@rei___l that does not help bruh

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      @rei___l 4 роки тому +3

      @@cactus8911 why not

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  • @DC-qk7hx
    @DC-qk7hx 4 роки тому +18

    I'm just curious why the problem at 45:00 does not use formula FT = sqrt(FTx^2 + FTy^2), taking into account the effects of gravity

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  • @therandomperson9627
    @therandomperson9627 6 місяців тому +1

    1:01:30 the answer for net acceleration is done right but due to intermediate rounding the answer became off by 0.4 In this scenario, 0.4 is a slightly large difference since the answer itself is less than 10. Rather if a direct input of the v^2/r in the Pythagorean equation then it would yield about 5.26. You taught the right way but it was just off due to rounding. But still you helped me learn how to approach these problems

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  • @roberto3196
    @roberto3196 6 років тому +10

    Great video, but one question. At about 46:28 did you just not count the tension force for the Y component when calculating the overall tension force because the Y component tension is almost negligible? I counted the Y component and got 29.7 N instead of 29.6 N.

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  • @kabouch
    @kabouch 3 роки тому +3

    8:49 in this example, I would think that the normal force is balanced by a force of the magnitude of mgcosΘ and in an opposite direction; while, the acceleration along the direction of the velocity is due to a net force equal to the (mgsinΘ-friction) force. At the initial point when the moving object is no longer in touch with the ground i.e. when the gravitational force is not balanced by the normal force, the object accelerates downwards by gravity.

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  • @picturebazzare
    @picturebazzare 4 роки тому +2

    The force causing the vertical acceleration comes from the centrifugal force. This causes the
    swings to move at a faster speed which then ultimately leads to the swings moving outwards and,
    in the direction, going up.

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  • @andrewpq5149
    @andrewpq5149 2 роки тому +3

    35:21 I got a question. Shouldn't the forced acting on the ball at point A be T-Fg because only T is pointing towards the circle. Point C should be T+Fg because both T and Fg are providing the centripetal for, so they should both be positive

  • @picturebazzare
    @picturebazzare 4 роки тому +3

    The circular motion and, the effect of magnitude of radius on the time period of an object was
    investigated in this practical. According to this the relationship between the radius and the period
    as follows,
    T
    2 = r
    According to the collected data it was able to prove that above statement.

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  • @ArcherGabs
    @ArcherGabs 6 років тому +6

    Hey I think you made a mistake at around 35:00, the tension at the top is equal to the sum of the weight force and the centripetal force, and the difference of them at the bottom.

    • @DavidGarcia-ve2ll
      @DavidGarcia-ve2ll 5 років тому

      Archer i’m thinking the same thing too but thinking about it it kind of makes sense because at the top the tension would be less than the tension at the bottom since gravity is helping the fc at the top and relieving tension, and at the bottom fc is trying to go up wards and gravity is pulling the opposite direction, increasing the tension. so the tensions there should be T at point A>C which proves his equation but i also get what you mean so i’m very confused lmao

    • @ralphanthonymallillin2712
      @ralphanthonymallillin2712 3 роки тому +1

      Nope..actually it'a correct...he said that centripetal forces are positive when the direction is seekin to the center of the circle..He wrote it as Fc=T+Mg at the top since both Mg and T are directed through the center..and Fc=T-Mg at the bottom since T is directed through the center and Mg is away from the center :)

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    @evanjones9602 4 роки тому +12

    Is anyone else watching this the day before their big physics test over centripetal force, acceleration, and gravitation?

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    @saraassaf892 6 років тому +7

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  • @user-clouddy
    @user-clouddy 2 роки тому +1

    it has been 5 years that u made this video. I am not sure whether u r gonna answer my question or not. But still, (56:39) u solved Normal Force equals to mg/cos. What makes it different from the other questions that the normal force was usually mg x cos? why makes the normal force to be mg/cos? Also, Thank you for making these videos. I like how u explain the general concept first and then u solved questions that are related to the concepts that u just taught.

  • @kal7708
    @kal7708 8 років тому +16

    At 36:43 isn't it supposed to be T+mg=Fcg for the top and T-mg for the bottom?

    • @martin6320
      @martin6320 8 років тому +1

      yes, because mg points downward along with Tension at the top.

    • @saadrehman362
      @saadrehman362 7 років тому +3

      yes it is, be he put the equations in terms of Fcg. "Fcg=..."

    • @timothyc2346
      @timothyc2346 4 роки тому

      S. R. Oooooo, makes sense now. Thxs

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    One thing that really helped me understand the free-body diagrams is that remember that fNET= Fac all the time. So in the roller coster example, at the bottom, Fnet= Fac= FN-mg and then at the top it is Fnet = Fac = mg - FN

    • @ro1882
      @ro1882 4 роки тому

      arham siddiqui what do you mean by fac? I guess i have studied too much and am starting to mix things up

    • @arhamsiddiqui7083
      @arhamsiddiqui7083 4 роки тому

      @@ro1882 i meant force of centripetal acceleration

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  • @greatpharoh0303
    @greatpharoh0303 5 років тому +9

    Slight correction for the teatherball problem, for T x all you use is mv^2/r and T y is mg so you get 29.6 and 2.45.
    By pathagorean T = 29.7N right?

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    @shirayokidono3356 4 роки тому +3

    1:07:10
    I want to understand. you said that if the speed exceeds the value that makes the normal force equal to zero it's going to fly off the road. but if the normal force was already 0 the car will lose contact so the normal force needs to be little more than zero, not exactly zero. isn't that?

  • @hasanciftci9432
    @hasanciftci9432 5 років тому +1

    I had exactly that question. The question ask me the acceleration which i calculated and find 4 m/s2. But in answers i saw in two choice the number 4. The first: constant, with a magnitude of 4 m/s2 the second 4m/s2, pointing the center of the circle. Thanks God that i watch your video.

  • @PenandPaperScience
    @PenandPaperScience 3 роки тому +2

    For those that might want some more Real Life Problems on Circular motion, I just released a video where I solve such problems step-by-step. It might help some of you :)
    ua-cam.com/video/O2pqU_n-8j8/v-deo.html

  • @rahipatel7285
    @rahipatel7285 4 роки тому +2

    WIsh me good luck I have my test right now, Btw thank you for these videos otherwise I would be failing Right now lol

  • @bhavana9618
    @bhavana9618 6 років тому +1

    A perfect teacher doesn't exi....

  • @mellomilky8621
    @mellomilky8621 3 роки тому

    This guy deserves a spot in my uni

  • @sikubokum5960
    @sikubokum5960 8 років тому +25

    you're awesome bro! Keep up the good work!

  • @habunali415
    @habunali415 6 років тому +3

    Thank you sooo much, you don't know how much you helped me in these topics 💟💟💟💟💟

  • @thethtar9264
    @thethtar9264 6 років тому +8

    At about 40:00, I solved the problem by using F= mv2/R which is totally different from his solution. But still I get the same answer as his. Is my solution a right way? If not, why?

    • @ashaa9855
      @ashaa9855 6 років тому

      Same here. Idk if I​ just got lucky or what

    • @boxman_ninja0819
      @boxman_ninja0819 6 років тому +1

      The equation he used is just a manipulation of the f=mv2/R equation. So he did the same thing you did just simplified it

    • @kylejohnson8447
      @kylejohnson8447 6 років тому

      He just solved for v in that equation...

  • @NdeCasper
    @NdeCasper Рік тому +1

    Thank you Mr with the good work, more energy with this vibes

  • @harjindersinghjanda8644
    @harjindersinghjanda8644 Рік тому +1

    Mind blowing, it really serves the purpose, thanks 👏

  • @Josh-pm4qx
    @Josh-pm4qx 5 років тому +3

    Just wanna say thanks for the videos they are extremely helpful

  • @gracemcpadden839
    @gracemcpadden839 3 роки тому +1

    THANK YOU!! I missed these lessons in school due to covid 💕

  • @Chris15430
    @Chris15430 4 роки тому +1

    i fricking love you man. If i get rich ill make sure youre compensated

  • @tatiana1310
    @tatiana1310 4 роки тому +3

    35:05 Somebody could help me? Why they are both negative if they are pointing to the center (positive)?

    • @ralphanthonymallillin2712
      @ralphanthonymallillin2712 3 роки тому +1

      Nope..actually it'a correct...he said that centripetal forces are positive when the direction is seekin to the center of the circle..He wrote it as Fc=T+Mg at the top since both Mg and T are directed through the center..and Fc=T-Mg at the bottom since T is directed through the center and Mg is away from the center :)

  • @mrssyrc
    @mrssyrc Рік тому

    YOU ARE THE BEST! THANK YOU SO MUCH FOR MAKING MY LIFE EASIER!!!!! 💗 BTW, I LOVE YOUR VOICE!!! IT'S LIKE MUSIC TO MY EARS.

  • @jeremyzhang6765
    @jeremyzhang6765 4 роки тому +3

    i love you bro you legit are a life saver i owe you so much