Wow! Thank you so much!! I have been struggling so much until I found your lectures. I really appreciate your efforts to make these complex concepts accessible to students from different backgrounds, learning pace and and learning style. Thank you!!
Thank you so much sir!! I couldn't grasp the concepts and had literally lost complete interest in soil mechanics course of my curriculum. But your videos have been extremely helpful . Thanks a lot sir!!!
Dear Professor, Thanks for your great effort. I have mailed to you extending my greetings. I think you are so busy to answer. Anyway, I wish you will continue your great work to enrich our knowledge with your lectures.
Do you by any chance have a foundation design or earth structures lecture videos. I am studying for the FE and was looking for material. Your lecture videos are great and detailed.
Greetings from Brazil. Thanks for sharing your extraordinary lectures, dr. Franke. About the DSS test, why it cant be used for fiding undrained strengh? I would like to know a little bit more about the limitations of DSS test.
The direct shear device (DS) does not have a membrane surrounding the soil, and therefore cannot be used to perform undrained tests. On the other hand, the direct simple shear device (DSS) DOES have a membrane and is capable of performing undrained tests. Perhaps you mistook my refence to the DS test as the DSS test.
Hi prof, im really into geotechnics but it's quite hard to really understand the concentps.Could you be more specific about the symmetrie of mohr-coulomb criteria,the symmetrie means that the element fails at to planes? one above and one below? or at one only and the direction is govern by the nature of the element?
By definition, a circle is symmetric. Mohr's circles are symmetric about their center. For simple loading assumptions, the stresses that define the circle are symmetric on both sides of the sigma axis (i.e., the x-axis). In advanced soil mechanics, you will learn that the failure envelope is also "sort-of" symmetric about the sigma axis, meaning that there is a failure envelope on the negative side of the sigma axis that represents the failure state for tension. It has a different friction angle than the failure envelope for compression though, so it's not really symmetric.
@@officehours4028 but even if sample get failed at a displacement of 0.5 cm..then reduction in area is 3 sq.cm. if we are using 6 cm * 6 cm box..i think which is considerable..but yeah..considering full area will give us conservative results..lower tau and lower phi..👍..thank you.😊
Hands down best Geotech lecturer on YT😎.....THANK YOU
Wow! Thank you so much!! I have been struggling so much until I found your lectures. I really appreciate your efforts to make these complex concepts accessible to students from different backgrounds, learning pace and and learning style. Thank you!!
You're very welcome!
Great presentation indeed, love your diction and rhythm while presenting!
Thank you so much for posting your excellent lectures on UA-cam. Regards from Saudi Arabai.
Excellent Teacher!!!!
Cant pity myself enough. I just found out this lecture in a few days to graduate.
The way you explain the concepts is outstanding, sir. thanks a lot regards form INDIA
You're the man, thanks from Canada :)
excellent sir ,plz complete the whole course your lectures are very amazing
Thank you so much Dr. Franke. The lecture is very clear. I am writing from Peru
Creí que era el único peruano viéndolo
Thank you so much sir!! I couldn't grasp the concepts and had literally lost complete interest in soil mechanics course of my curriculum. But your videos have been extremely helpful . Thanks a lot sir!!!
Thank you so much, that's a lot of valuable knowledge
Amazing! God bless you!
Fantastic lectures!!!
Great presentation. Thank you professor Franke!
Awesome and interesting!
Dear Professor, Thanks for your great effort.
I have mailed to you extending my greetings.
I think you are so busy to answer.
Anyway, I wish you will continue your great work to enrich our knowledge with your lectures.
Fantastic lecture! Thank you Dr Franke!!
Good Job
Do you by any chance have a foundation design or earth structures lecture videos. I am studying for the FE and was looking for material. Your lecture videos are great and detailed.
thank you professor for the lectures.
Greetings from Brazil.
Thanks for sharing your extraordinary lectures, dr. Franke.
About the DSS test, why it cant be used for fiding undrained strengh?
I would like to know a little bit more about the limitations of DSS test.
The direct shear device (DS) does not have a membrane surrounding the soil, and therefore cannot be used to perform undrained tests. On the other hand, the direct simple shear device (DSS) DOES have a membrane and is capable of performing undrained tests. Perhaps you mistook my refence to the DS test as the DSS test.
Thanks so much for your great sharing
You are so welcome
❤❤❤❤
Great presentation n explanation sir
Thanks and welcome
Great lecture. Thanks
Thank you for the explanation
great lectures
Glad you like them!
Thank you Sir. 😊
3:00 That house is horrified.
HAHAHA....yes, it is
very good!!!
Hi prof, im really into geotechnics but it's quite hard to really understand the concentps.Could you be more specific about the symmetrie of mohr-coulomb criteria,the symmetrie means that the element fails at to planes? one above and one below? or at one only and the direction is govern by the nature of the element?
By definition, a circle is symmetric. Mohr's circles are symmetric about their center. For simple loading assumptions, the stresses that define the circle are symmetric on both sides of the sigma axis (i.e., the x-axis). In advanced soil mechanics, you will learn that the failure envelope is also "sort-of" symmetric about the sigma axis, meaning that there is a failure envelope on the negative side of the sigma axis that represents the failure state for tension. It has a different friction angle than the failure envelope for compression though, so it's not really symmetric.
Does anyone understand how the angle Professor Franke found on 20:11? I don't understand why.
an external angle at any corner with an extension of a line will be a summation of two other angles of the triangle.
two radius of the circle therefore the triangle has two equal corners (0cr) . then the external angle 180-(180-20cr)
at 43:28, while calculating tau, a contact area between soil decrease. shouldn't we consider?
You could, but the change in area is small enough and its effect is negligible such that most engineers ignore it.
@@officehours4028 but even if sample get failed at a displacement of 0.5 cm..then reduction in area is 3 sq.cm. if we are using 6 cm * 6 cm box..i think which is considerable..but yeah..considering full area will give us conservative results..lower tau and lower phi..👍..thank you.😊