How to determine if a function graph has an inverse and if the inverse is a function

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  • Опубліковано 5 січ 2025

КОМЕНТАРІ • 79

  • @allieramirez162
    @allieramirez162 3 роки тому +21

    Mr. Sir I am in college and my college professor was trying to teach this to the whole class and we were all confused …. when you explained it, it was so much easier to understand … you have helped me since I was in high school and i just wanted to say … you are literally the best !

  • @Hanulwalker
    @Hanulwalker 6 років тому +55

    This is so help full, I learn thing here in 10 minutes, thing my teacher takes at-least a full hour of class to teach.

  • @greaserboy4614
    @greaserboy4614 2 роки тому +4

    You honestly have a unique gift, and that is explaining and teaching. Thank you for the time and hard work your put into every single video. I, among others, appreciate it.

  • @randomthoughts6875
    @randomthoughts6875 4 роки тому +9

    You're such a life saver🥺 you teach better than thousands of teacher

  • @ilovereadingwuxiaxianxiaat8994
    @ilovereadingwuxiaxianxiaat8994 6 років тому +12

    *wow!*, my teacher took the whole period teaching me this in a way 10x harder to understand. But after this video, I understand
    so much better :). Thanks!

  • @TheHonchoofAllSpearheads
    @TheHonchoofAllSpearheads 5 років тому +3

    6:13 because as mentioned previously, the horizontal line intersects the original function's graph at two points, hence the function is many-to-one relation = No Inverse Fn.

  • @hanifrafli4736
    @hanifrafli4736 4 роки тому +6

    1:49 very satisfying sounds of whiteboard markers

  • @aligu7
    @aligu7 Рік тому

    Videos from 2015 are very helpful, thanks for effort !

  • @starinsky2873
    @starinsky2873 6 років тому +6

    Brian you explained better than khan academy lol😂😂😂 cause you combined all the steps i learn then it made clear for me to understand

    • @brianmclogan
      @brianmclogan  6 років тому +2

      happy to be able to help you out William

  • @nataliepassus9064
    @nataliepassus9064 8 років тому +17

    Love you videos. They are very helpful and have really helped saved me in my precalcs homeworks and studying

    • @brianmclogan
      @brianmclogan  8 років тому +1

      awesome! happy to help you out!

  • @annavisagarVLOGS
    @annavisagarVLOGS 2 роки тому +1

    Im so slow in math and i repeat and pause but i understand well, thank you, i like the way you explain it , 🙏

  • @magicjohnson1622
    @magicjohnson1622 4 роки тому

    Hey Brian, Thanks so much I've watched 10 of your videos. Online learning is much easier with your videos thank you.

  • @joefanningartist
    @joefanningartist 3 роки тому

    Brilliant math teacher, I think he's the best on the Internet

  • @JamesBrodski
    @JamesBrodski 3 роки тому

    Amazing video. You explained it beautifully.

  • @tusharamreliya5250
    @tusharamreliya5250 2 роки тому +2

    Johnny got an another profession 😆

  • @hwang_kimi9169
    @hwang_kimi9169 4 роки тому

    thankyouuu so much sir,,god bless you❤️❤️

  • @fvckinrad6882
    @fvckinrad6882 4 роки тому

    This saved me so much, thank u so much man, will be needing you in the future lol

  • @FunFactopias-Facts
    @FunFactopias-Facts 3 роки тому +1

    Thank you so much!

  • @cjsimon2356
    @cjsimon2356 5 років тому +2

    u explained it better than my teacher damnnnn

  • @isabellestables5416
    @isabellestables5416 5 років тому +1

    I learnt a lot, thank you

  • @raghavbhatia3231
    @raghavbhatia3231 6 років тому +1

    Very helpfull sir.....

  • @neelpatel5703
    @neelpatel5703 6 років тому +1

    Very helpful thank you

  • @sidneyremshik
    @sidneyremshik 4 роки тому +1

    good luck on your test tomorrow!

  • @thatomofolo452
    @thatomofolo452 Рік тому

    great👍👍

  • @USER-s9r9l
    @USER-s9r9l 4 роки тому

    this guys great! thank you sooooooo much!!!

  • @stefankljaic2884
    @stefankljaic2884 5 років тому +1

    bless you sir

  • @Iddy267
    @Iddy267 2 місяці тому

    how do you do this algebraicly tho? Sometimes you dont have a way to graph it, or at least not in a fast manner of time.

  • @taonamvududu6494
    @taonamvududu6494 3 роки тому

    Thank you sir

  • @thomasf915
    @thomasf915 7 років тому +1

    You. Are. A. Life. Saver. WOOO

  • @vishgouravelli4264
    @vishgouravelli4264 4 роки тому

    Thanks

  • @blisterycrane6963
    @blisterycrane6963 4 роки тому +6

    i watching this now, cause i just stuffed my functions test.

  • @jillmont3342
    @jillmont3342 2 роки тому

    THANK U

  • @caesar1512
    @caesar1512 6 років тому +1

    Thanks buddy

  • @donny5429
    @donny5429 3 роки тому +1

    3:10 that sound

  • @khalidashzz
    @khalidashzz 7 років тому

    thx a lot 😍😍😍

  • @hussainshivaan419
    @hussainshivaan419 6 років тому +1

    thanks alot

  • @strive7612
    @strive7612 6 років тому +1

    goat teacher.

  • @mereditha6597
    @mereditha6597 5 років тому +4

    Not all heroes wear capes.

  • @jennyke8080
    @jennyke8080 4 роки тому

    Please help the following:
    Find the inverse of f(x)=1-|2ln(x-1)|, restrict if necessary.
    There is no inverse function for this one since there are 2 roots if f(x)=0
    Is it right? Please help.
    How to do with piecewise function?

  • @Siphephelomaseko9
    @Siphephelomaseko9 Рік тому

    y = 1−2

    x +3

  • @nurulwahida9049
    @nurulwahida9049 4 роки тому

    Thankyouuuuu

  • @user-gp2bh6jh3k
    @user-gp2bh6jh3k 6 років тому +2

    LEGEND

  • @مامۆستامحمدبیرکاری

    hi.y=x^2 is not one to one
    you can finde inverse or not

  • @_____758
    @_____758 4 роки тому

    thank goodness. i get it now

  • @lightdax3568
    @lightdax3568 4 роки тому

    your right it is kindu cool

  • @sarrveshraaj9054
    @sarrveshraaj9054 5 років тому

    Tq sir

  • @vishuchaturvedi5953
    @vishuchaturvedi5953 3 роки тому

    MY SCHOOL USED UR VID TO SHOW US HOW TO DO OUR PROJECT LOL

  • @sarah821
    @sarah821 5 років тому

    Can I change an inverse(not a function) to a function by any way?

  • @ComedyGlor
    @ComedyGlor 5 років тому

    so can you not tell without drawing the graph? Say if you only have the equation, would you have to draw the function to know if it has an inverse?

    • @esterhango2104
      @esterhango2104 5 років тому

      No. Just check if that function is injective (one-to-one) . If it is then it does have an inverse😊

    • @ComedyGlor
      @ComedyGlor 5 років тому

      Ester Hango thanks but how do you do that?

    • @esterhango2104
      @esterhango2104 5 років тому

      @@ComedyGlor You can start by letting xx' be the domains of the function. What you do is equate whatever function you got to itself...and then on one side you substitute x the other x' and then you do some mathematical manipulations ... If in the end you have x=x' then that function is injective and have an inverse
      I hope am clear tho. Otherwise just watch a UA-cam vid on injectivity.

    • @ComedyGlor
      @ComedyGlor 5 років тому +1

      Ester Hango ah okay thanks very much dearie

  • @مريممجدي-ص8ح
    @مريممجدي-ص8ح 4 роки тому

    which grade?

  • @juol2702
    @juol2702 4 роки тому

    HAHA woah it is cool seeing you biting the cap of the marker HAHAHA

  • @fr0iler578
    @fr0iler578 8 років тому

    Thanks!😂😂

  • @madelinerevere3584
    @madelinerevere3584 6 років тому

    I finally understand

  • @alexrode7858
    @alexrode7858 2 роки тому

    the speed of your dotted lines tho

  • @鸡腿塞牙
    @鸡腿塞牙 Рік тому

    5:58 / 7:31

  • @isaacgart7466
    @isaacgart7466 6 років тому +1

    beast

  • @lizhao810
    @lizhao810 8 років тому

    did you say.first function has no inverse?

    • @brianmclogan
      @brianmclogan  8 років тому +1

      it has an inverse, but the inverse is not a function

    • @adebayosodiq5344
      @adebayosodiq5344 7 років тому

      because it failed horizontal line test

  • @TheTurbanatore
    @TheTurbanatore 6 років тому +2

    thanks!