great! my lecturer would only explain it on the powerpoint slide and its hard to get you know. its math you have to show the workflow like you did! thanks!
John Martinez It's the inverse rule. He took the inverse of (-1/y) which is basically (1/-1/y) which you just swap the top and bottom and that becomes just -y then he had a do the exact same thing to the other side and multiply both sides my negative one to have it y= instead of -y=
Basically, if you have something on the denominator on one side and move it to the other side it will be in the numerator position. That leaves you with 1/y is equal to whatever. Because we want you to be the subject and not 1/y, you reciprocate both sides.
for a question on my homework it asks on which interval is the solution defined. My professor said it is the largest interval that contains the initial value on which the solution is continuous. ANd the he showed me an example that didn't make sense: 1/(x-3)^2, y(0)=5 is (-infty, 3), but 1/(x-3)^2, y(4)=2 is (3,infty). I don't understand. Can you show me how to find the interval on the example of this video? Or the example my professor gave me. Please help I'm screwed otherwise.
dy/y^2 can be rewritten as (1/y^2)dy and then as y^-2*dy. So integrate y^-2*dy and you have -y^-1 or -1/y
Thank you u r legend mate
Yes
You are correct
Thank you so much
great! my lecturer would only explain it on the powerpoint slide and its hard to get you know. its math you have to show the workflow like you did! thanks!
Great! Best of luck with the AP exam. The phrasing of these questions can vary a bit as it depends on an author's writing style.
This video alone made me understand IVP's. Thank you so much.
Dr. Chris T, you are another professor for all students. 👍
Finally! someone can explain it simple enough for me to understand
THANK YOU, you saved me one day before my calc test!!
saved me two hours before mine! i know to start study earlier next time..
It's like watching Doctor Who, but the Doctor actually takes the time to explain things in a meaningful and helpful way. Thank you!
That is the worst capital E I have ever seen in my life.
I was looking without a sound and was thinking "what the heck is ODK?"
Thank goodness. It's your life.
I understood it pretty well.
Its like an E fucked a K and thats the abomination that came out. lol
@@chrisgraham5963 Hahahhahaha that's so true
how about that x
Dude, I've been trying to figure out how to solve IVPs for a couple weeks and in four minutes everything made sense. H O W
Best maths talent Chris Tisdell!!
Could you please put the time in the video that you are referring to?
What is the 'ODE' (I think that's what you said) at 0:10? I haven't heard that term before.
Ordinary Differential Equation
I solved that question myself
I searched cause I didn't understood the concept but you taught so well
why do you only get a +C on one side if you intergrate both??
3 minute video that's equivalent to at least 2 lectures.
how did you go from 2:00 - 2:25? I'm confused.
John Martinez It's the inverse rule. He took the inverse of (-1/y) which is basically (1/-1/y) which you just swap the top and bottom and that becomes just -y then he had a do the exact same thing to the other side and multiply both sides my negative one to have it y= instead of -y=
+John Martinez
All he did was multiply "y" to both sides and then divided (x+(1/3)x^3+c) on both sides.
Basically, if you have something on the denominator on one side and move it to the other side it will be in the numerator position. That leaves you with 1/y is equal to whatever. Because we want you to be the subject and not 1/y, you reciprocate both sides.
This guy has balls.
How did dh/y2 turn to -1/y
Thank you so much.
can i knw where is the y sqrt 2 goes???
thank you very much. It is very useful for me.
Hi - I can't understand your question. Could you rephrase it please?
this video is the best
for a question on my homework it asks on which interval is the solution defined. My professor said it is the largest interval that contains the initial value on which the solution is continuous. ANd the he showed me an example that didn't make sense: 1/(x-3)^2, y(0)=5 is (-infty, 3), but 1/(x-3)^2, y(4)=2 is (3,infty). I don't understand. Can you show me how to find the interval on the example of this video? Or the example my professor gave me. Please help I'm screwed otherwise.
The ivp dy/dx=3y^(2/3) ,y(0)=0
Does the ivp has two solutions or infinitely many solutions?
Please reply
Thank you so much sir!
Thanks. Understand it completely.
Talos bless you kind sir.
you absolute mad lad
how does the square root of Y become Y???
I wish u were my diff prof
Thank you!
beton yetmez abi
what is ODk?
It’s ode ordinary differential equation
Just here to learn what "Solve for IVP mean" because my professor didn't explain what it means. It just means solve for c
wow great stuff thank you
Helped me solve a problem that had two variable! Thanks
Kindly solve this one--- y''-2y'+y=0 , y(0)=0, y'(0)=1
Great! Thanks!
Cx
1.17 to 1.56
Thanks sir
Thanks
Who wants to do my homework for some money!!!
me...hahaha..loss of money
beautiful
You really couldn't get the entire page in the screen. You had one job.
It's a balance between size of font and amount of text on the screen. If the font is too small then it's impossible to read on mobile devices.
Thank you so much.