Sir, I have a situation: first layer is a clay with thickness H1 and coefficient of consolidation Cv1, the second layer is also a clay layer with thickness H2 and coefficient of consolidation Cv2, the third layer is a sand layer with thickness H3, the fourth layer is again a clay layer with thickness H4 and coefficient of consolidation Cv4. How can I apply Terzaghi's solution t = Tv/Cv*hd^2 for such situation?
Say, there are four layers below a square footing. Up to the depth of footing the soil is clay. First layer: clay soil, thickness H1, coefficient of consolidation: Cv1 Second layer: clay soil, thickness H2, coefficient of consolidation: Cv2 Third layer: sandy soil Fourth layer: clay soil, thickness H4, coefficient of consolidation: Cv4 The fourth layer is followed by impermeable rock. How would you apply Terzaghi's classical formula , t = Tv/Cv*hd^2 to this problem? (hd = drainage path) To be more specific, how can we calculate time required for 50% consolidation of entire soil system? What will be the values of Cv and hd for the first layer?
Hi. I think Hdr for the first layer has to be Hdr = Ht, because we can consider that the second layer is "impermeable" (to simplify) and first layer is single-drained. Another way to do it is consider Hdr = H1+H2 for the first layer, and find a way to get an "average" for Cv1 and Cv2 to use it for Tv equation for the first layer. That's only my opinion. For second and fourth layer we can consider only single-drained system, so Hdr = Ht. I hope you get the answer soon. That's an interesting question.
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Sir, I have a situation: first layer is a clay with thickness H1 and coefficient of consolidation Cv1, the second layer is also a clay layer with thickness H2 and coefficient of consolidation Cv2, the third layer is a sand layer with thickness H3, the fourth layer is again a clay layer with thickness H4 and coefficient of consolidation Cv4. How can I apply Terzaghi's solution t = Tv/Cv*hd^2 for such situation?
Say, there are four layers below a square footing. Up to the depth of footing the soil is clay.
First layer: clay soil, thickness H1, coefficient of consolidation: Cv1
Second layer: clay soil, thickness H2, coefficient of consolidation: Cv2
Third layer: sandy soil
Fourth layer: clay soil, thickness H4, coefficient of consolidation: Cv4
The fourth layer is followed by impermeable rock.
How would you apply Terzaghi's classical formula , t = Tv/Cv*hd^2 to this problem? (hd = drainage path)
To be more specific, how can we calculate time required for 50%
consolidation of entire soil system? What will be the values of Cv and
hd for the first layer?
Hi. I think Hdr for the first layer has to be Hdr = Ht, because we can consider that the second layer is "impermeable" (to simplify) and first layer is single-drained. Another way to do it is consider Hdr = H1+H2 for the first layer, and find a way to get an "average" for Cv1 and Cv2 to use it for Tv equation for the first layer. That's only my opinion.
For second and fourth layer we can consider only single-drained system, so Hdr = Ht.
I hope you get the answer soon. That's an interesting question.
Sir, at 14:56, you are showing the area covered with a green mark on left of u(z) line, won't that area be right of u(z) line?
u Are sooooo great thankkkkk you hope to make more lessons (postgraduate student in National technical University of Athens )
Hi
Is there no Lecture 16?
100% amazing teaching thank you .....
kralsın
Where is lecture 16 ??
SIr, how OC soil can have a higher value of k than NC soil?
if you check the consolidation curve, OC part has larger void ratio than NC part
Lecture 16 and 22 Please?
lecture 16 and 22 please sir