Solve the MIND-BOGGLING Math Olympiad Problem: m^6-m^3=2?

[@maths01n]

Liked and learnt alot keep up

[@MathswithChinwendu]

Thank you so much sir

[@dillonlabonte9685]

When m^3 = 2, take the cube root. So m = cube root 2 or 2^(1/3). Similarly, when m^3 = -1, take the cube root and m = -1

[@MathswithChinwendu]

Thank you so much sir

[@AuthenticArnav]

Let m cube be a so the equation becomes a^2 - a - 2 = 0
=> a^2 - 2a + a -2 = 0
=> a(a-2) + (a-2) = 0
=> (a+1)(a-2) = 0
=> a = -1 or a = 2
hence, a = m cube = -1 or 2
m = -1 or cube root 2
Ezy

[@MathswithChinwendu]

Thank you so much for sharing this